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Page 858: Practice Problems

Exercise 6

Solution 1

Solution 2

Step 1

1 of 2

$textbf{Given: }$

$E_{photon} = 2.5 times 10^{-19}$ J

$textbf{Find: }$ frequency of light, $f$

The energy of a photon can be calculated using the formula:

$$
begin{gather}
E = hf
end{gather}
$$

Using Eq (1), we can compute for $f$, such that:

$$
begin{align*}
f &= dfrac{E}{h} \
&= dfrac{2.5 times 10^{-19} text{ J}}{6.626 times 10^{-34} text{ Js}} \
&= boxed{3.8 times 10^{14} text{ Hz}}
end{align*}
$$

Result

2 of 2

$$
3.8 times 10^{14} text{ Hz}
$$

Step 1

1 of 2

The energy of a photon is always given by

$$
E=hnu
$$
yielding for its’ frequency

$$
nu= frac{E}{h} =frac{2.5times10^{-19}text{ J}}{6.62times10^{-34}text{ J s}} = 3.8times 10^{14}text{ Hz}.
$$

Result

2 of 2

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Page 858: Practice Problems

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