ucr BCH100 Fall 2009 – Flashcards

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question

Electonegativity

Most electronegative?

answer

Up and to the right

Flourine is most at 4.0

question
NonCovalent Bond Energies
answer

Hydrogen Bonds 20KJ*mol

Ion dipole bonds 20 KJ*mol

Hydrophobic Interactions 4-12

Van der Waals 4

question
Micelle
answer

a spherical arrangement of organic molecules in water solution clustered so that:
their hydrophobic parts are buried inside the sphere and
their hydrophilic parts are on the surface of the sphere and in contact with the water environment

question

Hydrogen bond

Strength

answer

the attractive interaction between dipoles when the:
positive end of one dipole is a hydrogen atom bonded to an atom of high electronegativity, most commonly O or N, and
the negative end of the other dipole is an atom with a lone pair of electrons, most commonly O or N
The strength of hydrogen bonding is about 2-5 kcal•mol -1  
for water, it is 5 kcal•mol-1

question
Strong base
answer
LiOH, NaOH, KOH, Ca(OH)2, and Ba(OH)2
question
Ka
answer

Ka = [H+][A-] / [HA]

 

 

question
pH=
answer
-log[H+]
question

Calculate pH when 1L of water is added to 10ml of 5M HCl

b) then same for 10ml 5M Naoh

answer

(.01L)(5M)/ 1.01L = .05M = [H+] => -log[.05]

 

b) [OH-] =.05M => [H+]= 10-14/[OH-] =>-log[H+]

question
Calculate the oH of a 1L solution to which has been added 6mL of 1.5M acetic acid (pka4.76) and 5ml .4 Sodium acetate
answer

[H+] = (.06L)(1.5)/1.011L = .009M

 

[OH-]= (.005L)(.4M)/1.011L = .002M

 

pH = 4.76 + log(.002/.009)

question
Hydrophobic Amino Acids

Trend?
answer
Alanine, Valine, Leucine, Isoleucine, Phenylalanine, Methionine, Tryptophan, Proline

Side Chains terminate in with Carbon
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alpha-Amino acid
answer
a structure in which the amino group is on the carbon adjacent to the carboxyl group
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Polar Amino Acids

Trend
answer
Serine, Threonine, Tyrosine, cysteine, asparagine, glutamine, histidine

Side chains terminate with xH
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Cysteine Special Property
answer
Can form disulfide bonds with other cysteines
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Acidic AA and Basic AA
answer
Acidic: side chain end in COOH which wants to become COO-

Basic: Sidechain ends with NHx that wants to become Nx+1
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Amino Acid Ionized form at Ka
answer
50% is ionized and 50% is protonated
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Finding Ionization ratio at a specific pH
answer
Ka/[H+] = [OH-]/[H+] =# 1:# is ratio
For basic
Ka/[H+] = [NH2]/[NH3+] = # => 1/# 1:1/# is ratio
question
Calculating Charge at pH
answer
When acids give up a H add a -1 when base gains an H add a +1

NH2 pka = 9.69 and pH below that it will be NH3+ = +1

COOH pka 2.34 and pH above it will give off its H COO- add -1
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Bohr Effect
answer

The pH of blood to promote/discourage oxygen holding ability of hemoglobin.

 

Muscles produce CO2 which increases acidity. The Increased Acidity caused the release of O2

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Chirality of Amino Acids
answer

COOH

H2N+H         

R     

 

N and H switch sides

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Polypeptide Bonding

 

How to write

answer

O- of COOH and the NH3+ bind to form

 

C-OH part and NH2-C part disapear to make

 

H

C-N-C

 

Write

 

NH3->COOH

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Aldose & Ketose
answer

Aldose: Monosaccharides with an aldehyde group

 

Ketose: Monosaccharides with a Ketone group

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D+L Saccharides Fischer Projection
answer
The Bottom most (closest to CH2OH) switches places
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Alpha and Beta Glycosidic Bonds
answer

Alpha = opposite side C1

Beta = Same Side C4

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Alpha Helix
answer

- One ploypeptide per turn

- Peptide bond is planar and rigid

- C=O is hydrogen Bonded to N-H for AA away

- The bonds are PARALLEL to the axis

-ProLine prevents Alpha helix becuase N isnt free for H bond

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Beta Pleated Sheet
answer

-Polypeptide chains run next to each other parallel or anti parallel C-N   or C-N

                        C-N       N-C  

 

-Can be diff parts of 1 chain or 2 chains

 

-R group alternate above and below the plane

 

-C=O and N-H hydrogen bonds and perpendicular to sheet

question
Collagen Triple Helix
answer

-Called Tropocollagen

 

- 3 polypeptide chaines wrapped around each other

 

-every 3rd AA is GLY

 

-Alternate X-Pro-Gly and X-Hyp-Gly

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Fibrous Proteins

Vs

Globular Proteins

answer

Fib: Long Rod, very strong, no folding

 

Glob: Sphereical, lots of folding

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Myoglobin
answer

-takes O2 from Hb

 

- two polar histidines that coordinate the Heme group

 

-Fe(II) of heme has 6 coordination sites, 4 interact with N atoms, 1 N of His, and 1 O2

 

-1 hist is a covalent tether for heme group

 

- 1 hist acts as a lid to prevent CO2 from bind straight on, weak angle allows removal, straight would be permanent

 

-CO2 binds to Heme better that O2

question
Hemoglobin
answer

-2 alpha and 2 beta chains

 

-each chain has 1 heme group so it can carry 4 O2

 

-O2 Binds cooperatively, 1st is hardest but it makes it easier for the next O2 to bind and so on

 

-goes through conformational change to bind O2

 

-Uses BPG to bind and transport Oxygen

-BPG lowers affinity so it can get rid of it

question
Fetal Hemoglobin
answer

Higher affinity for O2 the adult Hemoglobin

 

-Binds less strongly to BPG which means tighter O2 binding

 

-Sereine replaces Histadine

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Allosteric Change

 

Denaturization

answer

Allo: Temporary Protein shape change

 

Denature: Permanent shape change

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endergonic vs exergonic
answer

ender: gives of less energy than it consumes

 

Exer: gives of more energy than it consumes

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Enzyme rate equation
answer

A+B-> C+D

 

Rate=k[A]1 * [B]1

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Chymotrypsin
answer

Cut polypeptides into smaller pieces

Active form of chymotrypsinogen

seperate pepetides with Cysteine S-S bonds

 

question

Km

 

equation

answer

how tightly an enzyme binds to a substrate

Lower number = tighter bond

0 = permanent

 

Km = k-1 + K2 / K1

question

Lineweaver-Burk Plot

eq

y intercept

x intercept

x and y axis

answer

1/v = Km/Vmax * 1/[S] + 1/Vmax

 

y intercept = 1/Vmax

x intercept = -1/Kmax

 

x axis = 1/[S]

y = 1/V

question

Competitive Inhibition

Burk graph

answer

- inhibitor binds to active site preventing substrate and enzyme from binding

 

LOWERS Km but Vmax stays the same so slope gets steeper X intercept moves closer to 0

 

 

slope = Km/Vmax * (1 + [I]/Ki)

 

new Km = -1/Km * (1 + [I]/Ki)

 

question
Noncompetitive inhibition
answer

inhibitors bind elsewhere on the enzyme

 

Vmax decreases (y intercept gets higher) Km stays the same

 

New Vmax = 1/Vmax * (1 + [I]/Ki)

 

Slope = slope = Km/Vmax * (1 + [I]/Ki)

question

Allosteric inhibitor

2 types

answer

Changes shape to the protein

 

does not change Km or Vmax

 

Homotropic: Allosteric interaction occur when several identical molecules bind to a protein (O2 and Hb)

 

Heterotropic: Allosteric interaction occur when several different molecules bind to a protein

question

R and T

Concerted Model

Sequential Model

answer

R= active

T= deactive

 

Concerted: Allosteric activation binds to R and stabilizes it, more R or Allosteric Inhibitor binds to T and Stabilizes it, less R.

 

Sequential: Inhibitor or activator induces a conformational change make the active site more active or less

question

ΔG>0

ΔG<0

answer

ΔG<0 exergonic, spontaneous, warm

ΔG>0 endergonic, nonspontaneous, cold

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