– The mass of the piece of aluminium $m = 111text{ g}$

– The initial temperature $T_i = 22.5text{textdegree}text{C}$

– The energy added $Q = 79.3text{ J}$

Heating the aluminium leads to an increase of its temperature

$$
begin{equation*}
T_f = T_i + Delta T
end{equation*}
$$

Where the change in temperature is found from:

$$
begin{equation*}
c = frac{Q}{m , Delta T}
end{equation*}
$$

rearranging:

$$
begin{equation*}
Delta T = frac{Q}{m , c}
end{equation*}
$$

Where the specific Heat Capacity for aluminium is $C = 900 frac{text{J}}{text{kg}text{textdegree}text{C}}$

Plugging in the values:

$$
begin{align*}
Delta T = frac{79.3text{ J}}{0.111text{ kg} cdot 900 frac{text{J}}{text{kg}text{textdegree}text{C}}} = 0.793text{textdegree}text{C}
end{align*}
$$

So the final temperature is:

$$
begin{align*}
T_f = T_i + Delta T = 22.5text{textdegree}text{C} + 0.793 approx 23.3text{textdegree}text{C}
end{align*}
$$

– The mass of the piece of glass ball $m = 55text{ g}$

– The change of temperature $Delta T = 15text{textdegree}text{C}$

Heating the glass leads to an increase of its temperature where the change in temperature is found from:

$$
begin{equation*}
c = frac{Q}{m , Delta T}
end{equation*}
$$

rearranging:

$$
begin{equation*}
Q = m , c Delta T
end{equation*}
$$

Where the specific Heat Capacity for glass is $c = 837 frac{text{J}}{text{kg}text{textdegree}text{C}}$

Plugging in the values:

$$
begin{align*}
Q &= 0.055text{ kg} cdot 837 frac{text{J}}{text{kg}text{textdegree}text{C}} cdot 15text{textdegree}text{C} \
Q &= 690.5text{ J}
end{align*}
$$