Home Page Textbooks Physics: Principles and Problems Page 786: Practice Problems

Physics: Principles and Problems

9th Edition

Elliott, Haase, Harper, Herzog, Margaret Zorn, Nelson, Schuler, Zitzewitz

ISBN: 9780078458132

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Page 786: Practice Problems

Exercise 22

Step 1

1 of 4

In this problem, we are given a battery that powers a diode with a given voltage in a circuit of known current, and resistance. We should find the battery voltage.

Step 2

2 of 4

The equation that describes this process is Ohm’s law applied on the diode circuit

$$
V_b=IR+V_d
$$

Step 3

3 of 4

center{Now, we can insert the given values to have that}
[V_b=2.5times 10^{-3}times 470 +0.7=boxed{1.9 textrm{ V}}]

Result

4 of 4

$$
V_b=1.9 textrm{ V}
$$

Exercise 23

Step 1

1 of 4

In this problem, we are given a battery that powers two diodes connected in series with a given voltage in a circuit of known current and resistance. We should find the battery voltage.

Step 2

2 of 4

The equation that describes this process is Ohm’s law applied on the diode circuit

$$
V_b=IR+2V_d
$$

Step 3

3 of 4

center{Now, we can insert the given values to have that}
[V_b=2.5times 10^{-3}times 470 +2times 0.7=boxed{2.6 textrm{ V}}]

Result

4 of 4

$$
V_b=2.6 textrm{ V}
$$

Exercise 24

Step 1

1 of 1

The positive end of the first diode when we follow the direction of the current (anode) should be attached to the cathode of the second diode where the anode of the second diode should be facing the positive voltage.

Exercise 26

Step 1

1 of 4

In this problem, we are given a battery that powers a diode with a given voltage in a circuit of known current, and resistance. We should find the battery voltage.

Step 2

2 of 4

The equation that describes this process is Ohm’s law applied on the diode circuit

$$
V_b=IR+V_d
$$

Step 3

3 of 4

center{Now, we can insert the given values to have that}
[V_b=12times 10^{-3}times 470 +0.4=boxed{6.04 textrm{ V}}]

Result

4 of 4

$$
V_b=6.04 textrm{ V}
$$

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