Physics
Physics
1st Edition
Walker
ISBN: 9780133256925
Textbook solutions

All Solutions

Page 93: Practice Problem

Exercise 42
Step 1
1 of 4
a.) From the properties of position-time relationship graph for constant acceleration we will answer the questions.Initial position of the object is presented by the intercept on the vertical-axis of the position-time curve and is donated by $x_i$. By inspecting the location where all four curves intersects the vertical (position) axis, we can rank the curves in order of initial position, from most negative to most positive:

$$
color{#4257b2} boxed{bf A < D < C < B}
$$

Step 2
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b.) The initial velocity is the slope of the position-time curve. By examining the slope of the curves where they intersect the vertical (position) axis, we rank the curves in order of initial velocity, from most negative to most positive:
$$
color{#4257b2} boxed{bf D < C < B < A}
$$
.
Step 3
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c.) Acceleration on the graph is represented by the sharpness of the curvature of the position-time graph. By examining the sharpness of the curvatures we can rank the curves in order of acceleration, from most negative to most positive:
$$
color{#4257b2} boxed{bf C < B < D < A}
$$
.
Result
4 of 4
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