– The force acting on a spring $F = 1.2text{ N}$

– The elongation of the spring $x = 6.4text{ cm}$

When a spring is compressed or pulled by a given force $F$ its elongation $x$ is proportional to that force, and the coefficient is called the spring constant.

We will solve the problem by applying Hooke’s Law :

$$
begin{equation*}
F = k , x
end{equation*}
$$

Rearranging for $k$ we have:

$$
begin{equation*}
k = frac{F}{x}
end{equation*}
$$

Plugging in the numbers we get:

$$
begin{align*}
k = frac{1.2text{ N}}{0.064text{ m}} = 18.75 ; frac{text{N}}{text{m}}
end{align*}
$$

– The force acting on a spring $F = 2.3 text{ N}$

– The spring constant of the spring $k = 19 ; frac{text{N}}{text{m}}$

When a spring is compressed or pulled by a given force $F$ its elongation $x$ is proportional to that force, and the coefficient is called the spring constant.

We will solve the problem by applying Hooke’s Law :

$$
begin{equation*}
F = k , x
end{equation*}
$$

Rearranging for $x$ we have:

$$
begin{equation*}
x = frac{F}{k}
end{equation*}
$$

Plugging in the numbers we get:

$$
begin{align*}
x = frac{2.3text{ N}}{19 ; frac{text{N}}{text{m}}} = 12.1text{ cm}
end{align*}
$$