AP Chemistry Midterm Review – Flashcards

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Mercury
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Polyatomic Ion Hg2^+2
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Ammonium
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Polyatomic Ion NH4^+1
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Nitrite
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Polyatomic Ion NO2^-1
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Nitrate
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Polyatomic Ion NO3^-1
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Sulfite
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Polyatomic Ion NO3^-1
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Sulfate
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Polyatomic Ion SO4^-2
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Hydrogen Sulfate
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Polyatomic Ion HSO4^-1
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Hydroxide
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Polyatomic Ion OH^-1
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Cyanide
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Polyatomic Ion CN^-1
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Phosphate
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Polyatomic Ion PO4^-3
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Hydrogen Phosphate
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Polyatomic Ion PO4^-3
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Dihydrogen Phosphate
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Polyatomic Ion H2PO4^-1
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Thiocyanate
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Polyatomic Ion NCS^-1
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Carbonate
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Polyatomic Ion CO3^-2
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Hydrogen Carbonate
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Polyatomic Ion HCO3^-1
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Hypochlorite
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Polyatomic Ion ClO^-1
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Chlorite
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Polyatomic Ion ClO2^-1
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Chlorate
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Polyatomic Ion ClO3^-1
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Perchlorate
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Polyatomic Ion ClO4^-1
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Acetate
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Polyatomic Ion C2H3O2^-1
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Permanganate
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Polyatomic Ion MnO4^-1
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Dechromate
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Polyatomic Ion Cr2O7^-2
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Chromate
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Polyatomic Ion CrO4^-2
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Peroxide
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Polyatomic Ion O2^-2
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Oxalate
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Polyatomic Ion C2O^-2
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mega
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M 10^6
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kilo
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k 10^3
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deka
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da 10^1
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deci
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d 10^-1
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centi
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c 10^-2
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milli
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m 10^-3
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micro
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µ 10^-6
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nano
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n 10^-9
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hydrochloric acid
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Strong Acid HCl
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hydrobromic acid
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Strong Acid HBr
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hydroiodic acid
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Strong Acid HBr
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perchloric acid
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Strong Acid HClO4
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nitric acid
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Strong Acid HNO3
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periodic acid
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Strong Acid HIO4
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sulfuric acid
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Strong Acid H2SO4
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chloric acid
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Strong Acid HClO3
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Synthesis Reaction
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Reaction involves ELEMENTS combining to form a SINGLE substance e.g.: A solid piece of sodium is dropped into a container of fluorine gas 2Na + F2 → 2NaF
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Decomposition Reaction
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Reaction involves only ONE REACTANT, products are SIMPLE SALTS and OXIDE GASES.....CARBONATE = CO2 + other......HYDROXIDE = H2O + other Memorize: 2H2O2 → 2H2O + O2 (hydrogen peroxide)....and... 2KClO3 → 2KCl + 3O2 (potassium chlorate) e.g.: Solid calcium carbonate is heated CaCO3 → CO2 + CaO
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Combustion Reaction
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Reaction when a substance COMBINES with OXYGEN (O2).....HYDROCARBON = H2O + CO2.....NON-HYDROCARBON = combine oxygen with non-hydrocarbon e.g.: Octane (C8H18) is burned 2C8H18 + 25O2 → 16CO2 + 18H2O
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Mixing Two Salt Solutions Reaction
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KNOW SOLUBILITY RULES.....write the net ionic equation and be able to identify spectator ions e.g.: A solution of iron III sulfate is added to a solution of tin II chloride Sn^+2 + 2Fe^+3 → Sn^+4 + 2Fe^+2
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Simple Redox Reaction
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Oxidized, reducing agent = lose electron Reduced, oxidizing agent = gain electron e.g.: A piece of zinc is oxidized by placing it into a solution of aluminum nitrate 3Zn + 2Al^+3 → 3Zn^+2 + 2Al
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Complex Redox Reaction
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Use the "Common Oxidation State Changes" page to predict products and HALF-REACTION METHOD to solve it in both an acid and base environment to balance the reaction e.g.: A solution of tin II chloride is added to an acidified solution of potassium permanganate 5Sn^+2 + 2MnO4^- + 16H^+ → 5Sn^+4 + 2Mn^+2 + 8H2O
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Hydrolysis Pure Alkali Metal Reaction
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2X + 2H2O → 2X^+2 + 2OH^- + H2
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Hydrolysis Alkali Earth Metal Reaction
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X + 2H2O → X(OH)2 + H2
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Hydrolysis Alkali Metal Hydride Reaction
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XH + H2O → X^+ + OH^- + H2
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Hydrolysis Alkali Earth Metal Hydride Reaction
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XH2 + 2H2O → X(OH)2 + 2H2
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Hydrolysis Alkali Metal Oxide Reaction
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X2O + H2O → 2X^+ + 2OH^-
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Hydrolysis Alkali Earth Metal Oxide Reaction
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XO + H2O → X(OH)2
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Hydrolysis Nonmetallic Oxide Reaction
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General Formula = nonmetallic oxide + water → acid If the acid is a STRONG ACID then a H is removed and it becomes H^+ + (strong acid - a H)^-
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Strong Acid and Strong Base Reaction
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H^+ + OH^- → H2O Strong Bases tend to end with HYDROXIDE
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Strong Acid and Weak Base Reaction
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H^+ + weak base → (weak base + H)^+ Weak Bases tend to end with INE
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Weak Acid and Strong Base Reaction
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OH^- + strong base → H2O + (strong base)^- Strong Bases tend to end with HYDROXIDE
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Weak Acid and Weak Base Reaction
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weak acid + weak base → (weak base)^+ + (weak acid)^- Weak Bases tend to end with INE
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OH^-
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Base pH<7 Proton acceptors
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H^+
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Acid pH>7 Proton donors
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Solubility Rules
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(1) All Nitrate (No3-1) salts are soluble (2) Most salts containing the alkali metal ions (Li+, Na+, K+, Cs+, Rb+) and the ammonium ion (NH4+) are soluble (3) Most chloride, bromide, and iodide salts are soluble. Notable exceptions are salts containing the ions Ag+, Pb+2, and Hg2+2 (4) Most sulfate salts are soluble. Notable exceptions are BaSO4, PbSO4, Hg2SO4, and CaSO4 (5) Most hydroxide salts are nonsoluble. The important soluble hydroxides are NaOH and KOH. The compounds Ba(OH)2, Sr(OH)2, and Ca(OH)2 are soluble (6) Most sulfide (S-2), carbonate (Co3-2), chromate (CrO4-2), and phosphate (PO4-3) salts are nonsoluble
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Sig Figs
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Any non-zero digit is significant Any zero to the left of non-zero digits is not significant Any zero between significant digits is significant Zeroes at the end of the number and to the right of the decimal point are significant Zeroes at the end of the number without a decimal point are not significant
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Density
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D=M/V
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JJ Thompson
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Cathode ray tube Plum Pudding Model : found that atoms must have negative particles (electrons)
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Milikan
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Spray oil particles in a chamber Found the mass of electron
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Rutherford
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Gold Foil Experiment Atom is mostly empty, small positive center
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Dalton
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First person to publish a table of relative atomic masses Some were were wrong (didn't know about diatomic elements)
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Average atomic mass of an element
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(mass of isotope)x(percent present) + (mass of another isotope)x(percent present) = amu
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Avogadro's Number
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6.022 x 10^23 = 1 mole
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Mass Percent in a Compound
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Take the mass of each element and multiply by how many moles of each element is present. Add all the numbers together (A). To find the mass percent, divide the total mass of the element by the total mass of the compound (A) and multiply by 100.
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Empirical Formula
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A formula showing the lowest whole number ratio of atoms in a compound Find out how many moles are present for each element and divide it by the element with the smallest moles present to get the empirical formula.
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Molecular Formula
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A formula that tells how many atoms are present in a molecule Take the molar mass of the molecular formula and divide it by the molar mass of the empirical formula which will give you a whole number. Times the values in the empirical formula by this whole number to find the molecular formula
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"like dissolves like"
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Polar dissolves polar Non~polar dissolves non~polar Polar dissolves ionic (cause it's polar) Water is polar
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Molarity
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M moles/L expression of concentration
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Dilution
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M1V1=M2V2
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Precipitation
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Ax+Bz → Az + Bx cations always go first know solubility rules
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Cation
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Positive ion
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Anion
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Negative ion
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Molecular equation
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Gives overall reaction, good for stoichiometry
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Complete ionic equation
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All strong electrolytes are shown as ions
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Net ionic equation
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Only shows species that go through chemical change Spectator ions left out
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Oxidation States
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OIL RIG (1) An element (by itself) 0 (2) An ion (with the charge) charge of the ion (3) Fluorine in its compound -1 (4) Oxygen (except: peroxides) -2 (-1) (5) Hydrogen +1
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Kinetic Energy
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KE = (1/2)mv^2
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Work
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measure in joules (J) Force x Distance (FxD) OR Pressure x Change in Volume (Px∆V) Energy loss (system expands) Work is negative Energy gained (system contracts) Work is positive
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Exothermic
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Heat flows out of the system
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Endothermic
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Hear flows into system
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∆E
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q (heat) + w (work) -∆E system loses NRG +∆E system gains NRG
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∆H/Enthalpy change/"heat of reaction"
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q (heat) = mC∆T endothermic ∆H>0 exothermic ∆H<0 ∆Hrxn = ∆Hproducts - ∆Hreactants "Standard State" = 25°C, 1 atm, 1M concentration
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Heat Equation
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q = mC∆T (J)
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Wavelength
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λ (m)
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Speed of light
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c = 3.00 x 10^8 m/s
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Frequency
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ν (s^-1) or (Hz)
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∆E per photon
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hν (J per photon) h = 6.626 x 10^-34 Js
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Bohr Model
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E = -2.178 x 10^-18 J (z^2/n^2)
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Heisenberg
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Heisenberg Uncertainty Principle limit how certain we are of position and momentum at the same time, radiation used to find particle changes the particle's momentum
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Aufbau
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Aufau Principle electrons fill in order from lowest to highest energy Pauli Exclusion Principle: no two electrons in the same atom can have the same four quantum numbers ↓↑ yes ↑↑no ↓↓no
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Hund
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Hund's rule have to fill all the boxes before the second time goes through ↑ ↑ ↑ yes ↑↓↑ no
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First ionization energy
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↑→ big atom = low IE small atom = big IE
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Atom size
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↓← effective nuclear charge = protons - core e⁻
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(2,0)
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sp linear 180°
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(3,0)
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sp² trigonal planar 120°
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(2,1)
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sp² bent <120°
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(4,0)
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sp³ tetrahedral 109.5°
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(3,1)
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sp³ trigonal pyramidal <109.5°
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(2,2)
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sp³ bent <109.5°
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(1,3)
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sp³ linear/terminal NA
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(5,0)
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sp³d trigonal bipyramidal 90° + 120° + 180°
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(4,1)
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sp³d seesaw 90° + 120° + 180°
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(3,2)
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sp³d T-shaped 90° + 180°
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(2,3)
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sp³d linear 180°
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(6,0)
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sp³d² octahedral 90° + 180°
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(5,1)
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sp³d² square pyramidal 90°
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(4,2)
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sp³d² square planar 90°
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Single Bond
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Sigma bond (δ)
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Double Bond
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Sigma bond and Pi bond
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Triple Bond
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Sigma bond and 2 Pi bonds
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Collision Theory
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Particles must move toward each other Particles must hit with proper orientation Particles must hit with sufficiently high energy Particles will separate after reaction occurs
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Eareverse
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∆H + Eaforward
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Catalyst
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lowers the activation hill does NOT change the PE of the products of reactants does NOT change ∆H does NOT affect EQBM
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Activation Energy
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k=Ae^-Ea/RT R = 8.314 J/molK. Ea = J/mol. T = K. A = frequency factor
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Differential Rate Law
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K = L^(n-1)/mol^(n-1)s "0" change in [] does not affect anything "1" [] changes, so does the rate (double [], double rate) "2" [] changes, the rate is squared (double [], x4 rate., triple [], x9 rate)
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Equilibrium constant
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nA + mB ↔ pC + qD K=([C]^p[D]^q)/([A]^n[B]^m) Knew = (Koriginal)⁻¹ →rxn flips Knew = (Koriginal)^n →n = factor Kp = K(RT)^∆n → R=.08206 ∆n = coefficients of prod. - react.
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Reaction Quotient
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Q=([C]₀^p[D]₀^q)/([A]₀^n[B]₀^m) Q=K system already at equilibrium Q>K system will shift LEFT, too may products Q<K system will shift RIGHT, too many reactants
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Change in pressure
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P↑P↓→side w/ more less gas ions P↓P↑→side w/ more gas ions
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Change in temperature
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heat↑heat↓→side w/o heat heat↓heat↑→side w/ heat
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Change in concentration
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→opposite side
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