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Physics

1st Edition

Walker

ISBN: 9780133256925

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Page 349: Lesson Check

Exercise 9

Solution 1

Solution 2

Step 1

1 of 1

Average kinetic energy of the particle constituting object increases when the temperature increases.

Step 1

1 of 2

The average kinetic energy of particles in a substance increases when the temperature of the substance is increased because temperature is directly proportional to the average kinetic energy of particles.

Therefore the correct choice is: The average kinetic energy of particles in a substance increases with increase in temperature.

Result

2 of 2

The average kinetic energy of particles in a substance increases with increase in temperature

Exercise 10

Step 1

1 of 2

No, the statement isn’t correct because it is invalid to say a specific object possesses heat. An object can possess thermal energy. The exchange of thermal energy between bodies is called heat.

Result

2 of 2

No, the statement isn’t correct.

Exercise 11

Step 1

1 of 2

The energy transferred between two bodies because of the temperature difference is called $textbf{Heat}$.

Result

2 of 2

It is called Heat.

Exercise 12

Solution 1

Solution 2

Step 1

1 of 2

The total amount of energy in a substance is the sum of all its kinetic energy and potential energy is referred to as thermal energy. Thermal energy is also known as internal energy. Thus an object’s thermal energy refers to both the random motion of its particles (kinetic energy) and the separation and orientation of its particles relative to one another (potential energy).

Result

2 of 2

Thermal energy refers to both Kinetic and Potential Energy

Step 1

1 of 1

The thermal energy of a substance is defined as the total internal energy (that is total kinetic energy and total potential energy) of the particle constituting the substance.

Exercise 13

Solution 1

Solution 2

Step 1

1 of 1

Key characteristic of thermal equilibrium are:

* The temperature will be same
* Net heat or thermal energy flow will be zero.

Step 1

1 of 2

The key characteristics of thermal equilibrium are:\
begin{enumerate}
item A system is said to be in thermal equilibrium when its temperature is constant.\
item There is no net transfer of energy in thermal equilibrium.\
end{enumerate}

Result

2 of 2

Constant temperature and no net transfer

Exercise 14

Step 1

1 of 2

Absolute Zero.

Result

2 of 2

0 degrees kelvin is called Absolute zero.

Exercise 15

Step 1

1 of 2

We have temperature in Fahrenheit $T_f = 4500 text{textdegree} F$ To convert to Celsius we use:

$$
begin{equation*}
T_c = frac{5}{9} cdot left(T_f – 32 right)
end{equation*}
$$

Inserting we have:

$$
begin{align*}
T_c &= frac{5}{9} left(4500 – 32 right) \
T_c &= 2482.2 text{textdegree} C
end{align*}
$$

Result

2 of 2

$$
begin{equation*}
T_c = 2482.2 text{textdegree} C
end{equation*}
$$

Exercise 16

Step 1

1 of 3

a) To convert the temperature from Fahrenheit to Celsius, we use the following formula:

$$
T_C = dfrac{5}{9}left( {T_F – 32} right)
$$

Thus for changes, formula will be

$$
Delta T_C = dfrac{5}{9}(Delta T_F)
$$

Where $T_F = 35text{ }^circ text{F}$

$$
begin{align*}
Delta T_C &= dfrac{5}{9}(Delta T_F)
\
Delta T_C &= dfrac{5}{9}(35)\
\
Delta T_C &= boxed{19.4text{ }^circ text{C}}\
end{align*}
$$

Step 2

2 of 3

b) To convert the temperature from Celsius to Kelvin, we use the following formula:

$$
T = T_C + 273.15
$$

Thus the formula for changes will be

$$
begin{align*}
Delta T &= Delta T_C \
\
T &= boxed{19.4text{ K}}\
end{align*}
$$

Result

3 of 3

$19.4^{circ}text{ C}$

$$
19.4 text{ K}
$$

Exercise 17

Step 1

1 of 2

The change in temperature in Celsius is $20 text{textdegree} C$

Since the following formula holds

$$
begin{equation*}
T_f = frac{9}{5} cdot T_c + 32
end{equation*}
$$

We see that the changes on different units are related as follows:

$$
begin{align*}
Delta T_f &= frac{9}{5} cdot Delta T_c \
Delta T_f &= 52.2 F \
end{align*}
$$

From the formula for Kelvin we get:

$$
begin{align*}
Delta T &= Delta T_c \
Delta T &= 29 K
end{align*}
$$

Result

2 of 2

begin{enumerate}[a)]
item
$Delta T_f = 52.2 F$
item
$Delta T = 29 K$
end{enumerate}

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