CH3 — CH2 – CH – CH3
H3 H2 – CH3
CH3- CH2- CH2- CH2- CH3
CH3 -H – CH2 – CH 2 – Cl
CH3 -H – CH – CH3 and CH3 – CH2 — CH3
CH3- CH2- CH2- CH2- CH2- CH2- CH3
CH3-CH2-C-O-CH3 is a(n)
(ATTN! This formula wouldn’t copy so I recreated it the best I could. There is a double bond between the C and the O above it… I hope this makes sense!)
C7H16(l) + 11O2(g) → 7CO2(g) + 8H2O(g).
How many liters of CO2 at STP are produced from the complete combustion of 2.00 moles of heptane?
(there is a double bond between the C and the O)
^v^v^(sorry, best i could do with the skeletal formula)