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Page 608: Practice Problems

Exercise 17

Step 1

1 of 2

The refractive index is greater than than 1.5 since this glass obviously refracts more. Let us calculate this. We know that

$$
40^circ = arcsinleft(frac{1}{n_{glass}}right)Rightarrowfrac{1}{n_{glass}}=sin40^circrightarrow n=frac{1}{sin40^circ} =1.55.
$$

Result

2 of 2

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Exercise 18

Step 1

1 of 3

Total internal reflection occur when light travels from optically denser to lighter medium.
Refractive index of air is less than, water, so light travelling from water to air will have total internal reflection.

Step 2

2 of 3

Again since the refractive index of water is greater than ice. Hence light travelling from water to ice will have total internal reflection.

Result

3 of 3

Case A: Light travels from water into air.
Case C: Light travels from water into ice.

Exercise 19

Step 1

1 of 2

From the formula for critical angle we have

$$
46.5^circ = arcsinleft(frac{n_{air}}{n_{material}}right) = arcsinleft(frac{1}{n_{material}}right).
$$
Taking sine from both sides we get

$$
sin{46.5^circ}=frac{1}{n_{material}}Rightarrow n_{material} =frac{1}{sin46.5^circ} =1.38.
$$

Result

2 of 2

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