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Physics

1st Edition

Walker

ISBN: 9780133256925

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Page 512: Lesson Check

Exercise 41

Step 1

1 of 2

When the source moves toward on observer which is not moving, the frequency that is observed would be higher than that of the source. Therefore, the horn must moving toward you.

Result

2 of 2

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Exercise 42

Step 1

1 of 2

Due to Doppler effect, an observing that is moving towards the source would observe a higher frequency. A lower frequency is observed when moving away from the source. As a result, if you move away from a stationary source, the observed frequency would be less than that of the source.

Result

2 of 2

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Exercise 43

Step 1

1 of 2

When the source moves toward a stationary source, the frequency that is heard is higher than that of the source. Hence, it is safe to say that if a bird sings a 220-Hz note while flying towards you, your observed frequency would be greater than 220 Hz.

Result

2 of 2

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Exercise 44

Step 1

1 of 3

The general formula for Doppler effect problems is

$f_{listener}=f_{source}dfrac{v_{sound}pm v_{listener}}{v_{sound}pm v_{source}}$

The rules are:

If the listener is travelling towards the source, the sign of $v_{listener}$ is positive. If it’s moving away, then it is negative.

Furthermore, if the source is moving towards from the listener, the sign of $v_{source}$ is negative. If the source is moving away from the listener, it is positive.

Step 2

2 of 3

The sign of the $v_{source}$ is negative since it is moving towards the observer.

Plug-in the given values,

$389=381left(dfrac{343}{343-v_{source}}right)$

Solve for $v_{source}$

$$
v_{source}=7.05;m/s
$$

Result

3 of 3

$$
v_{source}=7.05;m/s
$$

Exercise 45

Step 1

1 of 3

The general formula for Doppler effect problems is

$f_{listener}=f_{source}dfrac{v_{sound}pm v_{listener}}{v_{sound}pm v_{source}}$

The rules are:

If the listener is travelling towards the source, the sign of $v_{listener}$ is positive. If it’s moving away, then it is negative.

Furthermore, if the source is moving towards from the listener, the sign of $v_{source}$ is negative. If the source is moving away from the listener, it is positive.

Step 2

2 of 3

Use the Doppler effect equation.

The sign of $v_{source}$ is negative since it is moving toward the observer.

Plug-in the given values and solve for $f_{listener}$

$$
f_{listener}=28,000left(dfrac{343}{343-12}right)=29015;Hzapprox 29kHz
$$

Result

3 of 3

$$
29;kHz
$$

Exercise 46

Step 1

1 of 3

The general formula for Doppler effect problems is

$f_{listener}=f_{source}dfrac{v_{sound}pm v_{listener}}{v_{sound}pm v_{source}}$

The rules are:

If the listener is travelling towards the source, the sign of $v_{listener}$ is positive. If it’s moving away, then it is negative.

Furthermore, if the source is moving towards from the listener, the sign of $v_{source}$ is negative. If the source is moving away from the listener, it is positive.

Step 2

2 of 3

Use the equation for Doppler effect equation.

Since the source is moving toward the observer, the sign of $v_{source}$ is negative.

Plug-in the given values

$f_{listener}=110dfrac{343}{343-12}=114;Hz$

For the second case, the source is moving away from the observer, hence, the sign of $v_{source}$ is positive.

$$
f_{listener}=220dfrac{343}{343+24}=206;Hz
$$

Result

3 of 3

114 Hz and 206 Hz

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