MCAT – Orgo – Flashcards

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question

What do these prefixes describe?

Vinyl

Allyl

Methylene

answer

Vinyl= monosubstituted ethylenes (vinyl chloride= CH2=CHCl)

 

Allyl= C3 substituted propylene (allyl bromide=

CH2=CHCH2Br)

 

Methylene= -CH2 group (methylene cyclohexane= a cyclohexane with a CH2 group...double bond from cyclic C to a CH2)

 

question
      Name these common substituents
1.   CH3          2. CH3         3.  CH3
      |                |                |
H3C-C-       H3C-C-CH2-      HC-    
      |                |                |
      CH3              CH3              CH3
 
      4.    CH3                 5.      CH3
             |                          | 
CH3-CH2-CH-                CH3-CH-CH2-
answer
1. t-butyl (tert-butyl)
2. neopentyl
3. isopropyl
4. sec-butyl
5. isobutyl
question

Common names for ethene and ethyne.

 

When naming a molecule with both a double and triple bond in it, which gets the lower carbon number?

answer

Ethene= ethylene

Ethyne= acetylene

 

When both in the same molecule, the double bond gets the lower number

CH3CH=CH-C=C-CH3

2-hexen-4-yne

question

What is a vicinal?

What is a geminal?

 

Why are geminals/hydrates not often seen?

answer

Vicinals= diols with hydroxyl groups on adjacent carbons

Geminal aka hydrates= diols with hydroxyl groups on the same carbon

 

Geminals/hydrates not often seen because they spontaneously lose water and produce carbonyls.

question

What is an ether?

 

What is a 3-membered cyclic ether called?

 

Common names for:

methanal

ethanal

propanal

answer

Ether=   R-O-R

 

3-membered cyclic ethers= oxiranes or epoxides - or ethylene oxide

 

Methanal= Formaldehyde

Ethanal= Acetaldehyde

Propanal= Propionaldehyde

question

Common names for:

2-propanone

methanoic acid

ethanoic acid

propanoic acid

answer

2-propanone= acetone

methanoic acid= formic acid

ethanoic acid= acetic acid

propanoic acid= propionic acid

question

Prefix and suffix for:

esters

acyl halides

 amides

nitriles/cyanide

 thiols

imines

ethers

...and just prefixes for:

sulfides

nitros

azides

diazos

answer
                        Prefix:                 Suffix:
Esters           alkoxycarbonyl-       -oate
Acyl halides     halocarbonyl-      -oyl halide
Amides               amido-                 -amide
Nitriles/Cyanide   cyano-                  -nitrile
Thiols (RSH)     sulfhydryl-                -thiol 
Imines (R2C=NR'); imino- ; ; ; ; ; ; ; -imine
Ethers ; ; ; ; ;;;;;; alkoxy-;;;;;;;;;;;;;;;;; -ether
Sulfide (R2S) ; ;; alkothio- ; ; ;
Nitros (RNO2) ; ;;;; nitro-
Azides (RN3) ; ; ;;; azido-
Diazo (RN2+) ; ; ;;; diazo-
; ; ;
question

What are structural/confirmational isomers?

;

What are enantiomers?

;

;

answer

Structure/confirmational isomers only share a molecular formula.

;

Enantiomers are chiral objects that are nonsuperimposable mirror images.

question

Put the following bases in order from strongest to weakest: RCO2-, ROH, HO-, RO-, H2O

;

Put the following nucleophiles in order from strongest to weakest when in a protic solvent: CN-, HO-, Br-, I-, F-, H2O, Cl-, RO-

;

Put the following nucleophiles in order from strongest to weakest in when in an aprotic solvent: Cl-, Br-, F-, I-

;

Put the following leaving groups in order of best to worst:

Cl-, Br-, F-, I-

answer

Base Strength:

RO-;OH-;RCO2-;ROH;H2O

;

Nucleophile strength in a protic solvent (larger atoms=stronger Nu in protic solvents:

CN-;I-;RO-;HO-;Br-;Cl-;F-;H2O

;

Nucleophile strength in an aprotic solvent (strong bases=stronger; Nu in aprotic solvents):

;F-;Cl-;Br-;I-

;

Leaving group strength (weak base=better LG):

I-;Br-;Cl-;F-

;

question

Are SN1 and SN2 reactions favored in protic or aprotic solvents?

;

What happens to the stereochemistry of SN1 and SN2 reactions?

answer

SN1 reactions are favored in polar protic solvents.

SN2 reactions are favored in polar aprotic solvents.

;

If the reactant is optically active, SN1 reactions produce racemic mixtures.

If the reactant is optically active, SN2 reactions produce a product with an inversion of stereochemistry (still optically active).

question

As you increase branching, what happens to the boiling point and density?

As molecular weight increases, what happens to the melting and boiling points and density?

answer

More branching means decreased boiling point and decreased density (decrease the surface area so decrease intermolecular forces).

As molecular weight increases, melting and boiling points also increase and density increases.

question

Addition of cold, dilute KMnO4 to an alkene yields...

;

Addition of hot, basic KMnO4 to a non-terminal alkene...

answer

Addn of cold, dilute KMnO4 to an alkene yields a 1,2 diol (vicinal diol/glycol), syn orientation.

;

Addn of hot, basic KMnO4 cleaves the non-terminal alkene to produce a carboxylic acid and carbon dioxide...if the double bonded carbon is disubstituted, it produces a ketone.

question

Steps for the addition of HX to an alkene.

;

Steps for the addition of X2 to an alkene.

answer

Addition of HX to an alkene:

step 1: Addn of H+ to less highly substituted C to form a stable C+ (Markovnikov's)

step 2: Addn of halide to the positive C

 

Addition of X2 to an alkene:

step 1: double bond displaces X- and forms a cyclic halonium ion

step 2: X- attacks to form a dihalide compound in anti addition.

question

Steps for addition of H2O to an alkene.

 

Steps for addition of a free radical (such as Br) to an alkene/alkyne.

answer
Addition of H2O to an alkene:
step 1: potonation of the double bond (Markovnikov's) to form a stable C+
step 2: addn of H2O to positively charged C
step 3: loss of H+ to form an alcohol;
;
Addition of a free radical to an alkene:
step 1: addn of the free radical to the less substituted C (anti-Markovnikov b/c adds H second)
step 2: addn of H to the free radical C
question

Steps of hydroboration and what it produces.

;

Products of ozonolysis with Zn/H2O.

;

Products of ozonolysis with NaBH4/CH3OH.

answer
Hydroboration:
step 1: B attaches to the less sterically hindered C (anti-Markovnikov b/c H adds second)
step 2: oxidation-hydrolysis with peroxide and an aqueous base (replacement of BH3 with OH)
...produces an alcohol in an anti-Markovnikov fasion with syn addition (of H and OH).
;
Ozonolysis with Zn/H2O cleaves the double bond to form carbonyls (aldehydes or ketones...not carboxylic acids).
;
Ozonolysis with NaBH4/CH3OH produces alcohols.
question

What do peroxycarboxylic acids (such as CH3CO3H and mcpba) do to alkenes? What is the product?

;

Polymerization occurs under...

;

How does the boiling point compare between internal alkenes/alkynes and terminal alkenes/alkynes?

answer

Peroxycarboxylic acids oxidize alkenes and produce oxiranes.

;

Polymerization occurs under high temperatures and high pressures.

;

Internal alkenes/alkynes boil at higher temps than terminal alkenes/alkynes.

question
Elimination of 2HX's from a vicinal dihalide to form an alkyne requires...
answer
Elimination of 2HX's for a vicinal dihalide to form an alkyne requires high temps and a strong base.
question
Difference between constitutional and conformational isomers.
answer

Constitutional isomers= different atom connectivity

Conformational isomers= different 3D arrangement

question

What are the structures of the following amine compounds:

Amide

;Carbamate/Urethane

Isocyanate

Enamine

Imine

Nitrile/Cyanide

Nitro

Diazo

Azide

answer

Amide:; O;;;;;; (carboxyl + amine)

; ; ; ; ;;; ||

;;;;;;;;; RCNR2 ; ; ;;

Carbamate/Urethane: ; O;;;;; (Ester + amine)

; ; ; ; ; ; ; ; ; ; ; ; ; ; ; ; ;;; ||

; ; ; ; ; ; ; ; ; ; ; ; ; ; ; ; ROCNR2

Isocyanate: ;; R=O=C=NR; (add alcohol-;carbamate)

Enamine: ; R2=CRNR2 (amine equivalent of anenol)

Imine:; R2C=NR; (carbon=nitrogen)

Nitrile/Cyanide:; C=N; (C triple bonded to N)

Nitro: -NO2

Diazo: R2C=N=N; (N2 group)

Azide: R-N=N=N; (N3 group)

;

;

;

question

alkyl halide + ammonia -;....+base-;

(CH3Br + NH3 -;_____+NaOH-;_____)

answer

Alkyl halide + ammonia -; alkylammonium halide salt

alkylammonium halide salt + base -; alkyl amine

CH3Br+NH3-; CH3NH3+Br-+NaOH-; CH3NH2 + NaBr +H2O

question

What is Markovnikov's Rule?

 

What conditions often cause free radical addition?

answer

Markovnikov's= When adding a protic acid HX to a double bond, the H will add to the less substituted carbon, and the X will add to the more substituted carbon after.

;

Peroxides, oxygen, and UV light cause free radical addition (which is anti-markovnikov...free radical adds before the free H).

question

How can you form an amine from a nitro compound?

;

How can you form an amine from a nitrile?

;

How can you form an amine from an imine?

answer

Nitro compound + reducing agent such as Zn or Fe in dilute HCl turns the nitro group into a primary amine.

;

Nitrile compound + hydrogen and a catalyst or LAH creates a primary amine

CH3CH2C=N + LAH -; CH3CH2CH2NH2

;

Aldehyde or ketone + ammonia -; Imine

Imine + hydrogen and a catalyst -; amine

; O;;;;;;;;;;;;;;;;;;;;; NH;;;;;;;;;;;;;;;;;;;;;;;;;;;;; NH2

; ||;; +; NH3 -; ||;; + H2-Ni/RaneyNi -;; |

RCR ;;;;;;;;;;;;; RCR;;;;;;;;;;;;;;;;;;;;;;;;;;;; RCR

question

What is Zaitsev's Rule?

 

 

answer
Zaitsev's rule states that if an elimination reaction can produce two products, the more highly substituted double bond will be the major product.
question

Describe the frequencies these bonds would absorb in an IR spectrum:

Carbonyl; (C=O)

Alcohol or Acid (O-H)

Amine (N-H)

answer

Carbonyl (C=O) ~1750

;Alcohol or Acid (O-H) ~3000 (broad)

Amine (N-H) ~3000 (sharp)

question
How can you form an amine from an amide?
answer

Amide + LAH -; amine

; O

; ||;;;; +; LAH -;

RCNH2;;;;;;;;;;;;;; RCNH2

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