Nelson Science Perspectives 10
Nelson Science Perspectives 10
1st Edition
Christy C. Hayhoe, Doug Hayhoe, Jeff Major, Maurice DiGiuseppe
ISBN: 9780176355289
Textbook solutions

All Solutions

Page 582: Review

Exercise 1
Solution 1
Solution 2
Result
1 of 1
A converging lens produces real as well as virtual images.
Step 1
1 of 2
Converging lens produces either real and virtual images.
Result
2 of 2
Real and virtual images.
Exercise 2
Solution 1
Solution 2
Step 1
1 of 2
Diverging lens produces only virtual images.
Result
2 of 2
It only produces virtual images.
Result
1 of 1
A diverging lens produces virtual images only.
Exercise 3
Solution 1
Solution 2
Step 1
1 of 2
The centre of the lens is called the optical centre. It lies on the principal axis and any light ray passing through it, passes through it without bending.
Result
2 of 2
The centre of the lens is called the optical centre.
Step 1
1 of 2
Centre of lens is called optical centre.
Result
2 of 2
It is called optical centre.
Exercise 4
Solution 1
Solution 2
Step 1
1 of 2
Two application of the converging lens are in compound microscopes or magnifying glasses and one application of diverging lenses is in construction of eyeglasses.
Result
2 of 2
Compound microscopes, magnifying glasses, eyeglasses etc.
Step 1
1 of 2
Converging lenses as magnifying glasses and in compound microscope produce virtual images of objects placed in front of them.
Step 2
2 of 2
Diverging lenses as eyeglasses produce virtual images of objects placed in front of them.
Exercise 5
Solution 1
Solution 2
Step 1
1 of 2
A compound microscope produces both real and virtual images of the object under observation. The objective lens first produces a real image of the object within the focal length of the eyepiece lens. The eyepiece lens then magnifies this real image to produce a large virtual image of the object.
Result
2 of 2
A compound microscope produces both real and virtual images of the object under observation.
Step 1
1 of 2
Compound microscope produces both virtual and real image.

Real image is produced by the objective lens when the actual object is placed withing the focal length of the lens and virtual one is produced by the eyepiece lens which magnifies the real image which as a result gives large, virtual image of the actual objects.

Result
2 of 2
Compound microscope produces both real and virtual images.
Exercise 6
Solution 1
Solution 2
Result
1 of 1
The object being observed using a refractive telescope is at an infinite distance away from the telescope.
Step 1
1 of 2
Object which is being observed by a refractive telescope is placed at an infinite distance from the telescope.
Result
2 of 2
It is placed at an infinite distance from the telescope.
Exercise 7
Solution 1
Solution 2
Step 1
1 of 2
Negative meniscus lens treats nearsightedness (myopia) since it spreads incoming rays of light so they could form image directly in retina.
Result
2 of 2
It treats nearsightedness (myopia).
Step 1
1 of 2
A negative meniscus lens is a modified version of a diverging lens. It diverges the light rays falling on to it, so that the image if correctly formed on the retina for people having near-sightedness or myopia.
Result
2 of 2
Near-sightedness or myopia is treated using a negative meniscus lens.
Exercise 8
Solution 1
Solution 2
Result
1 of 1
Eye muscles adjust to change the shape of the lens in the eyeball in order to focus objects correctly on the retina and form sharp images of the objects and the surroundings.
Step 1
1 of 2
Eye muscles adjust focus as they slightly change shape of the lens.
Result
2 of 2
They adjust focus.
Exercise 9
Step 1
1 of 6
a.

The image of the candle placed at a distance of 34 centimeters in front of the lens will be real in nature and inverted in attitude. It will be identical in size as the candle because it is placed on $34=2(17)=2$F of the lens. The image will be formed at a distance of 34 centimeters from the lens on the other side of the lens as the object.

Step 2
2 of 6
b.

The image of the candle placed at a distance of 52 centimeters in front of the lens will be real in nature and inverted in attitude. It will be smaller in size as the candle because it is placed on $52>2(17)=2$F of the lens. The image will be formed at a distance less than 2F from the lens on the other side of the lens as the object.

Step 3
3 of 6
c.

The image of the candle placed at a distance of 17 centimeters in front of the lens will be real in nature and inverted in attitude. It will be infinitely huge in size as the candle because it is placed on the focus of the lens. The image will be formed at an infinite distance from the lens and therefore invisible to the human eye.

Step 4
4 of 6
d.

The image of the candle placed at a distance of 25 centimeters in front of the lens will be real in nature and inverted in attitude. It will be larger in size as the candle because it is placed on $25<2(17)=2$F of the lens. The image will be formed at a distance greater than 2F from the lens on the other side of the lens as the object.

Step 5
5 of 6
e.

The image of the candle placed at a distance of 12 centimeters in front of the lens will be virtual in nature and upright in attitude. It will be larger in size as the candle because it is placed on $12<17$, that is within the focal length of the lens. The image will be formed on the same side of the lens as the object.

Result
6 of 6
Click to see answers.
Exercise 10
Solution 1
Solution 2
Step 1
1 of 2
Diverging lens can never produce a real image since it spreads beam of light which is falling on their surface from the focus on the same side of the lens.

Beam of light which is striking surface of the lens on the left side will diverge from the right side, appearing to diverge from the left focus and vice versa.

Reflected rays never focus into one single point there the image will be formed, their extensions do instead which makes formed image virtual.

Result
2 of 2
They never form real image since the beam of light which strikes their surface is being spread while reflecting and rays never diverge into a single point, their extension do instead.
Step 1
1 of 1
A diverging lens, diverges a beam of light falling on its surface from the focus of the lens located on the same side of the lens as the beam. Therefore, a beam of light striking the left side of the lens will diverge from its right side, appearing to diverge from the left focus of the lens and a beam of light striking the right side of the lens will diverge from its left side, appearing to diverge from the right focus of the lens. These rays on divergence will never intersect and therefore can never form real images and therefore always form virtual images only.
Exercise 11
Solution 1
Solution 2
Step 1
1 of 2
Real images are always inverted in attitude while virtual images are always upright in attitude. Therefore, any real image formed by a converging lens will always be inverted in attitude while any virtual image formed by a converging or a diverging lens will always be upright in attitude.
Result
2 of 2
Real images are always inverted in attitude while virtual images are always upright in attitude.
Step 1
1 of 2
$textit{a.}$, Image formed by the converging lens is either real or virtual; when real it will be inverted in altitude and when virtual it will be upright in altitude.

$textit{b.}$, Image formed by diverging lens is virtual, therefore, upright in altitude.

Result
2 of 2
$textit{a.}$, Virtual: upright in altitude. Real: inverted in altitude.

$textit{b}$, Virtual: upright in altitude.

Exercise 12
Solution 1
Solution 2
Result
1 of 1
Images formed on the retina of eye are always real in nature and inverted in attitude.
Step 1
1 of 2
Images formed on the retina of the eye are real in nature and inverted in altitude.
Result
2 of 2
Real in nature and inverted in altitude.
Exercise 13
Step 1
1 of 9
i. Ray diagram:Exercise scan
Step 2
2 of 9
The image formed is real in nature and inverted in attitude. It is located between f and 2f on the other side of the lens as the object. It is smaller than the object in size.
Step 3
3 of 9
ii. Ray diagram:Exercise scan
Step 4
4 of 9
The image formed is real in nature and inverted in attitude. It is located beyond 2f on the other side of the lens as the object. It is larger than the object in size.
Step 5
5 of 9
iii. Ray diagram:Exercise scan
Step 6
6 of 9
The image formed is virtual in nature and upright in attitude. It is located beyond f on the same side of the lens as the object. It is larger than the object in size.
Step 7
7 of 9
iv. Ray diagram:Exercise scan
Step 8
8 of 9
The image formed is virtual in nature and upright in attitude. It is located on the same side of the lens as the object. It is smaller than the object in size.
Result
9 of 9
Click to see answers.
Exercise 14
Solution 1
Solution 2
Step 1
1 of 2
$textit{Hyperopia}$ is an eye accommodation condition in which is eye unable to see objects which are located near the eye clearly, but can see objects which are located far from the eye.

This condition is caused by the shortening of the eyeball which brings the retina closer to the lens which will cause formation of the real image behind the retina, as the result part of the image which falls on the retina will be blurred.

$textit{Presbyopia}$ is a form of farsightedness which is caused by the weakening of the eye muscles as they age.

That is why it is almost inevitable in old age.

Result
2 of 2
Hyperopia is an eye accommodation condition in which is eye unable to see objects which are located near the eye clearly, but can see objects which are located far from the eye.

Presbyopia is a form of farsightedness which is caused by the weakening of the eye muscles as they age.

Step 1
1 of 1
Hyperopia is a eye accommodation condition. In this condition, the eye is unable to clearly see objects located near the eye but can see objects located far from the eye. Therefore, this is also known as far-sightedness. This condition is caused by the shortening of the eyeball which brings the retina of the eye closer to the lens and therefore the real image formed by the lens is formed behind the retina; as a result, the portion of the image falling on the retina is blurred. Presbyopia is a form of far-sightedness but is not caused by shortening of the eyeball, but weakening of the eye muscles as they age. It is for this reason that presbyopia is almost inevitable in old age.
Exercise 15
Step 1
1 of 5
a. In near-sightedness, the image is formed in front of the retina. This is corrected using a diverging lens which diverges the light rays falling on it so helps the eye lens focus a sharp image on the retina of the eye.
Step 2
2 of 5
Diagram:Exercise scan
Step 3
3 of 5
b. In far-sightedness, the image is formed behind the retina. This is corrected using a converging lens which converges the light rays falling on it so helps the eye lens focus a sharp image on the retina of the eye.
Step 4
4 of 5
Exercise scan
Result
5 of 5
Click to see answers.
Exercise 16
Solution 1
Solution 2
Step 1
1 of 3
Astigmatism is an eye condition where the eye produces blurred images of its surroundings because of the irregular shape of the cornea of the eye or the lens of the eye.
Step 2
2 of 3
Glaucoma is an eye disorder which is caused by damage to the optical nerve in the eye. This is a serious condition and can even lead to loss of vision if not treated promptly.
Step 3
3 of 3
The lens of the eye becomes cloudy with age. This condition is called cataract which leads to blurry visions because of the curtain of cloudiness gathered on the natural eye lens. This is treated by a surgery in which this cloudy natural lens is replaced by an artificial clear lens.
Step 1
1 of 2
$textit{Astigmatism}$ is an eye condition where the images produced by the eye are blurred because the cornea, or lens of the eye have irregular shape.

$textit{Glaucoma}$ is an eye disorder which is caused by the damage of the optical nerve.

$textit{Cataracts}$ is an eye condition which leads to blurry vision since there is a “curtain” over the natural eye lens.

Result
2 of 2
Astigmatism is an eye condition where the images produced by the eye are blurred because the cornea, or lens of the eye have irregular shape.

Glaucoma is an eye disorder which is caused by the damage of the optical nerve.

Cataracts is an eye condition which leads to blurry vision since there is a “curtain” over the natural eye lens.

Exercise 17
Step 1
1 of 3
Data:

$$
f=21
$$

$$
d_o=57
$$

Step 2
2 of 3
b.

Formula:

$$
dfrac{1}{d_0}+dfrac{1}{d_i}=dfrac{1}{f}
$$

Rearrange to solve for $d_i$:

$$
dfrac{1}{d_i}=dfrac{1}{f}-dfrac{1}{d_0}
$$

Simplify using least common denominator:

$$
dfrac{1}{d_i}=dfrac{d_0-f}{fd_0}
$$

Rearrange:

$$
d_i=dfrac{fd_0}{d_0-f}
$$

Substitute values:

$$
d_i=dfrac{21(57)}{57-21}
$$

Simplify and evaluate:

$$
d_i=dfrac{1197}{36}=dfrac{133}{4}=33.25
$$

The image of the object (candle) formed is $33.25$ cm away from the lens.

Step 3
3 of 3
a.

The positive value of $d_i$ indicates that this image is real in nature and inverted in attitude. Also note that it is formed on the other side of the lens as the object.

Exercise 18
Step 1
1 of 3
Data:

$$
f=18
$$

$$
d_o=13
$$

Step 2
2 of 3
Formula:

$$
dfrac{1}{d_0}+dfrac{1}{d_i}=dfrac{1}{f}
$$

Rearrange to solve for $d_i$:

$$
dfrac{1}{d_i}=dfrac{1}{f}-dfrac{1}{d_0}
$$

Simplify using least common denominator:

$$
dfrac{1}{d_i}=dfrac{d_0-f}{fd_0}
$$

Rearrange:

$$
d_i=dfrac{fd_0}{d_0-f}
$$

Substitute values:

$$
d_i=dfrac{18(13)}{13-18}
$$

Simplify and evaluate:

$$
d_i=dfrac{234}{-5}=-46.8
$$

The image of the object (leaf) formed is $46.8$ cm away from the lens.

Step 3
3 of 3
The negative value of $d_i$ indicates that this image is virtual in nature and upright in attitude. Also note that it is formed on the same side of the lens as the object.
Exercise 19
Step 1
1 of 3
Data:

$$
h_o=14
$$

$$
h_i=43
$$

Step 2
2 of 3
Equation of magnification in terms of height:

$$
M=dfrac{h_i}{h_o}
$$

Substitute values:

$$
M=dfrac{43}{14}
$$

Evaluate:

$$
M=3.071
$$

The magnification of the lens is $3.071$

Result
3 of 3
The magnification of the lens is $3.071$.
Exercise 20
Step 1
1 of 4
Data:

$$
h_o=18
$$

$$
h_i=12
$$

Step 2
2 of 4
a.

Equation of magnification in terms of height:

$$
M=dfrac{h_i}{h_o}
$$

Substitute values:

$$
M=dfrac{12}{18}
$$

Evaluate:

$$
M=0.bar6
$$

The magnification of the lens is $0.bar6$

Step 3
3 of 4
b. Virtual images are always formed on the same side of the lens as the object, therefore this virtual image will also be formed on the same side of the lens as the object.
Step 4
4 of 4
c. It is a characteristic property of diverging lenses to $color{#c34632}text{always}$ form $color{#c34632}text{virtual}$ images of objects placed in front of them. These virtual images are always $color{#c34632}text{smaller in size}$ than the object, therefore it is impossible for a diverging lens to produce a magnified virtual image.
Exercise 21
Step 1
1 of 3
Data:

$$
d_i=11
$$

$$
d_o=53
$$

Step 2
2 of 3
Equation:

$$
dfrac{1}{f}=dfrac{1}{d_0}+dfrac{1}{d_i}
$$

Substitute values:

$$
dfrac{1}{f}=dfrac{1}{53}+dfrac{1}{11}
$$

Simplify:

$$
dfrac{1}{f}=0.0189+0.bar0bar9=0.1098
$$

Evaluate:

$$
f=dfrac{1}{0.1098}=9.107
$$

The focal length of the camera lens is $9.107$ centimeters.

Result
3 of 3
The focal length of the camera lens is 9.107 centimeters.
Exercise 22
Step 1
1 of 3
a. The magnification of this lens is $2.8>1$, this implies that this must be a converging lens because only converging lenses have the ability to produce enlarged virtual images of objects placed within their focal length.
Step 2
2 of 3
b. The image is located on the same side of the lens as the object. This is a characteristic property of virtual images.
Result
3 of 3
a. Converging lens.

b. The image is on the same side of the lens as the object.

Exercise 23
Step 1
1 of 3
Ray diagram:Exercise scan
Step 2
2 of 3
The light rays are used to determine the location of the object. Note that it is between F and 2F on the other side of the lens as the image.
Result
3 of 3
Click to see ray diagram.
Exercise 24
Solution 1
Solution 2
Step 1
1 of 2
a. The student needed to sit “near” the board in order to clearly see it. This implies that he had near-sightedness also known as myopia.
Step 2
2 of 2
b. Near-sightedness or myopia can be corrected using a pair of negative meniscus lenses. This lens is a modified version of a diverging lens and it diverges light rays falling on the eye-lens so that the image is sharply focused on the retina.
Step 1
1 of 2
$textit{a.}$, Student has nearsightedness (myopia) since he needs to sit near the board in order to see clearly.

$textit{b.}$, Student’s eyeglasses have lenses that have negative meniscus which are modified version of diverging ones, since they focus light rays in the retina which helps people with farsightedness see clearer.

Result
2 of 2
$textit{a.}$, Student has nearsightedness (myopia).

$textit{b.}$, His eyeglasses have negative meniscus.

Exercise 25
Solution 1
Solution 2
Step 1
1 of 1
The camera and the human eye, both form real and inverted images of their surroundings. In both cases, the screen is fixed so the lens adjusts to form a sharp image. In case of a camera this is done by focusing while in the eye, this is done by the eye muscles. These images are formed on a screen of a photographic film or a charged couple device in case of a camera while in the human eye, these images are formed on the retina.
Step 1
1 of 2
Both camera and human eye form real and inverted images.

In both cases screen is fixed which helps lens in a formation sharp image.

In the case of human eye focusing is done by the eye muscles which are slightly changing shape of the lens and in the case of camera focusing is done manually.

In the case of camera images are formed on a photographic film and in the case of human eye images are formed on the retina.

Result
2 of 2
Both camera and human eye form real and inverted imaged, screen is fixed which helps lens in a formation of sharp image.

Focusing is done by the eye muscles in the case of human eye and manually in the case of camera and images are formed in the retina in the case of human eye and on the photographic film in the case of the camera.

Exercise 26
Step 1
1 of 1
If an invisibility cloak existed, it will be designed to bend light around the person that wears it and the person who is wearing it will not be capable to see a thing.
Exercise 27
Step 1
1 of 1
If all devices which are using lenses disappear it would affect our life pretty much.

People with eye conditions will not be able to see well, we will not be able to use devices which are important for scientific research such as microscope, telescope etc.

We will not be able to take photos, since the cameras are useful without lenses, flashlights will be useless as well.

Lasers, which are important nowdays, could not be controlled.

Exercise 28
Step 1
1 of 11
Timeline of invention of glasses:
Step 2
2 of 11
year: $textit{Before 1200.}$

In ancient times, people knew hot to enlarge things by using glass spheres filled with water.

Step 3
3 of 11
year: $textit{1200}$:

In Venice, people knew how to shape glass in convex shapes which they were holding in one hand while reading, but after, when they were making discs out of glass which they were using to close jars etc., they discover that while looking through the discs they can see objects more clearly.

Step 4
4 of 11
year: $textit{1300}$:

This is the time when lenses made of glass, for reading, were massive produced.

First eyeglasses were made of round lenses which were biconvex and farsightedness has been improved.

These two lenses were assembled with rim of metal or wrapped in leather and were being held with one handle.

Step 5
5 of 11
year: $textit{1400}$:

Around 1400., printed has been invented, therefore, the books became more available which has raised request for the eyeglasses.

Then, they made better steadiness for glasses on the nose, for the people who had to use both hands while working.

Step 6
6 of 11
year: $textit{1600}$:

There was a development in the processing of metal frames.

New ways to secure eyeglasses firmly have been discovered: to tie lenses around the head or bar under the hat etc.

Step 7
7 of 11
year: $textit{1700}$:

Edward Scarlett has perfected glasses which were now equipped with side-arms.

Then, the bifocals were invented which are lenses with two different optical powers which made each lens separated in two parts from which one has been treating farsightedness and one has been treating nearsightedness.

Step 8
8 of 11
year: $textit{1800}$:

Then, the most popular were eyeglasses without side-arms.

Step 9
9 of 11
year: $textit{1900}$:

They became a famous fashion accessory which have protected eyes and was irreplaceable for the vision.

Step 10
10 of 11
year $textit{2000}$:

Nowdays, new materials are combined with different designs and Italian eyewear is world leader when it comes to eyeglasses.

Result
11 of 11
See explanation.
Exercise 29
Step 1
1 of 3
Night vision goggles produce green and black images.

They consist intensifier tubes which use reflected infrared radiation which is invisible to the human eye. This radiation is is emitted by the Sun and stars.

These devices have:

– intensifier tubes and these contains tubes which have photocathode at one end and internal anode in the very middle and on the other end is the phosphor screen.

There is a high voltage between photocathode and anode and it creates a strong electrostatic field.

Step 2
2 of 3
Image is formed after the infrared light falls on the phosphor screen which will later produce image.
Step 3
3 of 3
Diagram which shows how night goggles work:Exercise scan
Exercise 30
Step 1
1 of 6
3D glasses helps us to see imkage on the screen in three dimensions.

There are three types of 3D glasses:

1. anaglyph

2. polarized

3. shutter

Step 2
2 of 6
How does each type work?

Anaglyph glasses use special lenses in variations of red/blue colours (red/cyan, red/green, magenta/green).

Image that we actually see is produced by filtering of the colour of the layered image we are looking at. One lens filters out all the red, and the other one filters out blue which is causing our brain to see in 3D and the image we are looking at is one same image which is projected from two different angles or two entirely different images.

Step 3
3 of 6
Polarized glasses are using polarized lenses which restrict the light which enters our eyes, not by red and blue colour, but by brown/yellowish tint.

Image which is projected on the screen is two, superimposed images, through an orthogonal polarizing filter and glasses have exactly the same filter which allows each eye to see two different images.

Step 4
4 of 6
Shutter glasses use LCD screen technology which darkens each lens by alternating left and right side.

They are mostly battery powered and are pretty expensive.

Step 5
5 of 6
Human eyes have binocular vision which works best when we use both eyes.

It relies on the distance between our eyes in order to present us with two different perspectives of the same thing. Work of 3D glasses depends on how eyes work and communicate with our brain.

Step 6
6 of 6
Pamphlet:

“If you want to get fully experience while watching your favourite movie and to explore wonders of Sci-Fi world hand by hand with your favourite heroes or just enjoy beautiful landscapes, put on your 3D glasses, sit relax and enjoy your favourite movie, or participate in it just by watching it!”

Exercise 31
Solution 1
Solution 2
Step 1
1 of 2
a.
Chromatic aberration is a lens defect in which the colors of the white light become dispersed on refraction through it. This happens because each wavelenght of light refracts at a slightly different angle than the rest. The images formed by these defected lenses is over-exposed with color fringes and one color is more prominent than the rest. This defect can be reduced by using an achromatic lens in combination with this lens.
Step 2
2 of 2
b.
Spherical aberration is a lens defect in which each refracted ray of light refracts at a slightly different angle than the rest and instead of converging to the focus of the lens, they intersect the principal axis at different points. This defect can be reduced by using a refractive diffractive lens in combination with the defected lens.
Step 1
1 of 2
$textit{a.}$, $textit{Chromatic aberration}$ is defect of the lens in which are colours of white light being dispersed on a refraction through it.

This happens because each colour has different wavelength, therefore it has different changes in speed which cause bending at different angle.

Images which are formed by defected lenses are over-exposed with colour fringes and one colour is more prominent than the rest.

This defect is being reduced by an achromatic lens which is combined with the defected lens.

$textit{b.}$, Spherical aberration is defect of the lens in which each refracted ray of light refracts at a slightly different angle and instead of converging to the focus of the lens, rays intersect the principal axis at very different points.

This defect is being reduced by a refractive diffractive lens which is being combined with the defected lens.

Result
2 of 2
$textit{a.}$, It is defect of the lens in which colours of white light are being dispersed on a refraction through it.

$textit{b.}$, Spherical aberration is defect of the lens in which each refracted ray of light refracts at slightly different angle and instead of converging to the focus, rays intersect the principal axis at different points.

Exercise 32
Step 1
1 of 1
begin{tabular}{|l|l|l|l|}
hline
& optician & optometrist & opthalmologist \ hline
skill exhibits & begin{tabular}[c]{@{}l@{}}measuring, fitting \ and adjusting glassesend{tabular} & begin{tabular}[c]{@{}l@{}}providing primary vision\ care ranging (sight testing, treatment)end{tabular} & correcting eye conditions \ hline
career & customer service specialists & eye care specialist & begin{tabular}[c]{@{}l@{}}medical doctors,\ specialized in surgery of\ the eyeend{tabular} \ hline
end{tabular}
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