Exam II Chemistry – Flashcards
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Unlock answersChemical kinetics |
how the molecular world changes with time |
Thermal |
__ energy produces constant molecular motion, causing molecules to repeatedly collide with one another. |
-nuclei -kinetics |
In a small fraction of the collisions caused by thermal energy, the electrons on one molecule or atom are attracted to the __ of another. Some bonds weaken and new bonds form – a chemical reaction occurs. Chemical __ is the study of how these kinds of changes occur in time |
Rate of reaction |
__ = how fast a reaction occurs |
life |
Reaction rates are important to __ |
enzymes |
Rate of reaction is controlled through the use of __ |
Wilhelmy |
__ = first person to measure the rate of a chemical reaction |
molecular |
The rate of a reaction can tell us much about how the reaction occurs on the __ scale |
reaction |
The rate of a chemical reaction is a measure of how fast the __ occurs |
Slow rate of reaction |
__ = small fraction of molecules react to form products in a given period of time |
Fast rate of reaction |
__ = large fraction of molecules react to form products in a given period of time |
change in some quantity per unit of time |
When measuring the rate at which something occurs, we express the measurement as a __ |
-measuring -time |
When measuring the rate at which something occurs, we report the rate in units that represent the change in what we are __ divided by the change in __ |
-reactants or products (usually in concentration units) -time |
The rate of a chemical reaction is measured as a change in the amounts of __ divided by the change in __ |
Reaction rate |
__ – the negative of the change in concentration of a reactant divided by the change in time |
-reactant -decrease |
The negative sign is part of the definition when the reaction rate is defined with respect to a __ because reactant concentrations __ as a reaction proceeds; therefore the change in the concentration of a reactant is negative, which makes the overall rate positive |
positive |
Reaction rates are reported as __ quantities |
product |
The reaction rate can also be defined with respect to the __ of the reaction |
-increase -positive |
Product concentrations __ as the reaction proceeds, the change in concentration of a product is __ |
-don’t include - positive |
When the rate is defined with respect to a product, __ a negative sign – the rate is naturally __ |
stoichiometric coefficients |
To have a single rate for an entire reaction, the definition of the rate with respect to each reactant and product must reflect the __ of the reaction |
-decreases -consumed |
The reactant concentration __ with time because reactants are __ in a reaction |
-increases -formed |
The product concentration __ with time because products are __ in a reaction |
Rate = - ?[molecule] / ?t |
Calculate the average rate of the reaction for any time interval using the equation: __ |
- decreases -slows down |
The average rate __ as the reaction progresses, the reaction __ as it proceeds |
concentrations of the reactants |
The average rate of the reaction depends on the __ |
-decrease -slows down |
As reactants transform to products, their concentrations __, and the reaction __ |
Instantaneous rate of the reaction |
__ = the rate at any one point in time, and is represented by the instantaneous slope of the curve at that point |
slope of the tangent to the curve |
Determine the instantaneous rate from the __ at the point of interest |
-(1 / a)(?[A] / ?t) = -(1 / b)( ?[B] / ?t) = +(1 / c)( ?[C] / ?t) = +(1 / d)( ?[D] / ?t) A and B C and D a, b, c, and d |
Rate of the reaction > Rate = __ __ are reactants, __ are products, and __ are the stoichiometric coefficients |
any other reactant or product at that point in time (from the balanced equation) |
Knowing the rate of change in the concentration of any one reactant or product at a point in time allows us to determine the rate of change in the concentration of __ |
not possible |
Predicting the rate at some future time is __ from just the balanced equation |
kinetics |
Must have an experimental way to measure the concentration of at least one of the reactants or products as a function of time to study the __ of a reaction |
Polarimetry (experimental way to measure the concentration of at least one of the reactants or products as a function of time) |
__ – measuring the degree of polarization of light passing through a reacting solution to determine the relative concentrations of the reactants and products as a function of time |
spectroscopy (experimental way to measure the concentration of at least one of the reactants or products as a function of time) |
Most common way to study the kinetics of a reaction is through __ |
Spectrometer (experimental way to measure the concentration of at least one of the reactants or products as a function of time) |
__ – device that passes light through a sample and measures how strongly the light is absorbed. |
spectrometer (experimental way to measure the concentration of at least one of the reactants or products as a function of time) |
In using a __, if the sample contains the reacting mixture, the intensity of the light absorption will decrease as the reaction proceeds, providing a direct measure of the concentrations of the molecule as a function of time |
pressure (experimental way to measure the concentration of at least one of the reactants or products as a function of time) |
Reactions in which the number of moles of gaseous reactants and products changes as the reaction proceeds can be monitored by measuring changes in __ |
-increases -rises -rise |
As a reaction proceeds and the amount of gas __, the pressure steadily __. The __ in pressure can be used to determine the relative concentrations of reactants and products as a function of time |
polarimetry, spectroscopy, and pressure measurement |
Three techniques – __ – can be used to monitor the reaction as it occurs in the reaction vessel |
progress of the reaction |
Some reactions occur slowly enough that samples, or aliquots can be periodically withdrawn from the reaction vessel and analyzed to determine the __ |
sample |
__ = aliquot |
aliquot |
Instrumental techniques – gas chromatography, mass spectrometry - can be used to measure the relative amounts of reactants or products in the __ |
reactants and products |
Taking aliquots at regular time intervals, can determine the relative amounts of __ as a function of time |
concentration |
Rate of a reaction depends on the __ of one or more of the reactants |
rate law |
As long as the rate of the reverse reaction (in which the products return to reactants) is negligibly slow, we can write a relationship – called the __ – between the rate of the reaction and the concentration of the reactant |
k[A]n |
Rate law equation = __ |
k = constant of proportionality called the rate constant n = reaction order. The value of this determines how the rate depends on the concentration of the reactant |
in the rate law equation k[A]n , k = __, n = __ |
-zero order - independent of the concentration of A |
if n = 0, the reaction is __ and the rate is __ |
-first order -directly proportional to the concentration of A |
ifn = 1, the reaction is __ and the rate is __ |
-second order -proportional to the square of the concentration of A |
if n = 2, the reaction is __, and the rate is __ |
concentration |
in a zero-order reaction, the rate of the reaction is independent of the __ of the reactant |
k[A]0 = k |
if the reaction is a zero-order reaction, rate = |
-decreases -constant -does not |
in a zero-order reaction,the concentration of the reactant __ linearly with time at a __ rate because the reaction ___ slow down as the concentration of A decreases |
same |
The rate of a zero-order reaction is the __ at any concentration of A |
Zero-order |
__ reactions occur under conditions where the amount of reactant actually available for reaction is unaffected by changes in the overall quantity of reactant |
zero order |
Sublimation is normally a __ reaction because only molecules at the surface can sublime, and their concentration does not change when the amount of subliming substance decreases |
directly proportional |
in a first-order reaction,the rate of the reaction is __ to the concentration of the reactant |
k[A]1 |
in a first-order reaction, rate = __ |
-slows down - decreases |
For first-order reaction the rate __ as the reaction proceeds because the concentration of the reactant __ |
first-order |
in a __ reaction,the rate is directly proportional to the concentration |
proportional to the square |
in a second-order reaction,the rate of the reaction is __ of the concentration of the reactant |
k[A]2 |
for a second-order reaction, rate = __ |
sensitive |
For second-order reaction, the rate is __ to the reactant concentration |
second-order |
for a __ reaction,the rate is proportional to the square of the concentration |
experiment |
The order of a reaction can be determined only by __ |
Method of initial rates |
___ = common way to determine reaction order method of initial rates |
the initial rate |
__ – the rate for a short period of time at the beginning of the reaction |
method of inital rates |
the initial rate is measured by running the reaction several times with different initial reactant concentrations to determine the effect of the concentration on the rate |
-initial rate - initial concentration |
For a reaction that is a first-order reaction, the __ is directly proportional to the __ |
k[A]1 |
for a reaction that is a first-order reaction, Rate = __ |
solving the rate law for k and substituting the concentration and the initial rate from any one of the measurements found through experiment |
For a reaction that is a first-order reaction, determine the value of the rate constant, k, by __ |
s-1 |
For a first-order reaction, the rate constant has units of __ |
-same -initial |
For a zero-order reaction, the initial rate is independent of the reactant concentration – the rate is the __ at all measured __ concentrations |
-quadruples -doubling -quadratic |
For a second-order reaction, the initial rate __ for a __ of the reactant concentration – the relationship between concentration and rate is __ |
second-order |
For a __ reaction you can substitute any two initial concentrations and the corresponding initial rates into a ratio of the rate laws to determine the order (n): rate 2 / rate 1 = k[A]n2 / k[A]n1 |
M x s-1 |
The rate constant for a zero-order reaction has units of __ |
M-1 x s-1 |
The rate constant for a second-order reaction has units of __ |
multiplied |
reaction order for multiple reactants:As long as the reverse reaction is negligibly slow, the rate law is proportional to the concentration of [A] raised to the m __ by the concentration of [B] raised to the n |
k[A]m[B]n |
Reaction order for multiple reactants; Rate = __ |
-A and B -m -n |
in the reaction order for multiple reactions,Rate = k[A]m[B]n; __ are reactants
__ is the reaction order with respect to A __ is the reaction order with respect to B
|
sum of the exponents (m + n) |
in the reaction order for multiple reactants,the overall order is the __ |
-experiment -method of initial rates |
the rate law for any reaction must always be determined by __, often by the __ |
rate law |
no simple way to look at a chemical equation and determine the __ for the reaction |
independently |
in determining the reaction order for multiple reactants,when there are two or more reactants, the concentration of each reactant is usually varied __ of the others to determine the dependence of the rate on the concentration of that reactant |
Integrated rate law |
__ for a chemical reaction is a relationship between the concentration of the reactants and time |
order of the reaction |
The integrated rate law for a reaction depends on the __ |
ln[A]t = -kt + ln[A]0 OR ln ([A]t / [A]0) = -kt |
what is the first-order integrated rate law? |
[A]t k [A]0 |
for all of the integrated rate laws: __ = the concentration of A at any time, t __ = rate constant __ = initial concentration of A |
straight line ln[A]t = -kt + ln[A]0 --> y = mx + b
|
the integrated rate law has the form of an equation for a __ |
straight line –k ln[A]0 |
for a first-order reaction, a plot of the natural log of the reactant concentration has a function of time yields a __ with a slope of __and a y-intercept of __ |
negative positive |
for a first-order reaction, slope is __, but the rate constant is always __ |
1 / [A]t = kt + 1 / [A]0 |
what is the second-order integrated rate law? |
straight line 1 / [A]t = kt + 1 / [A]0 --> y = mx + b
|
The second-order integrated rate law is also in the form of an equation for a __ |
inverse straight line k 1 / [A]0 |
for a second-order reaction, plot the __ of the concentration of the reactant as a function of time, which yields a __ with a slope of __ and an intercept of __ |
[A]t = -kt + [A]0 |
what is the zero-order integrated rate law? |
straight line [A]t = -kt + [A]0 --> y = mx + b |
The zero-order integrated rate law is also in the form of an equation for a __ |
straight line –k [A]0 |
for a zero-order reaction, a plot of the concentration of the reactant as a function of time yields a __ with a slope of __ and an intercept of __ |
Half-life (t1/2) |
__ of a reaction is the time required for the concentration of a reactant to fall to one-half of its initial value |
rate constant initial concentration |
The half-life expression defines the dependence of half-life on the __ and the __ |
different |
the half-life expression is __ for different reaction orders |
t1/2 = 0.693 / k |
what is the half-life of a first-order reaction? |
independent |
For a first-order reaction, t1/2 is __ of the initial concentration |
constant |
Even though the concentration is changing as the reaction proceeds, the half-life (how long it takes for the concentration to halve) is __ for a first-order reaction half-life |
first-order |
Constant half-life is unique to __ reactions |
t1/2 = 1 / k[A]0 |
what is the half-life of a second-order reaction? |
initial concentration |
For a second-order reaction, the half-life depends on the __ |
decreases |
The half-life continues to get longer as the concentration __ for second-order reactions |
t1/2 = [A]0 / k[A]0 |
what is the half-life or a zero-order reaction? |
initial concentration |
For a zero-order reaction, the half-life depends on the __ |
reaction order rate law |
The __ and __ must be determined experimentally |
reactant(s) |
The rate law relates the rate of the reaction to the concentration of the __ |
reactant(s) time |
The integrated rate law (which is mathematically derived from the rate law) relates the concentration of the __ to __ |
one-half of its initial value |
The half-life is the time it takes for the concentration of a reactant to fall to __ |
first-order |
The half-life of a __ reaction is independent of the initial concentration |
zero-order second-order |
The half-lives of __ and __ reactions depend on the initial concentration |
C) the reaction is most likely second order because its rate depends on the concentration (therefore it cannot be zero order), and its half-life depends on the initial concentration (therefore is cannot be first order). For a second-order reaction, a doubling of the initial concentration results in the quadrupling of the rate |
A decomposition reaction, with a rate that is observed to slow down as the reaction proceeds, is found to have a half-life that depends on the initial concentration of the reactant. Which of the following is most likely to be true of this reaction? A) a plot of the natural log of the concentration of the reactant as a function of time will be linear B) the half-life of the reaction increases as the initial concentration increases C) A doubling of the initial concentration of the reactants results in a quadrupling of the rate |
temperature |
The rates of chemical reactions are highly sensitive to __ |
rate constant, k (which is actually a constant only when the temperature remains constant) |
The rate law for a reaction is Rate = k[A]n , the temperature dependence of the reaction rate is contained in the __ |
increase faster |
Increase in temperature generally results in an __ in k, which results in a __ rate |
Arrhenius equation |
__ – shows the relationship between the rate constant (k) and the temperature in kelvins (T) |
Kelvins |
The Arrhenius equation has to have the temperature in __ |
k = Ae-Ea / RT |
what is the Arrhenius equation? |
A -Ea e-Ea / RT R |
in the Arrhenius equation, __ = constant called the frequency factor (or pre-exponential factor) __ = activation energy (or activation barrier) __ = exponential factor __ = gas constant |
8.314 J / mol x K |
the gas constant (R) for the Arrhenius equation is what? |
Activation energy (Ea) |
__ is an energy barrier or hump that must be surmounted for the reactants to be transformed into products |
Frequency factor (A) |
__ is the number of times that the reactants approach the activation barrier per unit time |
activated complex, or transition state |
To get from the reactant to the product, the molecule must go through a high-energy intermediate state called the __ |
initially weaken the chemical bonds |
The overall reaction is energetically downhill (exothermic), but it must first go uphill to reach the activated complex because energy is required to __ |
activation energy |
The energy required to reach the activated complex is the __ |
slower |
The higher the activation energy, the __ the reaction rate (at a given temperature) |
approaches |
Frequency factor represents the number of __ to the activation barrier per unit time |
not equivalent |
Approaching the activation barrier is __ to surmounting it |
do not |
Most of the approaches to the activation barrier __ have enough total energy to make it over the activation barrier |
Exponential factor |
__ is a number between 0 and 1 that represents the fraction of molecules that have enough energy to make it over the activation barrier on a given approach |
successful product |
Exponential factor is the fraction of approaches that are actually __ and result in the __ |
temperature (T) activation energy (Ea) |
Exponential factor depends on both the __ and the __ of the reaction |
one |
Low activation energy and a high temperature make the negative exponent small, so that the exponential factor approaches __ |
one (e-0 = 1) successful |
If the activation energy is zero, then the exponent is zero, and the exponential factor is exactly __. every approach to the activation barrier is __ |
negative number very small |
A large activation energy and a low temperature make the exponent a very large __, so that the exponential factor become __ |
zero (e-infinitey = 0) |
As the temperature approaches 0 K, the exponent approaches an infinitely large number, and the exponential factor approaches __ |
increases |
As the temperature increases, the number of molecules having enough thermal energy to surmount the activation barrier __ |
distribution |
At any given temperature, a sample of molecules will have a __ of energies |
small |
Commonly, only a __ fraction of molecules have enough energy to make it over the activation barrier |
large |
A small change in temperature results in a __ difference in the number of molecules having enough energy to surmount the activation barrier |
frequency factor |
The __ is the number of times that the reactants approach the activation barrier per unit time |
exponential factor |
The __ is the fraction of approaches that are successful in surmounting the activation barrier and forming products |
increases decreases |
The exponential factor__ with increasing temperature, but __ with increasing activation energy |
ln k = - Ea / R (1 / T) + ln A |
what is the equation for the Arrhenius plots? |
straight line |
The Arrhenius plots equation is in the form of a __ |
Arrhenius plot |
A plot of the natural log of the rate constant (ln k) versus the inverse of the temperature in kelvins (1 / T) yields a straight line with a slope of –Ea / R and a y-intercept of ln A |
kinetic |
Arrhenius plot used in the analysis of __ data |
rate constant |
When either data are limited or plotting capabilities are absent, we can calculate the activation energy if we know the __ at just two different temperatures |
ln (k2 / k1) = Ea / R (1 / T1 – 1 / T2) |
what is the two-point form of the Arrhenius equation? |
two different |
the two-point form of the Arrhenius equation isused to calculate the activation energy from experimental measurements of the rate constant at __ temperatures |
Collision model |
__ – a chemical reaction occurs after a sufficiently energetic collision between two reactant molecules |
Collision theory |
__ – each approach to the activation barrier is a collision between the reactant molecules. So the value of the frequency factor should be the number of collisions that occur per second |
smaller |
Frequency factors of most gas-phase chemical reactions tend to be __ than the number of collisions that occur per second |
k = Ae-Ea / RT = pze-Ea / RT p = orientation factor z = collision frequency
|
what two separate parts can the frequency factor be separated into? |
collision frequency |
__ - number of collisions that occur per unit time, can be calculated for a gas-phase reaction from the pressure of the gases and the temperature of the reaction mixture |
109 |
single molecule undergoes on the order of __ collisions every second (typical conditions) |
sufficient energy |
for reaction to occur, molecules must collide with __ |
properly oriented |
not all collisions with sufficient energy will lead to products because the reactant molecules must also be __ |
break and form |
if two molecules are to react with each other, they must collide in such a way that allows the necessary bonds to __ |
small orientation factor |
__ = orientational requirements are very stringent – the molecules must be aligned in a very specific way for the reaction to occur |
1 |
reactions between individual atoms usually have orientation factors of approximately __, because atoms are spherically symmetric and thus any orientation can lead to the formation of products |
don’t have to collide to react |
a few reactions have orientation factors greater than one, which means that reactants __ |
nuclei weaken form products |
when two molecules with sufficient energy and the correct orientation collide the electrons on one of the atoms or molecules are attracted to the __ of the other; some bonds begin to __ while other bonds begin to __ and the reactants go through the transition state and are transformed into the __ --> how chemical reaction occurs |
C) since the reactants in part A) are atoms, the orientation factors should be about one. The reactants in parts B) and C) are both molecules, so we expect orientation factors of less than one. Since the reactants in B) are symmetrical, we would not expect the collisions to have as specific an orientation requirement as in C), where the reactants are asymmetrical and must therefore collide in such way that a hydrogen atom is in close proximity to another hydrogen atom. Therefore, we expect C) to have the smallest orientation factor |
Which reaction would you expect to have the smallest orientation factor? A) H(g) + I(g) --> HI(g) B) H2(g) + I2(g) --> 2 HI (g) C) HCl(g) + HCl(g) --> H2(g) + Cl2(g) |
overall reaction |
In writing a chemical equation to represent a chemical reaction, we usually represent the __, not the series of individual steps by which the reaction occurs |
Reaction mechanism |
__ – series of individual chemical steps by which an overall chemical reaction occurs |
elementary step |
Each step in a reaction mechanism is an __ |
cannot |
Elementary step – step that __ be broken down into simpler steps, they occur as they are written (they represent the exact species that are colliding in the reaction) |
equal |
For a reaction mechanism to be valid the individual steps in the mechanisms have to __ the overall reaction |
Reaction intermediate |
__ – forms in one elementary step and is consumed in another |
Reaction mechanism |
__ – complete, detailed description of the reaction at the molecular level – it specifies individual collisions and reactions that result in the overall reaction |
measuring the kinetics of the overall reaction |
Can put a reaction mechanism together by __ and working backward to write a mechanism consistent with the measured kinetics |
molecularity |
Elementary steps = characterized by their __ – number of reactant particles involved in the step |
unimolecular bimolecular |
Most common molecularities = __ and __ |
unimolecular |
A --> products = __ |
bimolecular |
A + A --> products = __ |
bimolecular |
A + B --> products = __ |
Termolecular |
__ = elementary steps in which three reactant particles collide; very rare because of low probability of three particles colliding simultaneously |
balanced chemical equation |
Rate law for an elementary step can be deduced from the __ (rate law can’t be found for an overall chemical reaction with same method) |
product |
Elementary step occurs though the collision of the reactant particles so the rate law is proportional to the __ of the concentrations of those particles |
A + B --> products; Rate = k[A][B] |
rate for the bimolecular elementary step in which A reacts with B is proportional to the concentration of A multiplied by the concentration of B: |
A + A --> products; Rate = k[A]2 |
rate law for the bimolecular step in which A reacts with A is proportional to the square of the concentration of A: |
1 k[A] |
A ---> products ; molecularity = __ ; Rate = __ |
2 k[A]2 |
A+A --> products ; molecularity = __ ; Rate = __ |
2 k[A][B] |
A+B --> products ; molecularity = __ ; Rate = __ |
3 k[A]3 |
A+A+A --> products; molecularity= __; Rate = __ |
3 k[A]2[B] |
A+A+B --> products; molecularity=__; Rate = __ |
3 k[A][B][C] |
A+B+C --> products; molecularity=__; Rate = __ |
overall order |
The molecularity of the elementary step is equal to the __ of the step |
rate-determining step |
In most chemical reactions, one of the elementary steps – called the __ – is much slower than the others |
limits rate law |
Rate-determining step in a reaction mechanism __ the overall rate of the reaction and determines the __ for the overall reaction |
1. The elementary steps in the mechanism must sum to the overall reaction 2. The rate law predicted by the mechanism must be consistent with the experimentally observed rate law |
what two conditions must be met for a reaction mechanism to be valid? |
validated |
reaction mechanisms can only be __ not proven |
is not |
valid mechanism __ a proven mechanism because other mechanisms may also fulfill both of the requirements; therefore, we can only say that a given mechanism is consistent with kinetic observations of the reaction and therefore possible |
validity |
other types of data – such as the experimental evidence for a proposed intermediate – can further strengthen the __ of a proposed mechanism |
overall reaction |
When proposed mechanism for a reaction has a slow initial step, the rate law predicted by the mechanism normally contains only reactants involved in the __ |
rate limiting step |
When a reaction mechanism begins with a fast initial step, some other subsequent step in the mechanism is the __. |
reaction intermediates |
When a reaction mechanism begins with a fast initial step, the rate law predicted by the rate-limiting step may contain __ |
experimental rate law |
Reaction intermediates do not appear in the overall reaction equation, so a rate law containing intermediates cannot generally correspond to the __ |
concentrations of the reactants |
We can express the concentration of intermediates in terms of the __ of the overall reaction |
limited |
In multistep mechanism where the first step is fast, the products of the first step can build up, because the rate at which they are consumed is __ by some slower step further along |
re-form |
In mechanism with a fast first step the build up of products from the first step react with one another to __ the reactants |
equilibrium |
In mechanism with a fast first step, as long as the first step is fast enough compared to the rate-limiting step, the first-step reaction will reach __ |
equals |
both the forward reaction and the reverse reaction occur. If equilibrium is reached, then the rate of the forward reaction __ the rate of the reverse reaction |
concentration of the reactants temperature |
Can speed up the rate of a reaction by increasing the __ or by increasing the __ |
catalyst |
Reaction rates can be increased by using a __ – substance that increases the rate of a chemical reaction but is not consumed by the reaction |
alternative mechanism |
Catalyst provides an __ for the reaction – one in which the rate-determining step has a lower activation energy |
homogeneous and heterogeneous |
catalysis can be categoriaed into what two types? |
Homogeneous catalysis |
__ = the catalyst exists in the same phase (or state) as the reactants |
Heterogeneous catalysis |
__ = the catalyst exits in a different phase than the reactants |
heterogeneous catalysis |
Use of solid catalysts with gas-phase or solution-phase reactants is the most common type of __ |
alkenes |
Second example of heterogeneous catalysis involves the hydrogenation of double bonds with __ |
1. adsorption, 2. diffusion, 3. reaction, 4. desorption |
what are the four steps of a heterogeneous catalysis? |
adsorption |
__ is the first step of a heterogeneous catalysis. the reactants are absorbed onto the metal surface |
diffusion |
__ is the second step of a heterogeneous catalysis. the reactants diffuse on the surface until they approach each other |
reaction |
__ is the third step of a heterogeneous catalysis. the reactants react to form the products |
desorption |
__ is the fourth step of a heterogeneous catalysis. the products desorb from the surface into the gas phase |
enzymes |
Living organisms rely on __, biological catalysts that increase rates of biochemical reactions |
Enzymes |
__ – large protein molecules with complex 3-D structures. Within their structures there is a specific area called the active site |
substrate |
properties and shape of the active site are just right to bind the reactant molecule, called the __ |
lowered faster |
substrate fits into the active site perfectly, when substrate binds to the active site of the enzyme – through intermolecular forces – the activation energy of the reaction is greatly __, allowing the reaction to occur at a much __ rate |
which when |
enzymes give living organisms control over __reactions occur, and __ they occur |
specific efficient |
enzymes are extremely __ and __, speeding up reaction rates by factors of as much as a billion |
catalyze |
if living organism wants to turn a particular reaction on, it produces or activates the correct enzyme to __ the reaction |
kinetics |
Speed of a chemical reaction is determined by __ |
thermodynamics |
Extent of a chemical reaction is determined by __ |
large |
Reaction with a __ equilibrium constant proceeds nearly to completion – nearly all the reactants react to form products |
small |
Reaction with a __ equilibrium constant barely proceeds at all – nearly all the reactants remain as reactants, hardly forming any products |
extent |
Equilibrium constant is an experimentally measureable quantity and be used to predict and quantify the __ of a reaction |
equilibrium constant, K |
The concentrations of the reactants and products in a reaction at equilibrium are described by the __ |
right high low |
Large value of K = reaction lies far to the __ at equilibrium = __ concentration of products and a __ concentration of reactants |
left high low |
small value of K = reaction lies far to the __ at equilibrium = __ concentration of reactants and a __ concentration of products |
how far a reaction proceeds |
value of K = measure of __ |
toward the products |
the larger the value of K, the more the reaction proceeds __ |
maintain equilibrium counteract |
any system at equilibrium, responds to changes in ways that _; if any of the concentrations of the reactants or products change, the reaction shifts to __ that change |
larger product |
equilibrium for fetal hemoglobin is __ than the equilibrium constant for adult hemoglobin = the reaction tends to go farther in the direction of the __ |
increase decrease |
Reaction rates generally __ with increasing concentration of the reactants (unless the reaction order is zero) and __ with decreasing concentration of the reactants |
reversible |
A reaction that can proceed in both the forward and reverse directions is said to be __ |
equals |
Dynamic equilibrium for a chemical reaction is the condition in which the rate of the forward reaction __ the rate of the reverse reaction |
occurring occurring at the same rate |
In dynamic equilibrium, the forward and reverse reactions are still __; however, they are __ |
form at the same rate that they are depleted |
When dynamic equilibrium is reached, the concentrations of the reactants and products no longer change. They remain the same because the reactants and products __ |
equal to one another |
Because the concentrations of reactants and products no longer change at equilibrium does not mean that the concentrations of reactants and products are __ at equilibrium |
most small fraction |
Some reactions reach equilibrium only after __ of the reactants have formed products Some reactions reach equilibrium when only a __ of the reactants have formed products |
reaction |
When a reaction reaches equilibrium depends on the __ |
so small that it can be ignored |
Nearly all chemical reactions are at least theoretically reversible. In many cases, the reversibility is __ |
no longer change |
Equilibrium is reached in a chemical reaction when the concentrations of the reactants and products __ |
Dynamic equilibrium |
__: rate of forward reaction = rate of reverse reaction. Concentrations of reactant(s) and product(s) no longer change |
slows down speeds up |
As concentration of product increases, and concentrations of reactants decrease, rate of forward reaction __ and rate of reverse reaction __ |
constant |
When equilibrium is reached, both the forward and reverse reactions continue, but at equal rates, so the concentrations of the reactants and products remain __ |
concentrations |
When a chemical reaction reaches dynamic equilibrium the __ of reactants and products will not necessarily be equal at equilibrium |
not equal equal |
The concentrations of reactants and products are __ at equilibrium; rather, the rates of the forward and reverse reactions are __ |
quantify concentrations |
The equilibrium constant is a way to __ the __ of the reactants and products at equilibrium |
ratio products reactants |
The equilibrium constant (K) for the reaction is defined as the __ – at equilibrium – of the concentrations of the __ raised to their stoichiometric coefficients divided by the concentrations of the __ raised to their stoichiometric coefficients (Law of Mass Action) |
K = [C]c[D]d / [A]a[B]b |
what is the expression for the equilibrium constant (K) also known as the Law of Mass Action? |
molarity of products molarity of reactants molar concentration of A (M; molarity) |
in the equilibrium constant (K) equation (also known as the law of mass action) -->K = [C]c[D]d / [A]a[B]b [C]c[D]d = __ [A]a[B]b = __ [A] = __ |
law of mass action |
the relationship between the balanced chemical equation and the expression of the equilibrium constant is known as the __ |
balanced chemical equation law of mass action |
To express an equilibrium constant for a chemical reaction, examine the __ and apply the __ |
exponents |
The coefficients in the chemical equation become the __ in the expression of the equilibrium constant |
larger |
A large equilibrium constant (K>>1) indicates that the numerator (which specifies the amounts of products at equilibrium) is __ than the denominator (which specifies the amounts of reactants at equilibrium). |
forward |
when equilibrium constant is large (K>>1) the __ reaction is favored |
far to the right products reactants |
When the equilibrium constant is large, the equilibrium point for the reaction lies __ – high concentration of __, low concentrations of __ |
long time |
A reaction with a large equilibrium constant may be kinetically very slow and take a __ to reach equilibrium |
smaller |
A small equilibrium constant (K<<1) indicates that the numerator (which specifies the amounts of products at equilibrium) is __ than the denominator (which specifies the amounts of reactants at equilibrium) |
reverse |
when the equilibrium constant is small (K<<1) the __ reaction is favored |
far to the left reactants products |
When the equilibrium constant is very small, the equilibrium point for the reaction lies __ – high concentrations of __, low concentrations of __ |
K << 1 |
__ = reverse reaction is favored; forward reaction does not proceed very far |
K approximately equal to 1 |
__ = neither direction is favored; forward reaction proceeds about halfway |
K >> 1 |
__ = forward reaction is favored; forward reaction proceeds essentially to completion |
(b) the reaction mixture will contain 1 mol of A and 10 mol of B so that [B]/[A] = 10 ...it will contain more moles of B when compared to A because the equilibrium constant (K) is 'large' so the forward reaction is favored and the concentration of products is large and the concentration of reactants is small |
The equilibrium constant for the reaction A (g) <--> B (g) is 10. A reaction mixture initially contains 11 mol of A and 0 mol of B in a fixed volume of 1 L. When equilibrium is reached, which statement is true? (a) the reaction mixture will contain 10 mol of A and 1 mol of B (b) the reaction mixture will contain 1 mol of A and 10 mol of B (c) the reaction mixture will contain equal amounts of A and B |
equilibrium constant |
If a chemical equation is modified in some way, then the __ for the equation must be changed to reflect the modification |
1. reversing the equation 2. multiplying the coefficients in the equation by a factor 3. adding two or more individual chemical equations to obtain an overall equation |
what are the three common modifications for a chemical equation? |
invert |
because the equilibrium constant must be changed if a chemical equation is modified in some way, if you reverse a chemical equation __ the equilibrium constant to reflect the modification of the chemical equation |
same factor |
because the equilibrium constant must be changed if a chemical equation is modified in some way, if you multiply the coefficients in a chemical equation by a factor, raise the equilibrium constant to the __ to reflect the modification in the chemical equation |
multiply the corresponding equilibrium constants |
because the equilibrium constant must be changed if a chemical equation is modified in some way, if you add two or more individual chemical equations to obtain an overall equation, __ by each other to obtain the overall equilibrium constant to reflect the modification in the chemical equation |
concentration |
For gaseous reactions, the partial pressure of a particular gas is proportional to its __ |
equilibrium constant |
We can also express the __ in terms of partial pressures of the reactants and products |
Kc |
__ = equilibrium constant with respect to the concentration in molarity |
Kp |
__ = equilibrium constant with respect to partial pressures in atmospheres |
partial pressure of each gas |
The expression for Kp takes the form of the expression for Kc, except that we use the __ in place of its concentration |
PA |
__ = partial pressure of gas A in units of atmospheres |
not necessarily equal |
Since the partial pressure of a gas in atmospheres is not the same as its concentration in molarity, the value of Kp for a reaction is __ to the value of Kc |
ideally |
As long as the gases are behaving __, we can derive a relationship between two constants (Kc and Kp) |
number of moles of A (nA) divided by its volume (V) in liters: [A] = nA/V |
The concentration of an ideal gas A is the __ |
PAV = nART --> PA = (nA/V)RT |
From the ideal gas law, we can relate the quantity nA/V (concentration of an ideal gas 'A') to the partial pressure of A: __ |
PA = [A]RT or [A] = PA / RT |
[A] = nA / V --> PA = __ or [A] = __ |
Kp = Kc(RT)c+d-(a+b) |
what is the equation for Kp (the equilibrium constant with respect to partial pressures)? |
delta n |
__ = c + d – (a + b), which is the sum of the stoichiometric coefficients of the gaseous products minus the sum of the stoichiometric coefficients of the gaseous reactants |
Kp = Kc(RT)delta n |
Kp = __ |
0 equal |
If the total number of moles of gas is the same after the reaction as before, then delta n = __, and Kp is __ to Kc |
corresponding units |
As long as concentration units are expressed in molarity for Kc and pressure units are expressed in atmospheres for Kp, we can skip the formality of units and enter the quantities directly into the equilibrium expression, dropping their __ |
reactants products |
Many chemical reactions involve pure solids or pure liquids as __ or __ |
does not |
The concentration of a solid __ change because a solid does not expand to fill its container. |
density |
A solids concentration depends only on its __, which is a constant as long as some solid is present |
are not |
Pure solids – those reactants or products labeled in the chemical equation with an (s) – __ included in the equilibrium expression (because their constant value is incorporated into the value of K) |
does not |
The concentration of a pure liquid __ change |
excluded |
Pure liquids – reactants or products labeled in the chemical equation with an (l) – are also __ from the equilibrium expression |
Heterogeneous |
__ equilibrium – the concentration of solid carbon (the number of atoms per unit volume) is constant as long as some solid carbon is present. The same is true for pure liquids. Thus, the concentrations of solids and pure liquids are not included in equilibrium constant expressions |
(b) since delta n for gaseous reactants and products is zero, Kp equals Kc |
For which reaction does Kp = Kc (a) 2Na2O2(s) + 2CO2(g) « 2Na2CO3(s) + O2(g) (b) NiO(s) + CO(g) « Ni(s) + CO2(g) (c) NH4NO3(s) « N2O(g) + 2H2O(g) |
concentrations of the reactants and products |
Most direct way to obtain an experimental value for the equilibrium constant of a reaction is to measure the __ in a reaction mixture at equilibrium |
has no formal part in the calculation |
Since equilibrium constants depend on temperature, many equilibrium problems will state the temperature even though it __ |
moles per liter (M) unitless |
The concentrations within Kc should always be written in __; however, the units are not normally included when expressing the value of the equilibrium constant, so Kc is __ |
equilibrium concentrations |
The __ of the reactants and products will depend on the initial concentrations (and in general vary from one set of initial concentrations to another) |
same |
The equilibrium constant will always be the __ at a given temperature, regardless of the initial concentrations |
the same |
Whether you start with only reactants or only products, the reaction reaches equilibrium concentrations in which the equilibrium constant is __ |
equilibrium constant, K |
No matter what the initial concentrations are, the reaction will always go in a direction so that the equilibrium concentrations – when substituted into the equilibrium expression – give the same __ |
the stoichiometry of the reaction |
We need only know the initial concentrations of the reactant(s) and the equilibrium concentration of any one reactant or product. The other equilibrium concentrations can be deduced from __ |
ICE table |
__ – table summarizing the initial conditions, the changes, and the equilibrium conditions; |
I = initial, C = change, E = equilibrium |
for the ICE table, I = __, C = __, E = __ |
equilibrium concentrations ICE table |
to calculate the equilibrium constant, we can use the balanced equation to write an expression for the equilibrium constant and the substitute the __ from the __ |
right (toward the products) |
When the reactants of a chemical reaction mix, they generally react to form products – we say that the reaction proceeds to the __ |
magnitude of the equilibrium constant |
The amount of products formed when equilibrium is reached depends on the __ |
reaction quotient |
In order to compare the progress of a reaction to the equilibrium state of the reaction, we use a quantity called the __ |
any point in the reaction |
Reaction quotient (Qc) – the ratio – at __ – of the concentrations of the products raised to their stoichiometric coefficients divided by the concentrations of the reactants raised to their stoichiometric coefficients |
Qp |
For gases with amounts measured in atmospheres, the reaction quotient uses the partial pressures in place of concentrations and is called __ |
equilibrium constant reactant quotient |
The difference between the reaction quotient and the equilibrium constant is that, at a given temperature, the __ has only one value and it specifies the relative amounts of reactants and products at equilibrium The __ depends on the current state of the reaction and has many different values as the reaction proceeds |
zero (Qc = 0) |
In a reaction mixture containing only reactants, the reaction quotient is __ |
infinite (Qc = infinitey) |
In a reaction mixture containing only products, the reaction quotient is __ |
one (Qc = 1) |
In a reaction mixture containing both reactants and products, each at a concentration of 1M, the reaction quotient is __ |
reaction toward equilibrium |
The reaction quotient is useful because the value of Q relative to K is a measure of the progress of the __ |
equal |
At equilibrium, the reaction quotient is __ to the equilibrium constant |
less than |
If Q is__ K, Q must therefore get larger as the reaction proceeds toward equilibrium. Q becomes larger as the reactant concentration decreases and the product concentration increases – the reaction proceeds to the right |
greater than |
If Q is __ K, Q must therefore get smaller as the reaction proceeds toward equilibrium. Q gets smaller as the reactant concentration increases and the product concentration decreases – the reaction proceeds to the left |
equal to |
If Q is __ K the reaction is at equilibrium – the reaction will not proceed in either direction |
progress of a reaction |
The reaction quotient (Q) is a measure of the __ toward equilibrium |
goes to the right (toward products) goes to the left (toward reactants) is at equilibrium |
Q < K ; reaction __ Q > K ; reaction __ Q = K ; reaction __ |
reactant or product |
Calculating equilibrium concentrations of reactants or products from the equilibrium constant allow us to calculate the amount of a __ at equilibrium |
(1) finding equilibrium concentrations when we know the equilibrium constant and all but one of the equilibrium concentrations of the reactants and products; and (2) finding equilibrium concentrations when we know the equilibrium constant and only initial |
Calculating equilibrium concentrations of reactants or products from the equilibrium constant can be divided into what two categories? |
1. Using the balanced equation as a guide, prepare a table showing the known initial concentrations of the reactants and products (ICE table) 2. Use the initial concentrations to calculate the reaction quotient (Q) for the initial concentrations. Compare Q to K to predict the direction in which the reaction will proceed. 3. Represent the change in the concentration of one of the reactants or products with the variable x. Define the changes in the concentrations of the other reactants or products in terms of x 4. Sum each column for each reactant and product to determine the equilibrium concentrations in terms of the initial concentrations and the variable x 5. Substitute the expressions for the equilibrium concentrations (from step 4) into the expression for the equilibrium constant. Using the given value of the equilibrium constant, solve the expression for the variable x. 6. Substitute x into the expressions for the equilibrium concentrations of the reactants and products (from step 4) and calculate the concentrations 7. Check your answer by substituting the computed equilibrium values into the equilibrium expression. The calculated value of K should match the given value of K |
what is the procedure for finding equilibrium concentrations from initial concentrations and the equilibrium constant? |
1. Using the balanced equation as a guide, prepare a table showing the known initial partial pressures of the reactants and products 2. Use the initial partial pressures to calculate the reaction quotient (Q). compare Q to K to predict the direction in which the reaction will proceed 3. Represent the change in the partial pressure of one of the reactants or products with the variable x. Define the changes in the partial pressures of the other reactants or products in terms of x 4. Sum each column for each reactant and product to determine the equilibrium partial pressures in terms of the initial partial pressures and the variable x 5. Substitute the expressions for the partial pressures (from step 4) into the expression for the equilibrium constant. Use the given value of the equilibrium constant to solve the expression for the variable x 6. Substitute x into the expressions for the equilibrium partial pressures of the reactants and products (from step 4) and calculate the partial pressures 7. Check your answer by substituting the calculated equilibrium partial pressures into the equilibrium expression. The calculate value of K should match the given value of K |
what is the procedure for finding equilibrium partial pressures when you are given the equilibrium constant and initial partial pressures? |
1. Using the balanced equation as a guide, prepare a table showing the known initial concentrations of the reactants and products 2. Use the initial concentrations to calculate the reaction quotient (Q). Compare Q to K to predict the direction that the reaction will proceed 3. Represent the change in the concentration of one of the reactants or products with the variable x. Define the changes in the concentrations of the other reactants or products with respect to x 4. Sum each column for each reactant and product to determine the equilibrium concentrations in terms of the initial concentrations and the variable x 5. Substitute the expressions for the equilibrium concentrations (from step 4) into the expression for the equilibrium constant. Use the given value of the equilibrium constant to solve the expression for the variable x.
in this case, the resulting equation is cubic in x. Although cubic equations can be solved, the solutions are not usually simple. However, since the equilibrium constant is small, we know that the reaction does not proceed very far to the right. Therefore, x will be a small number and can be dropped from any quantities in which it is added to or subtracted from another number (as long as the number itself is not too small)
check whether your approximation was valid by comparing the calculated value of x to the number it was added to or subtracted from. The ratio of the two numbers should be less than 0.05 ( or 5%) for the approximation to be valid. If approximation is not valid proceed to step 5a
5a. if the approximation is not valid, you can either solve the equation exactly (by hand or with your calculator), or use the method of successive approximations. In this case, we use the method of successive approximations substitute the value obtained for x in step 5 back into the original cubic equation, but only at the exact spot where x was assumed to be negligible and then solve the equation for x again. Continue this procedure until the value of x obtained from solving the equation is the same as the one that is substituted into the equation
6. Substitute x into the expressions for the equilibrium concentrations of the reactants and products (from step 4) and calculate the concentrations 7. Check your answer by substituting the calculated equilibrium values into the equilibrium expression. The calculated value of K should match the given value of K. Note that the approximation method and rounding errors could cause a difference of up to about 5% when comparing values of the equilibrium constant |
what is the procedure for finding equilibrium concentrations from initial concentrations in cases with a small equilibrium constant? |
(a) the x is small approximation is most likely to apply to a reaction with a small equilibrium constant and an initial concentration of reactant that is not too small. The bigger the equilibrium constant and the smaller the initial concentration of reactant, the less likely that the x is small approximation will apply |
For the generic reaction, A(g) « B(g), consider each value of K and initial concentration of A. For which set will the x is small approximation most likely apply? (a) K = 1.0 x 10-5; [A] = 0.250M (b) K = 1.0 x 10-2; [A] = 0.250M (c) K = 1.0 x 10-5; [A] = 0.00250M (d) K = 1.0 x 10-2; [A] = 0.00250M |
minimize the disturbance |
Le Chatelier’s principle states that the chemical system will respond to __ when a chemical system already at equilibrium is disturbed |
Le Chatelier’s principle |
__: when a chemical system at equilibrium is disturbed, the system shifts in a direction that minimizes the disturbance |
changing the concentration of a reactant or product, changing the volume or pressure, and changing the temperature |
how can we distrub a system in chemical equilibrium? |
< right (in the direction of the products) |
If a chemical system is at equilibrium, increasing the concentration of one or more of the reactants (which makes Q __ K) causes the reaction to shift to the __ |
> left (in the direction of the reactants) |
If a chemical system is at equilibrium increasing the concentration of one or more of the products (which makes Q __ K) causes the reaction to shift to the __ |
> left (in the direction of the reactants) |
If a chemical system is at equilibrium decreasing the concentration of one or more of the reactants (which makes Q __ K) causes the reaction to shift to the __ |
< right (in the direction of the products) |
If a chemical system is at equilibrium decreasing the concentration of one or more of the products (which makes Q __ K) causes the reaction to shift to the __ |
pressure |
Changing the volume of a gas (or a gas mixture) results in a change in __ |
inversely increase decrease |
Pressure and volume are __ related: a decrease in volume causes an __ in pressure, and an increase in volume causes a __ in pressure |
minimize that change |
If the volume of a reaction mixture at chemical equilibrium is changed, the pressure changes and the system will shift in a direction to __ |
lower |
From the ideal gas law (PV = nRT), we know that lowering the number of moles of a gas (n) results in a __ pressure (P) |
higher |
From the ideal gas law (PV = nRT), we know that increasing the number of moles of gas (n) results in a __ pressure (P) |
increases do not change no does not shift in either direction |
If we keep the volume the same, but increase the pressure by adding an inert gas to the mixture, the overall pressure of the mixture __, but the partial pressures of the reactants and products __. There is __ effect and the reaction __ |
has the fewer moles of gas particles |
If a chemical system is at equilibrium decreasing the volume causes the reaction to shift in the direction that __ |
greater number of moles of gas particles |
If a chemical system is at equilibrium increasing the volume causes the reaction to shift in the direction that has the __ |
produces no effect on the equilibrium |
If a chemical system is at equilibrium, if a reaction has an equal number of moles of gas on both sides of the chemical equation, then a change in volume __ |
no effect on the equilibrium |
If a chemical system is at equilibrium, adding an inert gas to the mixture at a fixed volume has __ |
temperature |
In considering the effect of a change in volume, we are assuming that the change in volume is carried out at a constant __ |
pressure |
In considering the effect of a change in temperature, we are assuming that the heat is added (or removed) at constant __ |
counter that change |
If the temperature of a system at equilibrium is changed, the system will shift in a direction to __ |
product in an exothermic reaction |
An exothermic reaction (negative delta H) emits heat and we can think of heat as a __ |
reactant in an endothermic reaction |
An endothermic reaction (positive delta H) absorbs heat and we can think of heat as a __ |
shift left reactants products smaller |
At constant pressure, raising the temperature of an exothermic reaction (think of this as adding heat) is similar to adding more product, causing the reaction to __. The new equilibrium mixture will have more __ and fewer __ and therefore a __ value of K |
equilibrium constant |
Changing the temperature does change the value of the __ |
exothermic |
At constant pressure, lowering the temperature of an __reaction, causes the reaction to shift right, releasing heat and producing more products because the value of K has increased. |
shift right products increased |
For an endothermic reaction at constant pressure, raising the temperature (adding heat) causes the reaction to __ to absorb the added heat and producing more __ because the value of K has __ |
shift left products lowering |
For an endothermic reaction at constant pressure, lowering the temperature (removing heat) of a reaction mixture causes the reaction to __, releasing heat, forming less __, and __ the value of K |
Increasing |
In an exothermic chemical reaction, heat is a product. __ the temperature causes an exothermic reaction to shift left (in the direction of the reactants); the value of the equilibrium constant decreases |
Decreasing |
In an exothermic chemical reaction, heat is a product. __ the temperature causes an exothermic reaction to shift right (in the direction of the products); the value of the equilibrium constant increases |
Increasing |
In an endothermic chemical reaction, heat is a reactant. __ the temperature causes an endothermic reaction to shift right (in the direction of the products); the equilibrium constant increases |
Decreasing |
In an endothermic chemical reaction, heat is a reactant. __ the temperature causes an endothermic reaction to shift left (in the direction of the reactants); the equilibrium constant decreases |
endothermic direction |
Adding heat favors the __ |
exothermic direction |
Removing heat favors the __ |
metastable |
Systems that are not in thermodynamic equilibrium but are kinetically stable are called __. |
concentration, pressure, temperature |
for a system at equilibrium, the principle can be used to qualitatively predict the effects of changes in what |