Physics
Physics
1st Edition
Walker
ISBN: 9780133256925
Textbook solutions

All Solutions

Page 603: Practice Problems

Exercise 6
Step 1
1 of 3
If the refractive index of the water was 1.35 instead of 1.33, the shiny object wold have been nearer to the dock.
Step 2
2 of 3
Exercise scan
Result
3 of 3
Nearer, see answer.
Exercise 7
Step 1
1 of 2
$textbf{Given values:}$

$$
begin{align*}
n_1 = n_{air} &= 1 \
theta_1 &= 43 text{textdegree} \
theta_2 &= 27 text{textdegree}
end{align*}
$$

The index of refraction for the benzene at angle $27 text{textdegree}$ with the normal can be calculated by applying Snell’s Law :

$$
begin{align*}
n_1 sin theta_1 &= n_2 sin theta_2 \
n_2 &= dfrac{n_1 sin theta_1}{sin theta_2} \
&= dfrac{1 (sin 43 text{textdegree})}{sin 27 text{textdegree}}
end{align*}
$$

$$
{boxed{n_2 = 1.5022}}
$$

Result
2 of 2
$$
{n_2 = 1.5022}
$$
Exercise 8
Step 1
1 of 2
Exercise scan
Result
2 of 2
59$text{textdegree}$
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