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Page 47: Practice Problems

Exercise 2

Solution 1

Solution 2

Step 1

1 of 3

To determine the displacement, first we have to identify the initial and final positions.

The initial position is the math classroom, $x_{i}=8 text{m}$, and the final position is the library, $x_{f}=0 text{m}$. Therefore, the displacement is

$$
begin{align*}
Delta x &=x_{f}-x_{i}\
&=0.0 text{m}-8.0 text{m}\
&=quadboxed{-8 text{m}}\
end{align*}
$$

Step 2

2 of 3

The distance for this trip is the sum of all distances traversed: from the math classroom to the music classroom, and then from the music classroom to the library. Thus

$$
begin{align*}
d&=6 text{m}+14 text{m}\
&=quadboxed{20 text{m}}\
end{align*}
$$

Result

3 of 3

Displacement: $boxed{Delta x= -8 text{m}}$

Distance: $boxed{d=20 text{m}}$

Step 1

1 of 2

$$
textbf{Concept:}
$$

Let the initial position at the maths classroom is $x_i=8.0m$ and the final position at the library be $x_f=0m$. The distance travelled is the sum total of the distances travelled on the individual legs of the journey.

$$
textbf{Solution:}
$$

$$
Delta x = x_f-x_i = 0.0 – 8.0 m = color{#4257b2} boxed{bf -8.0m}
$$

Now find the distance travelled

Distance = 6.0 m + 14 m = $text{color{#4257b2} boxed{bf 20m}}$

Result

2 of 2

$$
20m
$$

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Page 47: Practice Problems

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