All Solutions

Exercise 27

Step 1

1 of 2

The relation between rms current value to a max current value is:

$$
begin{align*}
I_{max}&=sqrt{2}cdot{I_{rms}}
end{align*}
$$

So, if we express $I_{rms}$ from this equation, we get:

$$
begin{align*}
I_{rms}&=frac{1}{sqrt{2}}cdot{I_{max}}
end{align*}
$$

Let’s substitute and compute the value:

$$
begin{align*}
I_{rms}&=frac{1}{sqrt{2}}cdot{2.7text{ A}}
end{align*}
$$

$$
boxed{I_{rms}=1.91text{ A}}
$$

Result

2 of 2

$$
I_{rms}=1.91text{ A}
$$

Exercise 28

Step 1

1 of 2

The relation between rms current value and a max current value is:

$$
begin{align*}
I_{max}&=sqrt{2}cdot{I_{rms}}
end{align*}
$$

Let’s substitute and compute the value:

$$
begin{align*}
I_{max}&=sqrt{2}cdot{1.6text{ A}}
end{align*}
$$

$$
boxed{I_{max}=2.26text{ A}}
$$

Result

2 of 2

$$
I_{max}=2.26text{ A}
$$

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