The angle of the outgoing ray makes with horizontal depends only on the angle $theta$, not where the ray hits the mirror. So the angle of the outgoing ray with horizontal will be $30text{textdegree}$.

Equal to $30text{textdegree}$

$$
tt{the angle of incidence with the vertical mirror is $90-theta$ as indicated in {color{#4257b2}{Example 16.4}}, in this example $theta=90-25=65^o$,\ therefore $90-theta=boxed{25^o}$}
$$

$$
25^o
$$