
Physics
1st Edition
ISBN: 9780133256925
Table of contents
Textbook solutions
All Solutions
Page 530: Practice Problems
Exercise 1
Step 1
1 of 4
Speed is calculated as the ratio between the distance travelled and the time it takes to travel the distance,
$$
begin{align}
v = frac{d}{t}
end{align}
$$
Step 2
2 of 4
We rearrange Equation 1 such that the distance $d$ is isolated on one side of the equation.
$$
begin{align*}
d = vt
end{align*}
$$
Step 3
3 of 4
We convert the time in seconds using the conversion $1;text{min} = 60;text{s}$. Using $v = c$ for the speed, the distance of Mars from Earth is
$$
begin{align*}
d &= ct \ &= left(3.0times 10^{8};frac{text{m}}{text{s}}right)(12;text{min}) left(frac{60;text{s}}{1;text{min}}right) \ &= boxed{2.2times 10^{11};text{m}}
end{align*}
$$
Result
4 of 4
$d = 2.16times 10^{11}$ m
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