
Physics
1st Edition
ISBN: 9780133256925
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Textbook solutions
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Page 394: Practice Problems
Exercise 17
Step 1
1 of 2
We know that the work is calculated using
$$
W=pDelta V=p(V_2-V_1)
$$
which yields
$$
p=frac{W}{V_2-V_1} =60text{Pa}.
$$
Result
2 of 2
Click here for the solution.
Exercise 18
Step 1
1 of 2
We know that the work is calculated using
$$
W=pDelta V
$$
and this gives
$$
Delta V = frac{W}{p} =0.13text{ m}^3.
$$
Result
2 of 2
Click here for the solution.
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