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Page 854: Practice Problems

Exercise 1

Solution 1

Solution 2

Step 1

1 of 2

$textbf{Given: }$

$T = 2500$ K

$textbf{Find: } f_{peak}$

To calculate $f_{peak}$, we use Wien’s displacement law as follows:

$$
begin{align*}
f_{peak} &= (5.88 times 10^{10} text{ Hz/K}) times T \
&= (5.88 times 10^{10} text{ Hz/K}) times (2500 text{ K}) \
&= boxed{14.7 times 10^{13} text{ Hz}}
end{align*}
$$

Result

2 of 2

$$
f_{peak} =14.7 times 10^{13} text{ Hz}
$$

Step 1

1 of 2

Using Wien’s law we have
$$
nu_{peak} = 5.88times 10^{10}text{ Hz/K}times 2500text{ K} = 14.7times 10^{ 13}text{ Hz}.
$$

Result

2 of 2

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Exercise 2

Step 1

1 of 2

The higher the temperature, the higher the peak frequency of radiation which dominantly determines the color of the star. Since blue color has higher frequency than red color we conclude that Rigel has greater surface temperature.

Result

2 of 2

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Page 854: Practice Problems

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