Physics
Physics
1st Edition
Walker
ISBN: 9780133256925
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Page 959: Practice Problems

Exercise 20
Solution 1
Solution 2
Step 1
1 of 2
$textbf{Given:}$

$E_o = 18000$ kWh

$textbf{Find:}$ mass

Using the mass-energy equivalence formula, we can find the mass, $m$ as follows:

$$
begin{align*}
E_o &= mc^2 \
m &= dfrac{E_o}{c^2} \
&= dfrac{(18000 text{ J/s})(1000)(3600 text{ s})}{(3.0 times 10^8 text{m/s})^2} \
&= 7.2 times 10^{-7} text{ kg}
end{align*}
$$

Hence, the mass required to have a rest energy of 18000 kWh is $boxed{7.2 times 10^{-7} text{ kg}}$

Result
2 of 2
m = $7.2 times 10^{-7} text{ kg}$
Step 1
1 of 2
Here we have to use the mass-energy equivalence i.e. to equate

$$
18000text{ kWh} = mc^2,
$$

and this gives

$$
m= frac{18000times 1000times 3600 text{ J}}{9times 10^{16}text{(m/s)}^2} = 7.2times 10^{-7}text{ kg}.
$$

Result
2 of 2
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