I have been asked to find out if four fish and chip shops have been diluting their vinegar, to save more money. I do this by carrying out a few experiments, testing on the separate fish and chip shops vinegar samples.
Apparatus:
- Vinegar samples
- Distilled Water
- Sodium Hydroxide
- Phenolphthalein
- Conical Flask
- Volumetric Flask
- Burette + Stand
- Pipette
- Balance
- Tile
Method
To carry out this experiment, I first had to get the control vinegar and measure how much ethanoic acid I found in the vinegar, then compare with the fish and chip shops.
So to do this I filled the burette with the sodium hydroxide, I then added 10cm3 of distilled water to 100 cm3 of the vinegar to dilute it (
...this was so when the colour changed I could see it)! After this I got 25 cm3 of the vinegar and put it in the conical flask, then to this I added the indicator.
I added the sodium hydroxide slowly to the solution in the conical flask until the sample turned pink, I then read the number of cm3 of sodium hydroxide had gone into the conical flask off the burette and kept the reading.
I repeated this experiment three more times, to get more results for a better average. Then with all the results collected I had to calculate the average.
Add all readings, then divide by three. The result was 37.75 cm3.
Equation
M = Molar cone
V = Volume used
N = Number of molars reacting
M1 = M2 ( V2 ( N1 / V1 ( N2 = 0.1 ( 37.75 / 25 ( 1 = 0.151
( CH3 CO2H + NaoH ==> CH3 CO2 Na + H2O )
2C = 2 ( 12 = 24
4H
= 4 ( 1 = 4
2O = 2 ( 16 = 32
24 + 4 + 32 = 60
Then to get my control results I had to multiply 37.75 by 60 and then I have to multiply that again by 10, which equalled 90.6 g/l.
Now this was done, I had to do the four fish and chip shop samples.
Blue Whale = I carried out the experiment again as shown above. I recorded the results three times and got these readings.
1st 41 cm3
2nd 39 cm3
3rd 39 cm3
I then added all the readings together and divided then by three and got 39.7 cm3. I Then multiplied it by 0.1 after this I divided it by 25 and I got 0.1588. Then I multiplied it by 60 and got 9.528, then multiplied this by 10. Then after this long equation my final result came out as 95.28 g/l. This concludes that the Blue Whale fish and chip shop do not dilute their vinegar.
Fish Frier = I did the experiment again but with the different sample and got these results.
31 + 29 + 27 / 3 = 29
0.1 ( 29 ( 1 / 25 ( 1 = 0.116 ( 60 = 9.96 ( 10 = 69.6 g/l
This concludes that the Fish Frier fish and chip shot dilute their vinegar a lot.
Frying Tonight = I did the experiment again this time I got these results.
16 + 17 + 15 / 3 = 16
16 ( 0.1 ( 1 / 25 ( 1 = 0.064 ( 60 = 3.84 ( 10 = 38.4 g/l
This concludes that the Frying Tonight fish and chip shop dilutes their vinegar a great deal more than they do
at the Fish Frier fish and chip shop.
Frier Tuck = finally I did the experiment one last time and got these result.
21 + 21 + 21 / 3 = 21
21 ( 0.1 ( 1 / 25 ( 1 = 0.084 ( 60 = 5 .04 g/l
These results conclude that the Frier Tuck fish and chip shop do also dilute their vinegar.
The tests that I carried out were that I measured 25 cm3 of each vinegar sample and added an indicator (phenolphthalein) to them. I then measured the amount of sodium hydroxide I added to the vinegar solution until it turned to the colour pink.
These results conclude that the following fish and chip shops dilute their vinegar: Fish Frier, Frying Tonight and Frier Tuck. The results also include that Blue Whale fish and chip shop don't water down their vinegar.
I hope that my investigation has been of help.
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