Home Page Textbooks Physics Page 544: Lesson Check

Physics

1st Edition

Walker

ISBN: 9780133256925

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Page 544: Lesson Check

Exercise 18

Step 1

1 of 2

$$
tt{An electron produces an electric field at all times when it starts oscillating the electric field will follow and produces a wave, this motion at the same time produces a wavy magnetic field, the two fields perpendicular to each other form the electromagnetic wave}
$$

Result

2 of 2

$$
tt{electrons}
$$

Exercise 19

Step 1

1 of 2

Ultraviolet wave has higher frequency than infrared, hence ultraviolet has smaller wavelength.

Result

2 of 2

Ultraviolet.

Exercise 20

Step 1

1 of 2

When red and blue light are mixed we will see magenta color.

Result

2 of 2

Magenta.

Exercise 21

Step 1

1 of 2

Cyan subtractive primary color corresponds to the combination of green and blue additive primary color.

Result

2 of 2

Cyan

Exercise 22

Step 1

1 of 4

We recall that when red, green, and blue light are added together, white light is produced. One third of the screen is red, one third white, and one third green.

Step 2

2 of 4

Red color dots are required for the red and white areas of the screen. So the number of red colors that are lit must be $text{textcolor{#c34632}{2,000,000}}$.

Step 3

3 of 4

Green color dots are required for the green and white areas of the screen. So the number of green colors that are lit must be $text{textcolor{#19804f}{2,000,000}}$.

Step 4

4 of 4

Blue color dots are only required for the white area of the screen. So the number of blue colors that are lit must be $text{textcolor{#4257b2}{1,000,000}}$.

Exercise 23

Step 1

1 of 1

The electromagnetic spectrum is classified into regions with increasing order of wavelength and each ranges of wavelengths correspond to a certain shade of color. The visible light is the part of the spectrum in which human eye is the most sensitive to and it has a frequency range of $4.3times 10^{14}$ Hz to $7.5times 10^{14}$ Hz. $textbf{Below the frequency of visible light is the infrared (IR) waves}$ which has a frequency that ranges from $10^{12}$ Hz to $4.3times 10^{14}$ Hz. $textbf{Above the frequency of visible light is the ultraviolet light}$ which has a frequency that ranges from $7.5times 10^{14}$ Hz to $10^{17}$ Hz. Finally, $textbf{the highest-frequency part of the EM spectrum is the gamma rays}$. It is highly energic rays which can be destructive to living cells.

Exercise 24

Step 1

1 of 3

Known:

$$
lambda=460 {rm nm=460times10^{-9} m}
$$

Unknown:

$$
f=?
$$

Solution:

$$
f=frac{c}{lambda}=frac{left(3times10^{8} {rm m/s}right)}{left(460times10^{-9} {rm m}right)}=6.52times10^{14} {rm Hz}
$$

Step 2

2 of 3

Period $T$ is

$$
T=frac{1}{f}=frac{1}{left(6.52times10^{14} {rm Hz}right)}=1.53times10^{-15} {rm s}
$$

Result

3 of 3

$6.52times10^{14} {rm Hz}$, $1.53times10^{-15} {rm s}$

Exercise 25

Step 1

1 of 2

Known:

$$
f=1.25times10^{9} {rm Hz}
$$

Unknown:

$$
lambda=?
$$

Solution:

$$
lambda=frac{c}{f}=frac{left(3times10^{8} {rm m/s}right)}{left(1.25times10^{9} {rm Hz}right)}=0.24 {rm m}
$$

Result

2 of 2

0.24 m

Exercise 26

Step 1

1 of 3

Known:

$$
lambda=9.0times10^{-6} {rm m}
$$

Unknown:

$$
f=?
$$

Solution

$$
f=frac{c}{lambda}=frac{left(3times10^{8} {rm m/s}right)}{left(9.0times10^{-6} {rm m}right)}=3.3times10^{13} {rm Hz}
$$

Step 2

2 of 3

This wave belongs to the infrared portion of the electromagnetic wave.

Result

3 of 3

(a) $3.3times10^{13} {rm Hz}$

(b) Infrared

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