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Exercise 17

Step 1

1 of 2

We know that the work is calculated using

$$
W=pDelta V=p(V_2-V_1)
$$
which yields

$$
p=frac{W}{V_2-V_1} =60text{Pa}.
$$

Result

2 of 2

Click here for the solution.

Exercise 18

Step 1

1 of 2

We know that the work is calculated using

$$
W=pDelta V
$$
and this gives

$$
Delta V = frac{W}{p} =0.13text{ m}^3.
$$

Result

2 of 2

Click here for the solution.

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