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Page 500: Assessment
Since the X is dominant over the Y chromosome, colorblindness will appear in males if it is inherited from their mother. In females, the recessive trait will appear if the recessive allele is inherited from both of the parents.
If a mother carries a recessive allele for colorblindness (red X chromosome), while the father does not, there is a 25 percent chance for that trait to appear in their offspring (genotype {color{Red}X}{color{Blue}Y}), while females (genotype {color{Blue}X}{color{Red}X}) are the carriers whose male children may be colorblind.
begin{center}
begin{tabular}{ c c c}
& {color{Blue}X} & {color{Red}X}\
{color{Blue}X} & {color{Blue}XX} & {color{Blue}X}{color{Red}X}\
{color{Blue}Y} & {color{Blue}X}{color{Blue}Y} & {color{Red}X}{color{Blue}Y}
end{tabular}
end{center}
Down syndrome (trisomy 21), Turner’s syndrome (45, X0), and Klinefelter’s syndrome (47, XXY) are all aneuploidies.
The sickle cell disease is a genetic disorder that is caused by substitution of thymine for adenine in one strand of the DNA molecule, which changes codon of the mRNA for a beta-globin from GAG (glutamic acid) to GUG (valine).
A DNA is a large molecule that first has to be cut into smaller pieces before the reading begin. Some bacterial enzymes known as restrictive enzymes are used in the laboratory for this very purpose. They are able to cut DNA into fragments of only several hundred bases long.
A DNA is a large molecule that first has to be cut into smaller pieces before the reading begin. Some bacterial enzymes known as restrictive enzymes are used in the laboratory for this very purpose. They are able to cut DNA into fragments of only several hundred bases long.
Genomic imprinting represents epigenetic changes that are heritable and are associated with certain traits or diseases. An example of an illness that is linked to genomic imprinting is an Angelman syndrome. The gene that is called UBE3A is located on a chromosome 15. A healthy child inherits an expressed gene from a mother and a silenced gene from a father. If the mother’s genome has a deletion of this particular gene and the father’s gene is silenced, the Angelman syndrome will appear.
An experiment would include a cross between sick female and a healthy male fruit fly. If the gene for this illness is sex-linked, the male offspring is the only one that would be affected.
Since the X is dominant over the Y chromosome, colorblindness will appear in males if it is inherited from their mother. In females, the recessive trait will appear if the recessive allele is inherited from both of the parents.
If a mother carries a recessive allele for colorblindness (red X chromosome), while the father does not, there is a 25 percent chance for that trait to appear in their offspring (genotype {color{Red}X}{color{Blue}Y}), while females (genotype {color{Blue}X}{color{Red}X}) are the carriers whose male children may be colorblind.
begin{center}
begin{tabular}{ c c c}
& {color{Blue}X} & {color{Red}X}\
{color{Blue}X} & {color{Blue}XX} & {color{Blue}X}{color{Red}X}\
{color{Blue}Y} & {color{Blue}X}{color{Blue}Y} & {color{Red}X}{color{Blue}Y}
end{tabular}
end{center}
If a mother is also colorblind (genotype {color{Red}X}{color{Red}X}), while the father does not, that trait will appear only in their male offspring.
begin{center}
begin{tabular}{ c c c}
& {color{Red}X} & {color{Red}X}\
{color{Blue}X} & {color{Blue}X}{color{Red}X} & {color{Blue}X}{color{Red}X}\
{color{Blue}Y} & {color{Red}X}{color{Blue}Y} & {color{Red}X}{color{Blue}Y}
end{tabular}
end{center}
If a mother is healthy but carries the allele for colorblindness, while the father is colorblind, that trait will appear in 50% of their offspring.
begin{center}
begin{tabular}{ c c c}
& {color{Red}X} & {color{Blue}X}\
{color{Red}X} & {color{Red}X}{color{Red}X} & {color{Blue}X}{color{Red}X}\
{color{Blue}Y} & {color{Red}X}{color{Blue}Y} & {color{Blue}X}{color{Blue}Y}
end{tabular}
end{center}
If both parents are colorblind, that trait will appear in all of their children.
begin{center}
begin{tabular}{ c c c}
& {color{Red}X} & {color{Red}X}\
{color{Red}X} & {color{Red}X}{color{Red}X} & {color{Red}X}{color{Red}X}\
{color{Blue}Y} & {color{Red}X}{color{Blue}Y} & {color{Red}X}{color{Blue}Y}
end{tabular}
end{center}
Cystic fibrosis is an autosomal recessive genetic disorder which results in the synthesis of altered cystic fibrosis transmembrane conductance regulator (CFTR) protein. Since this illness is caused by changes in a single gene, it will not reflect in the karyotype because this alteration of a DNA molecule is too small.
Therefore, the restriction enzymes that produce sticky ends are BamHI, HindIII, and EcoRI. All the restriction enzyme recognition sites are sequences that read the same in both directions.
An experiment would include a cross between sick female and a healthy male fruit fly. If the gene for this illness is sex-linked, the male offspring is the only one that would be affected.
Among prokaryotic organisms, there is a linear relationship between a genome size and a number of genes it contains. However, that is not the case in eukaryotes. For example, mustard weed has a larger genome and more genes than a roundworm. This is called the C-paradox. The genome size in eukaryotes is measured in haploid cells and it is constant for a species, so it is called a C-value.
Is there a relationship between genome size and a number of genes?
Some organisms have a large genome compare to the gene number it contains because of the repetitive DNA sequences which are the non-coding part of the molecule.
Is there a relationship between a number of genes and the complexity of an organism?
There is a linear relationship between a number of genes and the complexity of an organism. For example, people have about 25 000 genes, mice have around 24 000, while roundworm has 19 000 genes. However, there are exceptions, mustard weed has a smaller genome than humans, but the estimated gene number is about 25 500.
Since males have only one X chromosome, they can inherit black or orange fur, but not both.
However, a genetic disorder can occur in the male cat because of nondisjunction during meiosis among sex chromosomes. Males with this condition have an extra X chromosome, so their genotype is 47, XXY. This is very rare, but the result is a male calico cat, with an expression of both fur colors – black, and orange.
A beneficial mutation improves the health of an organism. Some examples include mutations in bacterial genome that causes their resistance to antibiotics, or mutation that affects the CCR5 gene, that codes a protein found in the surface of leukocytes, which causes HIV resistance in human. Polyploidy is another example of beneficial mutations, in which a plant’s genome contains more than two sets of chromosomes. That makes these plants bigger and stronger.
However, there are far more examples of harmful mutations. An example of point mutation that alters the phenotype of a person is the sickle cell disease. The cause of this genetic disorder is a substitution of thymine for adenine in one strand of the DNA molecule, which changes codon of the mRNA for a beta-globin from GAG (glutamic acid) to GUG (valine). This change in amino acid alters the structure of hemoglobin molecule making it less soluble which lead to the formation of sickle-shaped erythrocytes. However, it is discovered that persons who have one copy of the sickle cell allele are less prone to malaria because this allele provides them protection from the parasite.
A DNA is a large molecule that has to be cut into smaller pieces before the reading begin. Some bacterial enzymes known as restrictive enzymes are used in the laboratory for this very purpose. They are able to cut DNA into fragments of only several hundred bases long. Some bacteria contain these enzymes so they could dissolve the genome of bacteriophage, which is a type of virus that invade bacteria. In this way, bacteria protect itself from viruses as by disabling their reproduction.
begin{center}
begin{tabular}{ c c c}
& {color{Blue}T} & {color{Blue}T}\
{color{Blue}T} & TT & TT\
{color{Blue}t} & Tt & Tt
end{tabular}
end{center}
We can conclude that their children wouldn’t express lactose intolerance, but half of their children will be the carriers of the recessive allele.
begin{center}
begin{tabular}{ c c c}
& {color{Blue}T} & {color{Blue}T}\
{color{Blue}T} & TT & TT\
{color{Blue}t} & Tt & Tt
end{tabular}
end{center}
We can conclude that their children wouldn’t express lactose intolerance, but half of their children will be the carriers of the recessive allele.
The ratio in genotypes is:
– 50 percent homozygous dominant and
– 50 percent heterozygous.
Therefore, the ratio of phenotypes is 100 percent normal.
The ratio in genotypes is:
– 50 percent homozygous dominant and
– 50 percent heterozygous.
Therefore, the ratio of phenotypes in their children is 100 percent normal, which matches to the pedigree chart.
Persons 8, 9, and 10 are not lactose intolerant. Their father is homozygous recessive, but their mother is eighter homozygous dominant or heterozygous, so their children inherited one recessive allele from a father and a dominant allele from their mother, which makes them heterozygous.
Persons 11 and 12 are lactose intolerant, so their genotype is aa, which means that their parents are both heterozygous for the LCT gene.
The Genetic Information Nondiscrimination Act passed the Congress in 2008. This act is meant to prevent genetic discrimination in health insurance and employment. Health insurers are barred from refusing coverage to a healthy person or charging him higher premiums only because he has a genetic predisposition for a certain disease, which may or may not develop in his life. This act also prevent employers to make resolutions about hiring, firing, job position, or promotion based on the genetic predispositions of employes or potential employes.
However, adopted children should know the medical history of biological parents because of their own health and lifestyle even if the parents wouldn’t give a consent. Many diseases are hereditary, while others, such as some types of cancer, diabetes mellitus or hypertension, have a higher incidence among family members. This means that people with positive family history for certain illness should start screenings earlier in life than other people who have a negative family history. Also, if a child could be the allele carrier for certain diseases, such as sickle cell, Tey-Sachs, or Huntington disease, knowing medical family history could be very important when this person wants to start a family.
Klinefelter syndrome is a genetic disorder that occurs because of nondisjunction during meiosis among sex chromosomes. Males with this condition have an extra X chromosome, so their genotype is 47, XXY.
The genotype of females with Turner’s syndrome is 45, X0.
Down syndrome is a trisomy 21, which means that persons with this condition have an extra chromosome 21.
In the pedigree chart, males are marked as squares, while females are represented with circles. The shaded symbol means that the trait is expressed in that person, while symbols that are not shaded tells us that these persons doesn’t express the studied trait. Half shaded symbols determines the carriers for autosomal traits, while the circle with the dot in its center represents the carrier for an X-linked trait.
Generations are labeled in Roman numerals, while individuals are labeled in Arabic numbers.
Vertical lines represent marriage, while horizontal represents children. Breeding among relatives is marked with double lines.
In order to understand better the pedigree chart, we should know the way that the studied trait is inherited – is it recessive or dominant. If it is more common among males, it is probably X-linked, but if the ratio of expression is similar among males and females the trait is presumably autosomal.
1. Bacterial enzymes known as restrictive enzymes are used in the laboratory for cutting DNA into fragments of only several hundred bases long
2. The next step is electrophoresis, where DNA fragments are put in the porous gel
3. The electric voltage is been applied which cause negatively charged DNA fragments to move through the porous gel. The smaller DNA fragments will pass faster.
4. The particular stain is used that makes DNA fragments visible
5. Scientists get a model of bands based on the size of these DNA pieces.
6. In the next step, they join single-stranded DNA with DNA polymerase and nucleotide bases that are chemically stained.
7. DNA polymerase forms new DNA strand based on the one they put in
8. Because nucleotides this enzyme use are colored, scientists are able to read a complementary sequence of the examined DNA fragment.