Physics: Principles and Problems
Physics: Principles and Problems
9th Edition
Elliott, Haase, Harper, Herzog, Margaret Zorn, Nelson, Schuler, Zitzewitz
ISBN: 9780078458132
Textbook solutions

All Solutions

Page 684: Practice Problems

Exercise 16
Step 1
1 of 2
In order to solve this problem, we are going to use the transformer equation which is given as
$frac{I_s}{I_p}=frac{V_p}{V_s}=frac{N_p}{N_s}$
Now, we can express the voltage of the secondary circuit

$$
V_s=frac{N_s}{N_p}V_p=frac{125}{7500}times 7200
$$

Which gives that

$$
boxed{V_s=120textrm{ V}}
$$

Now, we can express the current in the primary circuit

$$
I_p=frac{N_s}{N_p}I_s=frac{125}{7500}times 36
$$

$$
boxed{I_p=0.6textrm{ A}}
$$

Result
2 of 2
$$
V_s=120textrm{ V}
$$

$$
I_p=0.6textrm{A}
$$

Exercise 17
Step 1
1 of 2
In order to solve this problem, we are going to use the transformer equation which is given as
$frac{I_s}{I_p}=frac{V_p}{V_s}=frac{N_p}{N_s}$
Now, we can express the voltage of the secondary circuit

$$
V_s=frac{N_s}{N_p}V_p=frac{90000}{300}times 60
$$

Which gives that

$$
boxed{V_s=18times 10^3textrm{ V}}
$$

Now, we can express the current in the primary circuit

$$
I_p=frac{N_s}{N_p}I_s=frac{90000}{300}times 0.5
$$

$$
boxed{I_p=150textrm{ A}}
$$

Result
2 of 2
$$
V_s=18times 10^3textrm{ V}
$$

$$
I_p=150textrm{ A}
$$

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