Molec Bio Exam 3 – Flashcards
Unlock all answers in this set
Unlock answersquestion  
            | Cell Cycle Phases | 
answer 
        | • G1: checkpoint 1 • G2: checkpoint 2 • S: synthesis phase • M: mitosis phase (cell division) *cell cycle will stop if any issues w/ 1st or 2nd checkpoints  | 
question  
            | S Phase | 
answer 
        | • synthesis phase • DNA replication (each DNA molecule = chromatid) • sister chromatid adhesion • in bacteria, replication & segregation occur in same step  | 
question  
            | Mitosis | 
answer 
        | • cell division where parental cell is used to form two identical daughter cells • chromosome segregation • sister chromatids segregated to opposite poles of cell; each daughter cell thus rcvs identical info when cell divides • Phases: PMATC (prophase, metaphase, anaphase, telophase) • cytokinesis actually splits one cell into two  | 
question  
            | G1 | 
answer 
        | • first checkpoint • makes sure DNA not damaged before S phase • parental cell preparing for DNA replication  | 
question  
            | G2 | 
answer 
        | • 2nd checkpoint • makes sure DNA fully replicated before M phase • cell preparing for chromosome segregation  | 
question  
            | 2 major events during cell cycle | 
answer 
        | • DNA replication • chromosome segregation  | 
question  
            | What happens during checkpoints - G1 & G2 | 
answer 
        | • allow cells to check to ensure necessary materials and energy present to proceed to next phase • makes sure DNA not damaged  | 
question  
            | sister chromatids | 
answer 
        | pair of DNA duplicated molecules | 
question  
            | chromatid | 
answer 
        | individually copied DNA molecule | 
question  
            | sister chromatid cohesion | 
answer 
        | cohesin holds together sister chromatids until segregation | 
question  
            | microtubule-organizing centers | 
answer 
        | • centrosomes (animal cell) or spindle pole bodies (yeast/fung) • form poles at opposite ends of cells • microtubules pull sister chromatids towards poles, preparing for cell division  | 
question  
            | sister chromatid separation | 
answer 
        | cohesion ring destroyed, sister chromatids segregate to opposite poles of cells | 
question  
            | Interphase | 
answer 
        | • G1, S & G2 phases • when mitotic division not occuring • DNA is not compact or condensed  | 
question  
            | Prophase | 
answer 
        | • long DNA strands wrap into highly condensed chromosomes • nuclear envelope breaks down • microtubule organizing centers migrate to opposite poles of cell; signals metaphase  | 
question  
            | Metaphase | 
answer 
        | • microtubules (long fibers) attach to each kinetochore of chromosome pair (centromeres when chromatids) to organizing centers on either side • two chromosomes form bivalent attachment • microtubules pull sister chromatids towards each pole • chromosomes align in middle of cell because cohesin rings still surrounding them  | 
question  
            | bivalent attachment (metaphase) | 
answer 
        | • two kinetochores of sister chromatid pair are attached to microtubules of opposite sides (poles) of cell | 
question  
            | monovalent attachment (metaphase) | 
answer 
        | • only one kinetochore of sister chromatid pair is attached to a microtubule on one side of cell (pole) • results in uneven segregation of chromosomes into daughter cells  | 
question  
            | cohesin removed by… | 
answer 
        | proteolytic destruction ® signals anaphase | 
question  
            | anaphase | 
answer 
        | • cohesion between sister chromatids lost (via proteolysis) • chromosomes migrate to opposite poles of cell  | 
question  
            | telophase | 
answer 
        | • new nuclear membranes form around each sets chromosomes before cells split, final step mitosis | 
question  
            | cytokinesis | 
answer 
        | cell divides into two daughter cells | 
question  
            | cell cannot perform cytokinesis | 
answer 
        | one cell will have two nuclei with duplicate chromosomes | 
question  
            | cell cannot break apart cohesin rings | 
answer 
        | anaphase affected and cell could not segregate chromosomes to opposite poles from center | 
question  
            | histones | 
answer 
        | proteins that DNA winds around before tightly compacting | 
question  
            | nucleosomes | 
answer 
        | • assembly to form compact DNA to fit into body • histone forms a spool with DNA wrapped around it • 8 histones (two each of H2A, H3, H2B & H4) form 1 core • assembled from histone protein subassemblies • H3 & H4 form tetramer subassembly • 2 H2A & H2B dimers form two subassemblies • each histone protein has N-terminal tail • DNA wraps around each histone core 1.65 times (147bp in length)  | 
question  
            | human genome contains… | 
answer 
        | • 3billion bp = 1 meter long if stretched out • to fit into body, DNA wound into 23 pairs of chromosomes  | 
question  
            | when cell divides… | 
answer 
        | • DNA must be duplicated • two new daughter strands rapidly reassembled into nucleosomes • old histones distributed between two new DNA strands • new histones brought in to fill in gaps  | 
question  
            | N-terminal tail on histone | 
answer 
        | • provide guide for DNA to wrap around histone core • emerge between DNA strands & create groove (like screw) • force DNA to twist around histone in left-handed manner  | 
question  
            | what binds DNA to core of histone | 
answer 
        | via hydrogen bonds | 
question  
            | H3 & H4 tetramer binds what part of DNA? | 
answer 
        | middle & both ends of core DNA | 
question  
            | H2A and H2B dimers bind to what part of DNA? | 
answer 
        | binds DNA between middle and ends | 
question  
            | how are multiple nucleosomes connected? | 
answer 
        | • adjacent nucleosomes connected by short stretches of DNA called linker DNA • fifth histone, H1 protein, is linker histone that binds linker DNA  | 
question  
            | H1 linker protein | 
answer 
        | • stimulates first level of chromatin packing, formation of 30nm fiber • binds both end linker DNA and middle of nucleosomal DNA, bringing adjacent nucleosomes into close proximity • larger than other histones at ~21 kD  | 
question  
            | 10nm fiber | 
answer 
        | • less condensed form of chromatin • "beads on a string"  | 
question  
            | 30nm fiber | 
answer 
        | • more condensed version of chromatin • one of two structures (might differ between species) ® • solenoid • zig-zag  | 
question  
            | solenoid structure | 
answer 
        | • nucleosome disks stacked on top of one another; forming helix; linker DNA packed inside | 
question  
            | zig-zag structure | 
answer 
        | • requires longer linker DNA because of how the nucleosomes cross over one another from opposite sides (may be preferred form for species w/ longer linker DNA) | 
question  
            | highly condensed mitotic chromosome | 
answer 
        | • 30nm fiber must fold even further • fold into large loops, held together by nuclear scaffolding proteins at the base of each loop • then folded again to form condensed chromosome  | 
question  
            | chromosome duplication | 
answer 
        | • associated proteins must be reassembled on each daughter DNA molecule • nucleosomes must be partially dissassembled to allow replication machinery to pass • histone synthesis & modification occurs  | 
question  
            | histone synthesis & modification | 
answer 
        | • H3:H4 tetramers remain bound to one of two daughter DNA duplexes at random • H2A:H2B intact but released into pool of free dimers, surrounding replication fork • H3:H4 tetramers from old nucleosomes form new nucleosomes on daughter DNA after replication fork passes • because amt of DNA doubled, more histones synthesized and recruited • histone chaparones guide to DNA behind replication fork  | 
question  
            | histone chaparones | 
answer 
        | • Asf1 & CAF-1 work together to bring new H3:H4 tetramer to assembly site that didn't get old tetramer, where PCNA ring is • NAP-1 brings two H2A:H2B dimers to each new strand (each gets one old dimer and one new dimer) • histone modifications carefully preserved • essential to survival of each daughter cell  | 
question  
            | PCNA ring | 
answer 
        | • proliferating cell nuclear antigen rings • sliding clamp proteins that tether DNAP to DNA during replication; left on new DNA to serve as markers  | 
question  
            | modified old ; new histones | 
answer 
        | • modified old histones can recruit enzymes that modify nearby new histones in same way • i.e. enzymes w/ bromodomains bind to acetylated histones ; acetylate nearby new histones  | 
question  
            | Why is packing DNA into chromosomes important? | 
answer 
        | • it allows DNA to fit into cell • protects DNA from damage • only packaged DNA can be transmitted to daughter cells • chromosomal DNA very stable (naked DNA not) • chromosome has overall organization to each DNA molecule  | 
question  
            | Why is organization of DNA important? | 
answer 
        | • organization regulates: gene expression ; recombination • recombination btw parental chromosomes - generates diversity seen w/ different individuals of any organism  | 
question  
            | molecular mass of eukaryotic chromosome | 
answer 
        | • half of mass is made up of proteins • most are histones and some are nonhistones  | 
question  
            | chromatin | 
answer 
        | • given region of DNA w/ its associated proteins • these proteins help to compact DNA  | 
question  
            | histones | 
answer 
        | • majority of DNA-associated proteins • small, basic proteins • have high contect of (+) charged amino acids • ; 20% of residues in histones are lysine or arginine  | 
question  
            | nonhistone proteins | 
answer 
        | • include DNA-binding proteins • they regulate transcription, regulation, repair ; recombination of cellular DNA  | 
question  
            | size properties of chromosomes | 
answer 
        | • human cell contains 3x109bp per haploid chromosomes set • avg thickness of each bp = 3.4A • if stretched out = ~1010A or 1m • diploid stretched out = 2m  | 
question  
            | prokaryotic nucleoid | 
answer 
        | • typically only has one complete copy of chromosome packaged into nucleoid • portions of chromosome present in two and sometimes four copies during rapid division  | 
question  
            | plasmids | 
answer 
        | • independent, circular DNA • not essential for bacterial growth • carry genes that confer desirable traits to bacteria (antibiotic resistance, etc)  | 
question  
            | diploid | 
answer 
        | • two copies of each chromosome • most eukaryotic cells are diploid  | 
question  
            | homologs | 
answer 
        | two copies of given chromosome (one from each parent) | 
question  
            | haploid | 
answer 
        | • only single copy of each chromosome • involved in sexual reproduction  | 
question  
            | polyploid | 
answer 
        | • more than two copies of each chromosome • some organisms - majority of adult cells in polyploid state  | 
question  
            | global genome amplification | 
answer 
        | • hundreds or thousands of copies of each chromosome • allows cell to generate larger amts of RNA ; proteins  | 
question  
            | megakaryocytes | 
answer 
        | • specialized polyploid cells • produce thousands platelets that lack chromosomes but essential to human blood (maintains high metabolism)  | 
question  
            | nucleus | 
answer 
        | chromosomes contained w/i membrane-bound organelle | 
question  
            | genome size, number of genes | 
answer 
        | • correlates with organism's complexity • generally though, it's the number of genes, not necessarily genome size • prokaryotic cells have genomes ;10Mb • single-cell eukaryotes ;50Mb • complex protozoans ;200Mb  | 
question  
            | genome density | 
answer 
        | increased complexity = less gene density | 
question  
            | intergenic sequences | 
answer 
        | • decrease gene density • discontinuous, protein-coding regions • takes up more than 60% of human genome • either unique or repeated  | 
question  
            | introns | 
answer 
        | • interspersed non-protein-coding regions • removed from RNA after transcription • 95% of average protein-coding gene (5% actually encodes)  | 
question  
            | RNA splicing | 
answer 
        | removes introns from RNA before translation = mature mRNA | 
question  
            | unique intergenic DNA | 
answer 
        | • 25% of intergenic DNA • regions of DNA required to direct/regulate transcription • nonfunct relics, mutant genes, fragments, pseudogenes, ori's  | 
question  
            | regulatory sequences | 
answer 
        | coordinate gene expression - direct/regulate transcription | 
question  
            | mutant genes & fragments arise from… | 
answer 
        | simple random mutagenesis or errors in DNA recombination | 
question  
            | reverse transcriptase | 
answer 
        | • enzymes that copy RNA into dsDNA used by viruses • where pseudogenes come from  | 
question  
            | miRNAs (microRNAs) | 
answer 
        | • small structural RNAs (maybe >400 in human cells) • regulate expression of other genes by altering stability of product mRNA or ability to be translated  | 
question  
            | repeated DNA | 
answer 
        | • almost half of genome are repeats; two types: • microsatellite DNA • genome-wide repeats  | 
question  
            | microsatellite DNA | 
answer 
        | • very short, tandemly repeated sequences (<13bp; CACACA…) • from difficulties in accurately duplicated DNA • approx 3% of genome  | 
question  
            | genome-wide repeats | 
answer 
        | • much larger than microsatellite (>100bp, can be 1kb) • either as single copies throughout genome or clusters • all forms are transposable elements  | 
question  
            | transposable elements | 
answer 
        | • sequences that can "move" to diff places in genome • they multiply and accumulate throughout genome • rare process in human cells, but now 45% of genome  | 
question  
            | transposition | 
answer 
        | elements move to new position in genome, often leaving original copy behind | 
question  
            | important non-genetic portions of eukaryotic chromosomes | 
answer 
        | • origins of replication: direct duplication of chrom DNA • centromeres: "handles" for movement of chromosomes into daughter cells • telomeres: protect and replicate ends of linear chrom  | 
question  
            | origins of replication | 
answer 
        | • sites where DNA replication machinery assembles to initiate replication • usually 30-40bp apart in eukaryotes • prokaryotes usually only have one ori  | 
question  
            | centromeres | 
answer 
        | • required for correct segregation of chromosomes after replication • they direct formation of elaborate protein complex, kinetochore • each chromosome only has ONE centromere  | 
question  
            | kinetochore | 
answer 
        | interacts w/ centromere DNA and microtubules (protein filaments) that pull sister chromosomes away from each other into two daughter cells | 
question  
            | telomeres | 
answer 
        | located at the two ends of linear chromosome, bound by several proteins • proteins distinguish natural ends of chromosome from sites of chromosome breakage & other DNA breaks • act as specialized origin of replication - allows cell to replicate ends of chromosomes (recruits telomerase) • portion is in single-strand form and usually TG rich  | 
question  
            | telomerase | 
answer 
        | telomeres recruit this DNAP to faciliate end replication • during replication, lagging strand synthesized as short fragments (okazaki) --> RNAP removed by RNAse H, filled in by DNAPs, then ligated by DNA ligase • DNAP only able to add to 3' end - even if primase able to synthesize, DNAP cannot replicate DNA when primer removed = short region of unreplicated ssDNA left at end of chromosome • incomplete sections = end replication problem  | 
question  
            | end replication problem | 
answer 
        | • incomplete replication of 3' terminus of template DNA caused by exclusive 3' to 5' activity of DNAP • unreplicated ssDNA leads to loss of genes • ends of euk chromosomes called telomeres (GT rich repeats) - 3' end extends past 5' end • most euk use telomerase = protein + RNA (1.5 copies of compliment of telomeric sequence 3'-UAACCCUAA-5') • telomerase extends 3' end of telomere - does not need template; telomeric RNA serves as template • can be repeated many times, extending 3' end of chromosome • DNA replication machinery then extends 5' end of telomere • DNAP still cannot extend all the way to end of 5' • telomeric repeats protect by acting as buffer as non-coding DNA & proteins protects degregation of chromosomes  | 
question  
            | chromosome structure changes | 
answer 
        | ?after cell division occurs, chromosome structure altered many times; two states ® • interphase (chromosome decondensation) • M phase (chromosome condensation)  | 
question  
            | SMC (structural maintenance of chromosome) proteins | 
answer 
        | • form defined pairs by interacting through lengthy coiled-coil domains ® • cohesin & condensin • w/ non-SMC proteins, they form multiprotein complexes that link two DNA helices together • cohesion links sister chromatids together • condensin ring w/i individual chromosomes = tigher pack  | 
question  
            | meiosis (2nd half of euk cell division) | 
answer 
        | • specialized to produce cells w/ 1/2 # chrom than parent • follows DNA replication w/ 2 rounds of chrom segregation • Metaphase I, Anaphase I • Metaphase II, Anaphase II ® four gametes (or spores) • elongated G2 phase • monovalent attachment occurs in metaphase I • bivalent occurs in metaphase II  | 
question  
            | meiosis I | 
answer 
        | • homologous sister chromatids pair ® 4 chromosomes • chromatids from diff homologs recombine to form link btw homologous chroms ® chiasma • during metaphase I, two kinetochores from each pair attach to opposite poles (each monovalent)  | 
question  
            | meiosis II | 
answer 
        | like mitosis but instead of splitting chromatid pair into 2 cells, 2 sets of 4 chroms split into 4 cells ® dsDNA in each cell | 
question  
            | core DNA | 
answer 
        | DNA btw each nucleosome ("beads on a string") | 
question  
            | linker DNA | 
answer 
        | • DNA most tightly associated w/ nucleosome • typically only 20-60bp long (diff's from larger structures)  | 
question  
            | nucleosome-free DNA | 
answer 
        | typically associated w/ non-histone proteins for gene expression, replication, recombination | 
question  
            | histone-fold domain | 
answer 
        | • mediates assembly of histone-only intermediates ; formation of head-to-tail heterodimers of specific histone pairs • w/o DNA, core histones form intermediate assemblies in solution • fold-domain is conserved region in each core histone, w/ 3 a-helical regions separated by 2 short, unstructured loops • H3 ; H4 form heterodimers, then together forms tetramer • H2A ; H2B stay as heterodimers  | 
question  
            | histone tails | 
answer 
        | • sites of extensive mods that alter fxn of indiv. nucleosomes • includes methylation, phosphorylation, acetylation • protease cleaves the tails, leaving histones intact  | 
question  
            | dyad axis | 
answer 
        | approximate twofold axis of symmetry in nucleosomes | 
question  
            | DNA Polymerization | 
answer 
        | • DNAP is enzyme that catalyzes synthesis of new DNA • 3 Domains: Palm, Finger, Thumb  | 
question  
            | DNA Synthesis | 
answer 
        | • Two things needed for DNA synthesis ® • dNTPs (deoxynucleoside triphosphates) • primer:template junction • each of 4 dNTPs have 3 phosphoryl groups attached to 5' OH of 2' deoxyribose (named a, b, and g phosphates)  | 
question  
            | primer:template junction | 
answer 
        | • primer template junction has two components ® • template provides ssDNA to be copied • primer provides free 3' OH at growing end of DNA • 3'OH of primer attacks a-phosphoryl of incoming dNTP • leaving group is pyrophosphate w/ b and g • pyrophosphate (rapid) hydrolysis by pyrophosphatase provides additional free energy to drive reaction into two phosphate groups (b and g) • process can be repeated w/ 3' OH of new dNTP as nucleophile • chemistry requires that DNA be made in polar fashion (extending 3' end of primer strand, so 5' ® 3') • template strand directs what dNTP is added  | 
question  
            | DNAP Domains | 
answer 
        | • Palm: active site for DNA • correct bp important for catalysis reaction to continue • Also binds 2 divalent metal ions for DNA polym activity • once correct bp formed, finger encloses dNTP • conformational change brings dNTP and primer into correct orientation w/ metal ions  | 
question  
            | Palm Domain | 
answer 
        | • recognizes dNTPs vs rNTPs (even though rNTPs more) • it can sterically disclude rNTP's because w/ 2'OH, it's too small to fit  | 
question  
            | Finger Domain | 
answer 
        | • metal ion A deprotonate 3'OH of primer, producing oxyanion to attack a-phosphate of incoming dNTP • metal ion B coordinates (-) charges of b and g phosphates of dNTP ; stabilizes pyrophosphate leaving group • Finger residues also help to ® • Lys ; Arg stabilize pyrophosphate • Via stacking interactions, Tyr helps hold dNTP in place for catalysis • Finger Domain also associates w/ template, turns it 90o to avoid confusion of template vs. primer in palm's active site • only single template base in active site so palm knows what base to add to primer next  | 
question  
            | Proofreading (in palm domain) | 
answer 
        | • it hydrogen bonds to base pairs in minor groove of new DNA • h-bonds only form if nucleotides correctly base paired • if mismatched bp added, replication rate slows • primer template free to move around exonuclease site • exo site removes incorrect bp from 3' DNA end site backwards • primer:template slides back to DNA replication site  | 
question  
            | Thumb Domain | 
answer 
        | • no interaction w/ catalysis process • interacts w/ DNA most recently synthesized • reduces rate of dissociation btw junction ; DNAP • holds primer:template junction in active site  | 
question  
            | DNA replication | 
answer 
        | • Parental DNA copied to form two daughter DNA molecules • leading strand: pulled to right, copied continuously • lagging strand: copied backwards, discontinous, okazaki fragments; 100-1000bp in length  | 
question  
            | Lagging strand | 
answer 
        | • DNAP has to add to 3' end of lagging, opposite of leading • therefore, DNAP must move opposite direction, only adding discontinuously in small fragments • short fragments are okazaki fragments (100-1000bps)  | 
question  
            | DNA helicases | 
answer 
        | • Parental DNA must be copied into two daughter • enzymes that couple ATP hydrolysis to separation of DNA • hexameric proteins in shape of ring • junction btw new separated template strand & unreplicated dsDNA called replication fork • moves continuously through unreplicated dsDNA  | 
question  
            | SSBs (single-stranded DNA binding proteins) | 
answer 
        | • bind to ssDNA to stabilize separated strands | 
question  
            | topoisomerases | 
answer 
        | • as DNA unwinds, twist number decreases • write number increases = (+) supercoiled DNA • Topo's remove (+) supercoils = (-) supercoil  | 
question  
            | primase | 
answer 
        | • specialized RNAP that makes short RNA primers using ssDNA as template • DNA primase activated by interacting w/ DNA helicase  | 
question  
            | DNA polymerazes (DNAPs) | 
answer 
        | • synthesis of DNA catalyzed by DNAP • can only add dNTPs to 3' OH of polynucleotide • bcz DNA antiparallel, one strand synthesized continuously towards repl fork, other is synthesized discontinously away from repl fork • takes 1 second for DNAP to bind to DNA • can add up to 1000 nucleotide bases per second  | 
question  
            | processivity | 
answer 
        | ability of an enzyme to catalyze reactions before releasing substrate | 
question  
            | sliding DNA clamps | 
answer 
        | • binds to DNAP, holding DNAP & DNA together • surrounds DNA to increase processivity of DNAP  | 
question  
            | RNAse H | 
answer 
        | • To complete replication, RNA primers must be removed  • RNAse H degrades RNA bp'd to DNA (H = hybrid for RNA:DNA) • single ribonucleotide directly linked to DNA removed by exonuclease (changes based on euk vs. prok) • single-strand gaps left behind by RNAse H are filled in by DNAP's  | 
question  
            | DNA ligase | 
answer 
        | • nicks btw 3'OH of repair section and 5' phos of replicated section repaired by DNA ligase | 
question  
            | Prokaryote Replication | 
answer 
        | • two DNAP's to replicate leading/lagging strands often linked in holoenzymes • trombone model? ssDNA template on lagging pulls through DNAP, allowing DNAP to add nucleotides to 3' end of growing strand • sliding clamps act as loaders - help DNAP to find primed DNA  | 
question  
            | Holoenzyme | 
answer 
        | multi-protein complex where core enzyme activity (i.e. DNAP) associated w/ additional components that enhance function | 
question  
            | Semi-Conservative Replication | 
answer 
        | in each new DNA double helix, one strand is from the original molecule, and one strand is new | 
question  
            | Where does prokaryotic replication take place? | 
answer 
        | In the cytoplasm | 
question  
            | Where does eukaryotic replication take place? | 
answer 
        | In the nucleus during S phase of the cell cycle | 
question  
            | What is the purpose of DNA replication? | 
answer 
        | Duplicate chromosomes, so that after mitosis each daughter cell will inherit a complete genome | 
question  
            | In what type of cells does DNA replication occur? | 
answer 
        | In dividing cells only; non-dividing cells are blocked in G0 and do not progress into S phase, so they do not replicate their DNA | 
question  
            | What are the requirements for DNA replication? | 
answer 
        | DNA polymerase, Mg2+, template, primer, and dNTPs | 
question  
            | In what direction does DNA replication occur? | 
answer 
        | 5` ® 3` direction | 
question  
            | What does complementarity mean? | 
answer 
        | For each A on the template strand, there is a corresponding T added to the new strand. The same applies for a G on the template strand. A corresponding C is added to the new strand | 
question  
            | What enzyme is reponsible for removing mismatched nucleotides? | 
answer 
        | 3`®5` exonuclease | 
question  
            | Bidirectional means? | 
answer 
        | Replication proceeds in both directions from central origins of replication (ori) | 
question  
            | The type of replication in which the lagging strand is synthesized | 
answer 
        | Discontinuous replication | 
question  
            | DNA in a newly synthesized daughter chromosome contains one new strand and one template strand. This is known as? | 
answer 
        | Semiconservative replication | 
question  
            | DNA polymerase does what? | 
answer 
        | It is an enzyme that catalyzes the polymerization of dNTPs into DNA | 
question  
            | How many types of DNA polymerases do prokaryotes have? | 
answer 
        | I, II, and III | 
question  
            | What are the different types of DNA polymerases in eukaryotes? | 
answer 
        | Pol-delta, pol-alpha, pol-beta, pol-gamma | 
question  
            | Pol-delta: location, function, processivity, proofreading, use of RNA primer | 
answer 
        | • Location: nucleus; function: leading strand synthesis • processivity: >100,000 bp; proofread: yes; use RNA primer: yes  | 
question  
            | Pol-alpha: location, function, processivity, proofreading, use of RNA primer | 
answer 
        | • Location: nucleus; function: lagging strand synthesis • processivity: ~180 bp; proofreading: no; use RNA primer: yes  | 
question  
            | Pol-beta: location, function, processivity, proofreading, use of RNA primer | 
answer 
        | • Location: nucleus; function: fill in gaps for repair;  • processivity: ~20 bp; proofreading: no; use RNA primer: no  | 
question  
            | Pol-gamma: location, function, processivity, proofreading, use of RNA primer | 
answer 
        | • Location: mitochondria; function: synthesis of both strands • processivity: ~8,300 bp; proofread: yes; use RNA primer: no  | 
question  
            | The cofactor that is required for DNA polymerase activity? | 
answer 
        | Mg2+ | 
question  
            | The pre-existing strand read by DNA polymerase is known as? | 
answer 
        | The template strand | 
question  
            | What are the building blocks of DNA? | 
answer 
        | dNTPs (deoxynucleotides) = dCTP, TTP, dGTP, dATP | 
question  
            | What is significant about dNTPs? | 
answer 
        | They lack a 2` hydroxyl group | 
question  
            | How is thymine different from uridine? Where is uridine used? | 
answer 
        | It is methylated at the 5` position; uridine is used for RNA | 
question  
            | Where does nucleotide polymerization get its energy from? How is this energy stored? | 
answer 
        | Hydrolysis of triphosphate bonds; energy stored in triphos bonds as electrostatic repulsion of negatively charged O2s | 
question  
            | T/F: DNA polymerase can bind a 5` phosphate with an incoming 3` -OH? | 
answer 
        | F; DNA polymerase can only bind a 3` -OH with a 5` phosphate of an incoming nucleotide | 
question  
            | What is a primer? | 
answer 
        | It is a strand with a free 3` -OH group; DNA polymerase can only bind a 3` -OH with a 5` phosphate of an incoming nucleotide | 
question  
            | What direction does DNA synthesis proceed in? | 
answer 
        | 5` ® 3` | 
question  
            | What direction is the template strand oriented? | 
answer 
        | 3` ® 5`; it is antiparallel to the newly synthesizing strand | 
question  
            | Which DNA polymerases have the ability to proofread and determine if the new nucleotide is complementary to the corresponding base of the template? | 
answer 
        | Pol-delta and pol-gamma | 
question  
            | What happens if an incorrect nucleotide is incorporated? | 
answer 
        | The polymerase's 3`-5` exonuclease activity "kicks back", excising the mismatch; pol-alpha and pol-beta lack this activity | 
question  
            | The leading strand | 
answer 
        | Continuously synthesized in the 5` - 3` direction | 
question  
            | The lagging strand | 
answer 
        | • The opposite strand synthesized;  • antiparallel to leading strand • discontinuously synthesized in 5`® 3` direction • stretches known as Okazaki fragments  | 
question  
            | How long are Okazaki fragments? | 
answer 
        | 100-200 bp | 
question  
            | What does semiconservative mean? | 
answer 
        | It means that each chromatid receives one de nova and one parental strand; DNA replication is always semiconservative, never conservative nor non-conservative | 
question  
            | What is the origin of replication (ori)? | 
answer 
        | It is the sequence where DNA replication begins | 
question  
            | How many ori's do prokaryotic chromosomes have? How many do eukaryotic chromosomes have? | 
answer 
        | Prokaryotes = 1 ori per chromosome; eukaryotes = multiple ori per chromosome | 
question  
            | What is the general procedure of DNA replication? | 
answer 
        | Factors recognize and bind specific ori sequence, unwind DNA, attract components of replication apparatus, apparatus moves down chromosome (away from ori), replicate DNA as it goes; DNA replication is bidirectional, two apparatuses assemble around ori | 
question  
            | What is a replicon? What is their average length? | 
answer 
        | Region of eukaryotic chromosome that is replicated as unit, from one central ori; length about 200 kb (this is about the length of DNA loops anchored to scaffold proteins, suggesting these proteins may be involved in defining replicon length) | 
question  
            | Why is it a benefit to have multiple replicons? | 
answer 
        | So that different regions of the genome can be replicated simultaneously; replication begins at the ori in the center of the replicon and extends in both directions until it reaches the end of an adjacent replicon | 
question  
            | What is the purpose of helicase? | 
answer 
        | Enzyme that unwinds DNA; one of the first factors to bind ori; serves to open double helix so DNA polymerase can replicate strands; is part of replication apparatus | 
question  
            | What are single stranded bindng proteins (SSB)? | 
answer 
        | Factors that stabilize single stranded DNA by preventing it from winding back into double helix | 
question  
            | What does the DNA replication apparatus consist of? | 
answer 
        | Helicase, DNA polymerase-delta, pol-alpha, beta-clamp, and primase; two apparatuses assemble, one on each side of the ori, and each moves in the oppostie directions, replicating DNA as they go | 
question  
            | What does the beta-clamp do? | 
answer 
        | Ring-like protein that wraps around DNA to stabilize association of replication apparatus; required for pol-delta processivity; without clamp = pol-delta only replicates short oligonucleotides (< 200 bp), with clamp = stretches > 100 kb are produced | 
question  
            | Strand that is continuously synthesized, in the 5`-3` direction? | 
answer 
        | Leading strand | 
question  
            | What is DNA polymerase-delta? | 
answer 
        | Enzyme that replicates leading strand, reads template one base at a time, incorporates complementary nucleotides and ligates their 5` phosphate to the 3` -OH of the growing strand | 
question  
            | What is the overall synthesis of the lagging strand? How is its synthesis overcome? | 
answer 
        | Overall synthesis is in the 3`-5` direction (wrong direction); its synthesis is overcome by synthesizing discontinuous short stretches called Okazaki fragments | 
question  
            | What does primase do? | 
answer 
        | Enzyme that binds unwound lagging strand and transcribes short stretches of RNA (< 15 bp); RNA serves as primer, providing 3` -OH group required by pol-alpha | 
question  
            | What is the purpose of DNA polymerase-alpha? | 
answer 
        | Enzyme uses RNA primer to synthesize Okazaki fragments of the lagging strand; NO proofreading ability; only synthesizes one fragment at a time while helicase contiues to unwind DNA for next fragment, so lagging strand held in loop | 
question  
            | What happens when pol-alpha reaches a primer at the end of a previous fragment? | 
answer 
        | Lagging strand is released, primase makes next primer at end of new single stranded region, process is repeated | 
question  
            | What are the three enzymes involved with removal of RNA primers from the lagging strand? | 
answer 
        | RNAase, DNA polymerase-beta, DNA ligase | 
question  
            | What does RNAase do? | 
answer 
        | This enzyme digests any RNA; in replication it serves to remove lagging strand primers | 
question  
            | What does DNA polymerase-beta do? | 
answer 
        | It fills in the gaps in DNA (~ 20 bp); in replication it fills in the gaps left after RNA primers are removed; N.B. = DNA polymerases can only add nucleotides, they cannot link DNA fragments (pol-beta leaves nicks in DNA) | 
question  
            | What does DNA ligase do? | 
answer 
        | Enzyme that binds any free 3` -OH and 5` phosphates of DNA; in replication it seals the nicks between Okazaki fragments left by pol-beta | 
question  
            | What happens as a result of helicase unwinding? What enzyme helps fix the problem? | 
answer 
        | Supercoiling increases; topoisomerases helps to restore DNA to its proper level of supercoiling | 
question  
            | What happens when the last RNA primer is removed from the end of the chromosome? | 
answer 
        | It leaves an overhang that cannot be filled by DNA polymerase; if this didn't get resolved, then every time dividing cells replicated their DNA, the lagging strands would lose a bit of their telomeric sequence, leading to chromosomal destabilization | 
question  
            | What enzyme is responsible for filling in the gap left when the last RNA primer is removed? | 
answer 
        | Telomerase (it is a type of reverse transcriptase) - it fills in the gaps as well as extends the length of the telomere | 
question  
            | What are some interesting facts about telomerase? | 
answer 
        | Activity and length decreases with age; primary cell culture lines have no telomerase activity; immortalized cell culture lines divide indefinitely b/c of activated telomerase; activated in cancer cells and believed to contribute to immortalization | 
question  
            | Where is gene expression controlled? | 
answer 
        | Pre-transcriptional, transcriptional, post-transcriptional, translational, and post-translational levels | 
question  
            | DNA replication must be these three thing | 
answer 
        | • high fidelity (but need mutations) • highly processive • relatively fast  | 
question  
            | Semiconservative replication | 
answer 
        | • both strands get a new stand • this is the correct method  | 
question  
            | conservative replication | 
answer 
        | • both strands stay connected and a new one is created | 
question  
            | dispersive replication | 
answer 
        | • random pieces are kept and others are replaced | 
question  
            | Meselson and Stahl experiment | 
answer 
        | • demonstradted semiconservative • applied CsCl gradient ultracenterfugation of DNA labeled with Heavy Nitrogen (15N) • cells moved to growth medium containing normal N (14N) • DNA was isolated at different times • pictures taken during centerfugation • found old strand of heavy DNA with new strand of light DNA  | 
question  
            | continuous replication | 
answer 
        | both strands serve as templates in the same compass direction one would do 3'®5' and hte other would do 5'®3'  | 
question  
            | semidiscontinuous replication | 
answer 
        | same as continuous, but broken up into bursts on the same double strand | 
question  
            | discontinous replication | 
answer 
        | fragmented on both parent strands | 
question  
            | Okazaki proposed | 
answer 
        | • proposed that DNA polymerase can make one strand of DNA continously 5'®3' (leading strand) • but the other strand would be discontinous in 5'®3' (lagging strand)  | 
question  
            | Okazaki's model had two experimentally testable predictions | 
answer 
        | • if short pieces of DNA are synthesized on lagging strand, should be able to catch w/ radiolabeling • if the enzyme DNA ligase is eliminated from the replication process, then short pieces of DNA made should be detectable even at longer labeling periods  | 
question  
            | Okazaki's experiment | 
answer 
        | • used T4 phage mutant that made Ligase • control - found short pieces for short periods of time before they were ligased together • using the T4 mutant - tons of short pieces as time increased  | 
question  
            | DNA replication is _____ with DNA synthesis occuring ____ at ____ _____ ____ | 
answer 
        | • bidirectional • simultaneously • 2 replication forks  | 
question  
            | specific location where replication starts | 
answer 
        | • oriC • contains 4 9-mers having consensus sequence of TTATCCACA  | 
question  
            | helicase | 
answer 
        | • an ATP-dependent enzyme that separates the DNA strands in advance of the replication fork • the dnaB gene product in E.coli  | 
question  
            | Single-Stranded DNA-Binding Proteins | 
answer 
        | • bind to ssDNA and prevent it from reforming dsDNA • product of ssb gene of E.coli • the bonding is cooperative - raises affinity by 1,000 fold for next molecule • stimulate replication  | 
question  
            | Topoisomerase | 
answer 
        | • as the DNA unwinds, it has to wind somewhere upstream, creates strain • topoisomerase releaves this strain by introducing temporary single- (Type I) or double-stranded (Type II) breaks in the DNA  | 
question  
            | DNA gyrase | 
answer 
        | • from E. coli • type II topoisomerase  | 
question  
            | DNA Polymerases found in E. coli | 
answer 
        | • Polymerase I - DNA repair, primer excision • Polymerase II - SOS repair • Polymerase III - required for DNA replication in E.coli  | 
question  
            | Holoenzyme polymerase III subunits (aka: pol III holoenzyme) | 
answer 
        | • composed of multiple subunits • The ?-subunit has the DNA polymerase activity • The ?-subunit has the 3’ a 5’ exonuclease proofreading activity • The ?-subunit has the ???? activity. The function is still unknown  | 
question  
            | eukaryotic DNA polymerases | 
answer 
        | • DNA polymerase ? (priming) • DNA polymerase ? (elongation) • DNA polymerase ? (repair) • DNA polymerase ? (repair) • DNA polymerase ? (mitochondrial)  | 
question  
            | DNA replication can be divided into 3 major events | 
answer 
        | • initiation ® elongation ® termination | 
question  
            | initation of replication - purpose of dnaA | 
answer 
        | • binds at the oriC • facilitates the binding of dnaB • stimulates melting of the 3 13-mer repeats at one end of the oriC to make an opening  | 
question  
            | initiation of replication - purpose of dnaB | 
answer 
        | • required for protein synthesis • dnaC binds to dnaB • stimulates binding of the primase • also serves as the helicase that moves 5'®3' on the lagging strand in the direction of the replication fork  | 
question  
            | initiation of replication - two other factors for open complex formation at oriC | 
answer 
        | • RNA polymerase which synthesizes a short piece of RNA that creates an R loop • helix unwinding (HU) protein which induces bending  | 
question  
            | Initiation of replication - primase | 
answer 
        | • product of the dnaG • its the RNA primer-synthesizing enzyme  | 
question  
            | initiation of replication - Primase (dnaG) + dnaB = | 
answer 
        | • primosome • this is responsible for laying down multiple primers for Okazaki fragments on the lagging strand  | 
question  
            | how eukaryotes handle initiation | 
answer 
        | • multiple sites of replication for each chromosome | 
question  
            | elongation - why pol III holoenzyme is highly processive | 
answer 
        | • due to the sliding clamp • its the ?-subunit of the holoenzyme • literally holds the entire pol III assembly on the template for long periods  | 
question  
            | elongation - group of protein required for the sliding clamp | 
answer 
        | • the ?-complex • sliding clamp cannot touch the DNA by itself • serves as the clamp loader and is ATP-dependent  | 
question  
            | elongation - eukaryotes version of the sliding clamp | 
answer 
        | • processivity factor PCNA • PCNA = proliferating cell nuclear antigen • forms a trimer (3 subunits) that can encircle the DNA as the bacterial clamp does  | 
question  
            | elongation - pol III holoenzyme | 
answer 
        | • contains two core polymerases - one for each strand • as it finishes one Okazaki fragment, it runs into a nick that is positioned in front of the primer on the next fragment • this nick is a cue for the complex to dissociate from the and move to the primer on the next fragment  | 
question  
            | termination - the _____ region | 
answer 
        | • terminus • where the replication forks begin to get near each other • contains 22bp sites that bind specific proteins called TUS proteins • replication forks stop moving when they get to this region • leaves the daughter couples entangled  | 
question  
            | TUS proteins | 
answer 
        | • terminus utilization substance | 
question  
            | termination - when circular DNAs are interlocked (entangled), the structure is called ________ | 
answer 
        | • a catenate | 
question  
            | termination - Decatenation | 
answer 
        | • process of untangling the interlocking DNA rings • performed by topoisomerase IV  | 
question  
            | eukaryotes' termination problems | 
answer 
        | • there are gaps left when RNA primers are removed • this is problematic because when the primer is removed DNA cannot be extended in the 3'-->5' direction • and there's no 3' upstream • so DNA should be getting shorter…  | 
question  
            | terminaton ends - which is which | 
answer 
        | • TTGGGG - Tetrahymena • TTAGGG - vertebrates  | 
question  
            | Hayflick Limit | 
answer 
        | • Hayflick (1960s) showed that normal animal cell lines are not immortal • grow in cultures of about 50 generations, then enter senescence • cancer cells do not have this limit (contain telomerase as do egg and sperm production cells)  |