$tt{The mirror equation states: $$frac{1}{f}=frac{1}{d_i}+frac{1}{d_o}$$}$

The mirror is convex $Rightarrow f<0$

The image is in behind the mirror (Virtual image) $Rightarrow d_i<0$

$$
frac{1}{d_o}=frac{1}{f}-frac{1}{d_i}=frac{d_i-f}{d_if}Rightarrow d_o=frac{d_if}{d_i-f}=frac{(-0.0175)(-0.0213)}{-0.0175+0.0213}=boxed{0.1m}
$$

The hight of the image:

$$
frac{h_i}{h_o}=-frac{d_i}{d_o}Rightarrow h_i=-frac{h_od_i}{d_o}=-frac{1.75*(-0.0175)}{0.1}=boxed{0.31m}
$$

$$
d_o=0.1m,h_i=0.31m
$$

$$
tt{ to find the focal legth of the mirror $f$ we use The mirror equation:
$$frac{1}{f}=frac{1}{d_i}+frac{1}{d_o}=frac{d_o+d_i}{d_od_i}Rightarrow f=frac{d_od_i}{d_o+d_i}=frac{1.5*(-0.031)}{1.5-0.031}=boxed{-0.032m}$$}
$$

We already know the image and real object distance from the mirror so we can use the magnification formula:

$$
m=-frac{d_i}{d_o}=-frac{-0.031}{1.5}=boxed{0.02}
$$

$$
f=-0.032m,text{m}=0.02
$$