Advanced Functions 12
Advanced Functions 12
1st Edition
Chris Kirkpatrick, Kristina Farentino, Susanne Trew
ISBN: 9780176678326
Textbook solutions

All Solutions

Section 9-1: Exploring Combinations of Functions

Exercise 1
Step 1
1 of 2
Answers may vary.For example, $textbf{the garph}$ of $y=((dfrac{1}{2})^x)(2x)$ is on the following picture:

Exercise scan

Result
2 of 2
see solution
Exercise 2
Step 1
1 of 7
#### (a)

A function with $textbf{a vertical asymptote}$ and $textbf{a horizontal asymptote}$.If the function $y=2^x$ and $y=2x$ are multiplied, the resulting function will have a vertical asymptote and a horizontal asymptote.For example, it could be a function $y=2^x(2x)$.

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Step 2
2 of 7
#### (b)

A function that is $textbf{even}$:

$y=2x$ is odd,

$y=cos(2pi{x})$ is odd.

$textbf{The product of the two odd functions will be even.}$For example, it could be a function:

$$
y=(2x)cos(2pi{x})
$$

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Step 3
3 of 7
#### (c)

A function that is $textbf{odd}$:

$y=2x$ is odd,

$y=sin(2pi{x})$ is even.

$textbf{The product of the two functions where is one odd and the other one is even is odd.}$For example, it could be a function $y=(2x)sin(2pi{x})$.

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Step 4
4 of 7
#### (d)

A function that is $textbf{periodic}$:

$y=sin(2pi{x})$ is periodic,

$y=cos(2pi{x})$ is periodic.

$textbf{The product of two periodic function is periodic function.}$So, for example, it could be a function $y=sin(2pi{x})cos(2pi{x})$.

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Step 5
5 of 7
#### (e)

A function that resembles $textbf{a periodic function with decreasing maximum values and increasing minimum values:}$

$y=cos(2pi{x})$ is periodic,

$y=(dfrac{1}{2})^x$ is decreasing.

$textbf{The product of those two functions will be a function that resembles a periodic function with decreasing maximum values and increasing minimum values}$.So, it could be a function $y=(dfrac{1}{2})^xcos(2pi{x})$ where $0leq{x}leq2pi$.

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Step 6
6 of 7
#### (f)

A function that resembles $textbf{a periodic function with increasing maximum values and decreasing minimum values}$:

$y=sin(2pi{x})$ is periodic.

$y=2x$ is increasing.

$textbf{The product of those two functions will be a function that resembles a periodic function with increasing maximum values and decreasing minimum values.}$So, it could be a function $y=2xcos(2pi{x})$,

where $0leq{x}leq2pi$.

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Result
7 of 7
see solution
Exercise 3
Step 1
1 of 2
For example,

$y=x^2$

$y=log{x}$.

$textbf{The product}$ will be $y=x^2log{x}$, on the following picture there is its $textbf{graph}$.

Exercise scan

Result
2 of 2
$y=x^2, y=log{x}$
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