Organic Chemistry Final – Flashcards
Unlock all answers in this set
Unlock answersquestion
| Alkyne has a BLANK bond |
answer
| Triple |
question
| Alkene has a BLANK bond |
answer
| Double |
question
| Alkyne + H2 & metal (Pt or Pd) |
answer
| Triple bond becomes single bond |
question
| Alkyne + H2 + Lindlar's catalyst |
answer
| Triple bond becomes cis double bond |
question
| Alkyne + H2 + Ni2B |
answer
| Triple bond becomes cis double bond |
question
| Alkyne + Na2 & NH3 (l) |
answer
| Triple bond becomes trans double bond |
question
| A more stable base corresponds with a BLANK acid |
answer
| Strong |
question
| A more stable base means that the base is BLANK (strong or weak) |
answer
| Weak |
question
| A BLANK (strong or weak) base will deprotonate a terminal alkyne |
answer
| Strong |
question
| A BLANK (strong or weak) base will not deprotonate a terminal alkyne |
answer
| Weak |
question
| Alkyne + H2SO4, H2O, & HgSO4 |
answer
| Triple bond becomes a single bond and double bonded oxygen on the more substituted position |
question
| Alkyne + excess (xs) HX |
answer
| Triple bond becomes a single bond with two Xs bonded to the more substituted position |
question
| Alkyne + HX |
answer
| Triple bond becomes a double bond with X bonded to the more substituted hindered side |
question
| Alkyne + xs X2 & CCl4 |
answer
| Triple bond becomes a single bond with 2 X's bonded at each end (total of 4) |
question
| Alkyne + RX (Ex: MeI) |
answer
| R is added to to open side of triple bond |
question
| Alkyne + 9-BBN, H2O2 & NaOH |
answer
| Triple bond becomes a single bond and a double bonded O at the less substituted position |
question
| Alkyne + Disiamylborane, H2O2, and NaOH |
answer
| Triple bond becomes a single bond and a double bonded oxygen on the less substituted side |
question
| Alkyne + O3 & H2O |
answer
| Oxidative cleavage: Triple bond becomes a double bonded oxygen and a single bonded OH x2 for each new molecule |
question
| Terminal alkyne + O3 &H2O |
answer
| Oxidative cleavage: Triple bond becomes a double bonded oxygen and a single bonded OH, and CO2 |
question
| Enol |
answer
| Molecule with a C=C double bond alyllically located to an alcohol; very stable |
question
| Ketone |
answer
| Oxygen double bonded to a carbon with an R on each side (resonance-stabilized enol) |
question
| Aldehyde |
answer
| An oxygen double bonded to a carbon with an H on one side and an R on the other |
question
| Alkyne + X2 & CCl4 |
answer
| Triple bond becomes a double bond with an X bonded to each side (trans) |
question
| Internal alkyne + NaNH2, NH3 (l) and H2O |
answer
| Terminal alkyne |
question
| Vinylic position |
answer
| One of the carbons in a C=C double bond |
question
| Allylic position |
answer
| Attached to one of the carbons in a C=C double bond |
question
| Hydrogen abstraction |
answer
| A form of radical inhibition in which hydroquinone donates a hydrogen to destroy a radical and resonance stabilizes itself and then destroys another radical by donating a hydrogen again |
question
| Hydrogen abstraction |
answer
| A form of radical inhibition in which hydroquinone donates a hydrogen to destroy a radical and resonance stabilizes itself and then destroys another radical by donating a hydrogen again |
question
| delta H must be (+ or -) for the halogenation of an alkane |
answer
| - |
question
| Delta G must be (+ or -) for a reaction to occur |
answer
| - |
question
| Which is a slower process, bromination or chlorination? And why? |
answer
| Bromination due to a higher activation energy |
question
| When an alkane is chorinated, the Cl is attached at the BLANK position |
answer
| 60% the more substituted position, 40% the less substituted position |
question
| When an alkane is brominated, the Br is attached at the BLANK position |
answer
| More substituted position |
question
| How to determine acid/base strength |
answer
| ARIO |
question
| Pattern of base stability in the periodic table |
answer
| Increasing to the right, increasing as you go down |
question
| Induction effects on base strength |
answer
| Weaker/stabler when negative atoms provide inductive effects |
question
| A negative charge on a triple bond is more or less stable than on a single bond? |
answer
| More stable |
question
| Which is a weaker base, methyl oxide or ethyl oxide? And why? |
answer
| Methyl oxide because methyl donates less electrons to the oxygen than ethyl |
question
| Z designates the top priority atoms to be on the (same or opposite) side(s) of a double bond |
answer
| Same |
question
| E designates the top priority atoms to be on the (same or opposite) side(s) of a double bond |
answer
| Opposite |
question
| Cis double bonds are more or less stable than trans? |
answer
| Less |
question
| Alkene stability can be determined by |
answer
| The number of substiuents on the double bond |
question
| Mechanism for primary carbocation treated with a nucleophile |
answer
| SN2 |
question
| Mechanism for secondary carbocation treated with a nucleophile |
answer
| SN2 & SN1 |
question
| Mechanism for tertiary carbocation treated with a nucleophile |
answer
| SN1 |
question
| Mechanism for a primary carbocation treated with a strong base |
answer
| E2 |
question
| Mechanism for a secondary carbocation treated with a strong base |
answer
| E2 |
question
| Mechanism for a tertiary carbocation treated with a strong base |
answer
| E2 |
question
| Mechanism for a primary carbocation treated with a strong nucleophile/strong base |
answer
| SN2 (and minor E2) |
question
| Mechanism for a secondary carbocation treated with a strong nucleophile/strong base |
answer
| E2 (and minor SN2) |
question
| Mechanism for a tertiary carbocation treated with a strong nucleophile/strong base |
answer
| E2 |
question
| Mechanism for a primary carbocation treated with a weak nucleophile/weak base |
answer
| N/A |
question
| Mechanism for a secondary carbocation treated with a weak nucleophile/weak base |
answer
| N/A |
question
| Mechanism for a tertiary carbocation treated with a weak nucleophile/weak base |
answer
| SN1 and E1 (high temperature favors E1) |
question
| Reagents that are nucleophile only (7) |
answer
| Cl-,Br-,I-, HS-,H2S, RS-,RSH |
question
| Cl-,Br-,I-, HS-,H2S, RS-,RSH |
answer
| Reagents that are nucleophile only |
question
| Reagents that are base only (3) |
answer
| H-,DBN, DBU |
question
| H-,DBN, DBU |
answer
| Reagents that are base only |
question
| Reagents that are strong nucleophiles/strong bases (4) |
answer
| OH-, MeO-, EtO-, T-BuOK |
question
| OH-, MeO-, EtO-, T-BuOK |
answer
| Reagents that are strong nucleophiles/strong bases |
question
| Reagents that act as weak nucleophiles/weak bases (3) |
answer
| H2O, MeOH, and EtOH |
question
| H2O, MeOH, and EtOH |
answer
| Reagents that act as weak nucleophiles/weak bases |
question
| Configuration of SN2 |
answer
| Inversion (back-side attack) |
question
| Rate of SN2 |
answer
| =k[substrate][nucleophile] |
question
| Which is concerted, SN2 or SN1? |
answer
| SN2 |
question
| Carbocation reactivity of SN2 |
answer
| Primary > Tertiary |
question
| Configuration of SN1 |
answer
| Racemic mixture of inversion and retention |
question
| Reactivity of SN1 |
answer
| Tertiary > Primary |
question
| (z) |
answer
| High priority groups on the same side of a double bond |
question
| (e) |
answer
| High priority groups on opposite sides of a double bond |
question
| Is cis more or less stable than trans |
answer
| More stable |
question
| Reactivity of E2 |
answer
| Tertiary > Primary |
question
| E2 mechanism: Double bond in more or less substituted position? |
answer
| With reagents that are not sterically hindered (OH, MeO, and EtO) the double bond is placed in the more substituted position. With t-BuOK, the double bond is placed in the less substituted position. |
question
| Reactivity of E1 |
answer
| Tertiary > Primary |
question
| E1 mechanism: Double bond in more or less substituted position? |
answer
| Major product is always the more substituted position |
question
| Alkene + HX |
answer
| Double bond becomes single bond with X bonded to the more substituted position |
question
| Alkene + HX & ROOR |
answer
| Double bond becomes single bond with X bonded to the less substituted position |
question
| Markovinikov position |
answer
| X placed in more substituted position |
question
| Anti-Markovnikov position |
answer
| X placed in less substituted position |
question
| Zaitsev product |
answer
| Double bond formed in more substituted position |
question
| Hofmann product |
answer
| Double bond formed in less substituted position |
question
| Configuration/stereochemistry of HX addition to an alkene |
answer
| Racemic mixture of R and S |
question
| Alkene + H3O+ |
answer
| Double bond becomes a single bond and an OH is bonded to the more substituted side |
question
| Stereochemistry (configuration) of acid-catalyzed hydration |
answer
| Racemic mixture of R & S |
question
| Difference between acid-catalyzed hydration and oxymercation-demurcation? |
answer
| Acid catalyzed hydration can undergo carbocation rearrangements, while oxymercation-demurcation cannot |
question
| Alkene + Hg(OAc)2, H2O, & NaBH4 |
answer
| Double bond becomes a single bond and an OH is bonded to the more substituted position (with no rearrangement!) |
question
| Alkene + BH3*THF & H2O2, NaOH |
answer
| Double bond becomes a single bond with an OH bonded to the less substituted position (with no carbocation rearrangement!) |
question
| Syn addition |
answer
| Two atoms are added to the same side of a molecule (dashed and dashed, or wedge and wedge) |
question
| Anti addition |
answer
| Two atoms are added to opposite sides of a molecule (dashed and wedge) |
question
| Is hydroboration-oxidation (BH3, THF, H2O2, NaOH) syn or anti? |
answer
| Syn |
question
| Alkene + H2 & Pt |
answer
| Double bond becomes a single bond |
question
| Is catalytic hydrogenation syn or anti? |
answer
| Syn |
question
| Alkene + H2 & Wilkinson's catalyst |
answer
| Double bond becomes a single bond with syn addition of H's |
question
| Alkene + H2 & BINAP |
answer
| Double bond becomes a single bond with anti addition of H's |
question
| Alkene + X2 |
answer
| Double bond becomes a single bond with an anti addition of an X on each side |
question
| Does halogenation (X2) occur via syn or anti addition? |
answer
| Anti |
question
| Alkene + X2 & H2O |
answer
| Double bond becomes a single bond and an OH is placed at the more substituted position and an X is placed at the other side (anti-addition) |
question
| Does halohydrin formation occur via syn or anti addition? |
answer
| Anti |
question
| Alkene + MCPBA & H3O+ |
answer
| Double bond becomes a single bond with an anti addition of OH on each side |
question
| Alkene + OsO4, NaHSO3 & H2O |
answer
| Double bond becomes a single bond with a syn addition of OH on each side |
question
| Alkene + KnO4, NaOH & cold |
answer
| Double bond becomes a single bond with a syn addition of OH on each side |
question
| Alkene + O3 & DMS |
answer
| Double bond is cleaved into two C=O double bonds |
question
| Use of TsCl & Py? |
answer
| Reagents used before an EN1 reaction if the leaving group is an OH |
question
| How to convert an alkene to an alkyne |
answer
| 1) Br2, CCl4 2) xs NaNH2, H2O |
question
| Lowest energy conformation of cyclohexane |
answer
| Chair |
question
| Highest energy conformation of cyclohexane |
answer
| Half-chair |
question
| Second highest energy conformation of cyclohexane |
answer
| Boat |
question
| Second lowest energy conformation of cyclohexane |
answer
| Twist-boat |
question
| Which substituent is more stable: axial or equatorial? |
answer
| Equatorial |
question
| Gauche interaction |
answer
| A form of steric hinderance present in a staggered conformation |