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Physics

1st Edition

Walker

ISBN: 9780133256925

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Page 400: Lesson Check

Exercise 23

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a) This is not true. Revision than makes it true is “The work done in a constant-volume process is zero.”

b) This is not true. Revision that would make it true is “The work done in a constant pressure process is equal to the product of that pressure and the change in volume.”

c) This is true.

d) This is true.

e) This is true.

Result

2 of 2

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Exercise 24

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It is possible for energy to flow into a system with fixed temperature in the form of heat, if that heat is fully transformed into work. Hence the change in internal energy of the system would remain zero, as expected for an isothermal process.

A good example of this is a weatherglass.. The expansion or contraction of the air inside the glass is an isothermal process, while heat is obviously exchanged with the surroundings.

Result

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It is possible for thermal energy to flow into the system if it is converted to heat only. A good example is weatherglass.

Exercise 25

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Using the 1st law of thermodynamics and the fact that $Q$ here is zero we easily conclude that the work done in adiabatic process is always negative change in the thermal energy $W=-Delta E$.

Result

2 of 2

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Exercise 26

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From the 1st law of thermodynamics and the fact that $Q=0$ we easily conclude that $Delta E = -50text{ J}.$

Result

2 of 2

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Exercise 27

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We start from the 1st law of thermodynamics
$$
Q=W+Delta E.
$$
Since in isothermal process there is no change in thermal energy we see that

$$
Q=W=10text{ J}.
$$

Result

2 of 2

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Exercise 28

Step 1

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There is no work done in constant volume process so the answer is
$$
W=0.
$$

Result

2 of 2

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Exercise 29

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In isobaric process the work done is

$$
W=p(2V-V)=pV
$$
which yields

$$
V=frac{W}{p} =1.16text{ dm}^3.
$$

Result

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Exercise 30

Step 1

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In the isobaric pressure work done is given by

$$
W=pDelta V = p(frac{V}{2} – V) = -pfrac{V}{2}.
$$
This yields

$$
V = -frac{2W}{p} =13.17text{ dm}^3.
$$

Note that the work done by the internal forces in the gas is negative.

Result

2 of 2

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