Advanced Functions 12
Advanced Functions 12
1st Edition
Chris Kirkpatrick, Kristina Farentino, Susanne Trew
ISBN: 9780176678326
Textbook solutions

All Solutions

Page 161: Practice Questions

Exercise 2
Step 1
1 of 5
Note that each of these examples has many solutions. It is important that the leading term is of the stated degree, while other terms or coefficients are not explicitly given and they can vary.
Step 2
2 of 5
*(a)* Leading term has to be of degree $3$. Since the number of terms is by $1$ greater than the degree of the function, all terms are included. One such example is
$$y=2x^3+3x^2-2x-5.
$$
Note that any other coefficient is allowed.
Step 3
3 of 5
*(b)* Leading term has to be of degree $4$. Note that beside the leading term, this function has to have two more terms. We can choose the term of any degree. One such example is
$$y=5x^4-2x^2-3.
$$
Note that any other coefficient is allowed, as well as the terms with $x^3$ or $x$.
Step 4
4 of 5
*(c)* Leading term has to be of degree $6$. Note that besides the leading term, this function has to have only one more term. We can choose the term of any degree. One such example is
$$y=12x^6-5x.
$$
Note that any other coefficient is allowed, as well as the terms with $x^5$, $x^4$, $x^3$, $x^2$, or constant term.
Step 5
5 of 5
*(d)* Leading term has to be of degree $5$. Note that besides the leading term, this function has to have four more terms. We can choose the terms of any degree. One such example is
$$y=3x^5-x^3+2x^2-7x+4.
$$
Note that any other coefficient is allowed, as well as the terms with $x^4$ instead of the chosen.
Exercise 3
Step 1
1 of 2
State end behavior for the following equations.

$$
color{#4257b2}text{(a)} f(x)=-11x^3+x^2-2
$$

The end behavior is as $(xrightarrowpminfty)$ and $(yrightarrow-infty)$

$$
color{#4257b2}text{(b)} f(x)=70x^2-67
$$

The end behavior is as $(xrightarrowpminfty)$ and $(yrightarrowinfty)$

$$
color{#4257b2}text{(c)} f(x)=x^3-1000
$$

The end behavior is as $(xrightarrow-infty, yrightarrow-infty)$ and $(xrightarrowinfty, yrightarrowinfty)$

$$
color{#4257b2}text{(d)} f(x)=-13x^4-4x^3-2x^2+x+5
$$

The end behavior is as $(xrightarrow-infty, yrightarrowinfty)$ and $(xrightarrowinfty, yrightarrow-infty)$

Result
2 of 2
$$
text{color{Brown}(a) The end behavior is as $(xrightarrowpminfty)$ and $(yrightarrow-infty)$
\ \
(b) The end behavior is as $(xrightarrowpminfty)$ and $(yrightarrowinfty)$
\ \
(c) The end behavior is as $(xrightarrow-infty, yrightarrow-infty)$ and $(xrightarrowinfty, yrightarrowinfty)$
\ \
(d) The end behavior is as $(xrightarrow-infty, yrightarrowinfty)$ and $(xrightarrowinfty, yrightarrow-infty)$}
$$
Exercise 4
Step 1
1 of 2
State the following expression that has an even turning point or an odd turning point.

$$
color{#4257b2}text{(a)} f(x)=6x^3+2x
$$

The turning point is most $n-1$ as follows:

$$
n=3 n-1=3-1=2 text{Even number}
$$

This equation may have zero or two turning point.

$$
color{#4257b2}text{(b)} f(x)=-20x^6-5x^3+x^2-17
$$

The turning point is most $n-1$ as follows:

$$
n=6 n-1=6-1=5 text{Odd number}
$$

This equation may have one or three or five turning point.

$$
color{#4257b2}text{(c)} f(x)=22x^4-4x^3+3x^2-2x+2
$$

The turning point is most $n-1$ as follows:

$$
n=4 n-1=4-1=3 text{Odd number}
$$

This equation may have one or three turning point.

$$
color{#4257b2}text{(d)} f(x)=-x^5+x^4-x^3+x^2-x+1
$$

The turning point is most $n-1$ as follows:

$$
n=5 n-1=5-1=4 text{Even number}
$$

This equation may have zero or two or four turning point.

Result
2 of 2
$$
text{color{Brown}(a) Even number (b) Odd number
\ \
(c) Odd number (d) Even number}
$$
Exercise 5
Step 1
1 of 5
Sketch the possible graph for the following expression.

$$
color{#4257b2}text{(a)} f(x)=-(x-8)(x+1)
$$

Use distributive property as follows:

$$
-[x(x+1)-8(x+1)]=-[x^2+x-8x-8]
$$

$$
-x^2-x+8x+8
$$

$$
-x^2+7x+8
$$

Exercise scan

Step 2
2 of 5
$$
color{#4257b2}text{(b)} f(x)=3(x+3)(x+3)(x-1)
$$

Use distributive property as follows:

$$
3x[(x+3)(x-1)]+9[(x+3)(x-1)]
$$

$$
3x[x^2+2x-3]+9[x^2+2x-3]
$$

$$
3x^3+6x^2-9x+9x^2+18x-27
$$

Rearrange the tiles to group like terms as follows:

$$
3x^3+15x^2+9x-27
$$

Exercise scan

Step 3
3 of 5
$$
color{#4257b2}text{(c)} f(x)=(x+2)(x-4)(x+2)(x-4)
$$

$$
(x+2)^2(x-4)^2
$$

$$
[x^2+4x+4][x^2-8x+16]
$$

Use distributive property as follows:

$$
x^2[x^2-8x+16]+4x[x^2-8x+16]+4[x^2-8x+16]
$$

$$
x^4-8x^3+16x^2+4x^3-32x^2+64x+4x^2-32x+64
$$

Rearrange the tiles to group like terms as follows:

$$
x^4+(-8x^3+4x^3)+(16x^2-32x^2+4x^2)+(64x-32x)+64
$$

$$
x^4-4x^3-12x^2+32x+64
$$

Exercise scan

Step 4
4 of 5
$$
color{#4257b2}text{(d)} f(x)=-4(2x+5)(x-2)(x+4)
$$

$$
-4(2x+5)[(x-2)(x+4)]
$$

$$
(-8x-20)[x^2+2x-8]
$$

Use distributive property as follows:

$$
-8x[x^2+2x-8]-20[x^2+2x-8]
$$

$$
-8x^3-16x^2+64x-20x^2-40x+160
$$

Rearrange the tiles to group like terms as follows:

$$
-8x^3+(-16x^2-20x^2)+(64x-40x)+160
$$

$$
-8x^3-36x^2+24x+160
$$

Exercise scan

Result
5 of 5
$$
text{color{Brown}(a) $-x^2+7x+8$
\ \
(b) $3x^3+15x^2+9x-27$
\ \
(c) $x^4-4x^3-12x^2+32x+64$
\ \
(d) $-8x^3-36x^2+24x+160$}
$$
Exercise 6
Step 1
1 of 2
Which of the following characteristic of the graph of

$y=k(x+14)(x-13)(x+15)(x-16)$ cant determined.

The $x$ intercepts the shape of the function near each zero.

Result
2 of 2
$$
text{color{Brown}The $x$ intercepts the shape of the function near each zero.}
$$
Exercise 7
Step 1
1 of 3
Determine of the polynomial function that passes through point $(7, 5000)$ and has a zeros of

$$
color{#4257b2}x=2
$$

Standard function is $y=a(x+x_{1})$

$$
y=a(x-2)
$$

Substitute the value of $x=7, y=5000$ as follows:

$$
5000=a(7-2) 5000=5a
$$

$$
a=dfrac{5000}{5} a=1000
$$

$$
y=1000(x-2)
$$

$$
color{#4257b2}x=-3, -3
$$

Standard function is $y=a(x+x_{1})(x+x_{2})$

$$
y=a(x+3)(x+3)
$$

Substitute the value of $x=7, y=5000$ as follows:

$$
5000=a(7+3)(7+3) 5000=100a
$$

$$
a=dfrac{5000}{100} a=50
$$

$$
y=50(x+3)(x+3)
$$

Step 2
2 of 3
$$
color{#4257b2}x=5
$$

Standard function is $y=a(x+x_{1})$

$$
y=a(x-5)
$$

Substitute the value of $x=7, y=5000$ as follows:

$$
5000=a(7-5) 5000=2a
$$

$$
a=dfrac{5000}{2} a=2500
$$

$$
y=2500(x-5)
$$

Result
3 of 3
$$
text{color{Brown}$y=1000(x-2)$
\ \
$y=50(x+3)(x+3)$
\ \
$y=2500(x-5)$}
$$
Exercise 8
Step 1
1 of 2
Describe the transformed function for the original equation is $y=x^4$ for the following terms:

$$
color{#4257b2}text{(a)} y=-25[3(x+4)]^4-60
$$

$$
a=-25 k=3 d=-4 c=-60
$$

$$
color{#4257b2}text{(b)} y=8left[dfrac{3}{4} xright]^4+43
$$

$$
a=8 k=dfrac{3}{4} c=43
$$

$$
color{#4257b2}text{(c)} y=(-13x+26)^4+13
$$

$$
k=-13 d=-26 c=13
$$

$$
color{#4257b2}text{(d)} y=dfrac{8}{11}(-x)^4-1
$$

$$
a=dfrac{8}{11} k=-1 c=-1
$$

Result
2 of 2
$$
text{color{Brown}(a) $a=-25 k=3 d=-4 c=-60$
\ \
(b) $a=8 k=dfrac{3}{4} c=43$
\ \
(c) $k=-13 d=-26 c=13$
\ \
(d) $a=dfrac{8}{11} k=-1 c=-1$}
$$
Exercise 9
Step 1
1 of 2
$$
text{color{#4257b2}Describe the transformation that are applied to the attached graph in the textbook for the parent function of $f(x)=x^3$}
$$

The center point of the parent function $f(x)=x^3$ is equal $(0, 0)$, and the center point of transformed function is equal $(-4, -2)$, so the function transformed by the following terms:

** Vertically translated by $(2)$ units down on the $(y)$ axis.

** Horizontal translated by $(-4)$ units to the left side on the $(x)$ axis.

** Vertically stretched by factor of $(5)$ and reflected to the $(x)$ axis.

$$
f(x)=-5(x+4)^3-2
$$

Result
2 of 2
$$
text{color{Brown}$$f(x)=-5(x+4)^3-2$$}
$$
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