Physics
1st Edition
ISBN: 9780133256925
Table of contents
Textbook solutions
All Solutions
Page 503: Practice Problems
Exercise 19
Step 1
1 of 2
The bottle can be modeled as an pipe open at one and end but closed at the other.
Hence, the equation for fundamental frequency (n=1) is
$$
f_1=dfrac{nv}{4L}=dfrac{(1)(343m/s)}{4(0.22;m)}=390;Hz
$$
Result
2 of 2
390 Hz
Exercise 20
Step 1
1 of 2
The bottle can be modeled as a pipe open at one end but closed at the other. Hence, the third harmonic (n=3) can be obtained as
$$
f_3=dfrac{3v}{4L}=dfrac{3(343m/s)}{4(0.18;m)}=1.4;kHz
$$
Result
2 of 2
$$
1.4;kHz
$$
1.4;kHz
$$
Exercise 21
Step 1
1 of 2
For standing waves in a pipe that is closed at one end, the wavelength of the fundamental frequency is $lambda=4L$
Therefore
$$
L=dfrac{lambda}{4}=dfrac{0.88;m}{4}=0.22;m
$$
Result
2 of 2
$$
0.22;m
$$
0.22;m
$$
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