All Solutions

Exercise 46

Solution 1

Solution 2

Step 1

1 of 2

Known

$L_{v}=22.6times10^{5}$ J/kg

$m=1.26$ kg

Unknown

$$
Q=?
$$

Solution:

$$
Q=mL_{v}=left(22.6times10^{5} {rm J/kg}right)left(1.26 {rm kg}right)=2.84times 10^6 {rm J}
$$

Result

2 of 2

$2.84times 10^6$ J

Step 1

1 of 2

Since we are converting liquid water to gaseous steam, we must use the latent heat of vaporization for water.

The amount of heat needed will be:

$$
Q = mL_v
$$

Where latent heat of vaporization is $L_v = 22.6 cdot 10^5text{ }dfrac{text{J}}{text{kg}}$,

Mass of water is $m = 1.26text{ kg}$, so

$$
begin{align*}
Q &= 1.26 cdot 22.6 cdot 10^5\
\
Q &= boxed{28.476 cdot 10^5text{ J}}\
end{align*}
$$

Result

2 of 2

$$
Q = 28.476 cdot 10^5text{ J}
$$

unlock