Physics
Physics
1st Edition
Walker
ISBN: 9780133256925
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Page 664: Lesson Check

Exercise 48
Step 1
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The interference pattern formed by a diffraction grating consists of a series of sharp, widely spaced bright or light fringes called principal maxima, separated by relatively dark regions which contain a number of weak secondary maxima.
Result
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The interference pattern formed by a diffraction grating consists of a series of sharp, widely spaced bright or light fringes called principal maxima, separated by relatively dark regions which contain a number of weak secondary maxima.
Exercise 49
Step 1
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A diffraction grating can have many slits. In some cases, a grating can have as many as 40,000 slits or lines as often called per centimeter. A screen with a large number of slits is referred to as a diffraction grating.
Result
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A diffraction grating can have many slits. In some cases, a grating can have as many as 40,000 slits or lines as often called per centimeter. A screen with a large number of slits is referred to as a diffraction grating.
Exercise 50
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Coloration that is produced by the interference of light is referred to as $textbf{iridescence}$. Iridescence is the phenomenon of certain surfaces that appear to gradually change color as the angle of view or the angle of illumination changes.
Result
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Coloration that is produced by the interference of light is referred to as $textbf{iridescence}$. Iridescence is the phenomenon of certain surfaces that appear to gradually change color as the angle of view or the angle of illumination changes.
Exercise 51
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If the slit spacing on a diffraction grating is increased which means a grating with less lines per centimeters, the grating spread the colors of the light through a $textbf{smaller angle}$. This occurs because a small value of slit spacing and a large value of angle, $theta$ , have the same effect as a large slit spacing and a small angle.
Result
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If the slit spacing on a diffraction grating is increased which means a grating with less lines per centimeters, the grating spread the colors of the light through a $textbf{smaller angle}$.
Exercise 52
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If the wavelength is increased in a diffraction grating, the angle to the first principal maximum will also $textbf{increase}$. From the constructive interference by a diffraction grating expression, the wavelength is directly proportional to the angle.
Result
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If the wavelength is increased in a diffraction grating, the angle to the first principal maximum will also $textbf{increase}$. From the constructive interference by a diffraction grating expression, the wavelength is directly proportional to the angle.
Exercise 53
Step 1
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$textbf{Given values:}$

$$
begin{align*}
m &= 1 \
theta &= 1.25 text{textdegree} \
lambda &= 587.5 text{ nm}
end{align*}
$$

The split spacing for the diffraction grating to the first order principal maximum of the yellow light from a helium discharge tube can be obtain by applying the expression for constructive interference by a diffraction grating :

$$
begin{align*}
d sin theta &= m lambda \
d &= dfrac{m lambda}{sin theta} \
&= dfrac{1 (587.5 cdot 10^{-9} text{ m})}{sin 1.25 text{textdegree}}
end{align*}
$$

$$
{boxed{d = 26.93 ~ mu text{m}}}
$$

Result
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$$
{d = 26.93 ~ mu text{m}}
$$
Exercise 54
Step 1
1 of 2
$textbf{Given values:}$

$$
begin{align*}
m &= 2 \
d &= 1.92 cdot 10^{-6} text{ m} \
lambda &= 692 text{ nm}
end{align*}
$$

The angle to the second order principal maximum of a light on a diffraction grating can be obtain by applying the expression for constructive interference by a diffraction grating :

$$
begin{align*}
d sin theta &= m lambda \
sin theta &= dfrac{m lambda}{d} \
theta &= {sin}^{-1} left( dfrac{m lambda}{d} right) \
&= {sin}^{-1} left( dfrac{2 (692 cdot 10^{-9} text{ m})}{1.92 cdot 10^{-6} text{ m}} right)
end{align*}
$$

$$
{boxed{theta = 46.12 text{textdegree}}}
$$

Result
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$$
{theta = 46.12 text{textdegree}}
$$
Exercise 55
Step 1
1 of 2
$textbf{Given values:}$

$$
begin{align*}
m &= 1 \
d &= 2.2 ~ mu text{m} \
theta &= 21 text{textdegree}
end{align*}
$$

The wavelength of the light that shines on a diffraction grating through an angle to the first order principal maximum can be obtain by applying the expression for constructive interference by a diffraction grating :

$$
begin{align*}
d sin theta &= m lambda \
lambda &= dfrac{d sin theta}{m} \
&= dfrac{2.2 cdot 10^{-6} text{ m} (sin 21 text{textdegree})}{1}
end{align*}
$$

$$
{boxed{lambda = 788.41 text{ nm}}}
$$

Result
2 of 2
$$
{lambda = 788.41 text{ nm}}
$$
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