Physics
Physics
1st Edition
Walker
ISBN: 9780133256925
Textbook solutions

All Solutions

Page 574: Lesson Check

Exercise 11
Step 1
1 of 2
Since the image distance and object distance for a plane mirror are equal. The image will be 1 m behind the mirror.
Result
2 of 2
1 m
Exercise 12
Step 1
1 of 2
If I walk towards the mirror, the object distance will decrease. Hence the image distance will also decrease. So the distance between me and image will also decrease.
Result
2 of 2
Decrease.
Exercise 14
Step 1
1 of 2
I am 2.3 m in front of the mirror. My brother is $(2.3 m)-(1.2 m)=1.1$ m in front of the mirror. So brother’s image will form 1.1 m behind the mirror. Hence the distance between me and my brother image will be

$$
(2.3 m)+(1.1 m)=3.4 m
$$

Result
2 of 2
3.4 m
Exercise 15
Step 1
1 of 2
Maximum distance between the head of the python and tells image should be 9.6 m. So the distance between head of the python and its image is $9.6-4=5.6$ m. Hence the distance of the python’s head from the mirror is

$$
frac{(5.6 m)}{2}=2.8 m
$$

Result
2 of 2
2.8 m
Exercise 16
Step 1
1 of 2
Here the angle of the incoming ray with the mirror surface is $60text{textdegree}$.

So the angle of the reflected ray with the mirror surface is also $60text{textdegree}$.

Now using the law of triangle, we can find out that the angle of the incident ray at the horizontal mirror is $180text{textdegree}-(60text{textdegree}+60text{textdegree})=60text{textdegree}$

Hence the angle of the outgoing ray with the mirror surface is also $60text{textdegree}$.

Result
2 of 2
$$
60text{textdegree}
$$
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