Gre Chemistry – Flashcards

Flashcard maker : Kenneth Wheeler
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Exo
answer

in bicyclic systems indicates that the subsituent on a bridge is on the side of the smaller bridge

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endo
answer

substituent on large bridge of bicyclic systems

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ozonolysis
answer

alkenes -> alcohols/aldehydes/acids
alcohol-from sodium borohydride
aldehydes-from zn, pph3, dimethyl sulfide
acids-peroxides
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hygroscpic
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substances that attract water easily and make it hard to use at standards
ex. KOH, NaOH
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Cyclic voltammetry
answer

generally used to study the electrochemical properties of an analyte in solution.
-marked by a cycle of potential
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1st law of thermodynamics
answer

The increase in the internal energy of a system is equal to the amount of energy added by heating the system, minus the amount lost as a result of the work done by the system on its surroundings.

E(universe) doesn’t change

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Frank-Condon Principle
answer

during an electronic transition, a change from one vibrational energy level to another will be more likely to happen if the two vibrational wave functions overlap more significantly.
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signal to noise ratio
answer

averaging scans improves by a squaree root

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Activating Substituents
ortho & para-Orientation
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–O(–)
–OH
–OR
–OC6H5
–OCOCH3
-NH2
–NR2
–NHCOCH3
–R
–C6H5
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Deactivating Substituents
meta-Orientation
answer

–NO2
–NR3(+)
–PR3(+)
–SR2(+)
–SO3H
–SO2R –CO2H
–CO2R
–CONH2
–CHO
–COR
–CN
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Deactivating Substituents
ortho & para-Orientation
answer

–F
–Cl
–Br
–I
–CH2Cl
–CH=CHNO2
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beta-keto esters
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prone to decarboxylation following hydrolysis

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geminal
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if the two substituents are on the same carbon

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vicinal
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two substituents on adjacent carbon atoms

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vinylic
answer

attached to the carbon atom of a double bond

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spinel structures
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any of a class of minerals of general formulation A2+B3+2O2-4 which crystallise in the cubic (isometric) crystal system, with the oxide anions arranged in a cubic close-packed lattice and the cations A and B occupying some or all of the octahedral and tetrahedral sites in the lattice. A and B can be divalent, trivalent, or quadrivalent cations, including magnesium, zinc, iron, manganese, aluminium, chromium, titanium, and silicon. Although the anion is normally oxide, structures are also known for the rest of the chalcogenides. A and B can also be the same metal under different charges, such as the case in Fe3O4 (as Fe2+Fe3+2O2-4).

pinel – MgAl2O4, after which this class of minerals is named

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ionic strength
answer

given by 1/2(c1z1^2 + c2z2^2 etc)

where c is the concentration of the species and z is the charge

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polarography
answer

a subclass of voltammetry where the working electrode is a dropping mercury electrode (DME), useful for its wide cathodic range and renewable surface

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gouy balance
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is a device for measuring the magnetic susceptibility of metals or metal complexes.
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jahn-teller distortion
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not for d3, d10 and d8 but for everything else if octahedral

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Lux-Flood definition of acidity
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describes an acid as an oxide ion acceptor and a base as an oxide ion donor. For example:
MgO (base) + CO2 (acid) → MgCO3
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Hard Soft Acid Base principle
answer

‘Hard’ applies to species that are small, have high charge states, and are weakly polarizable. ‘Soft’ applies to species that are large, have low charge states and are strongly polarizable. Acids and bases interact, and the most stable interactions are hard-hard and soft-soft. This theory has found use in organic and inorganic chemistry

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nucleophilic aromatic substitution vs. electrophilic
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attack at aromatic carbon with good leaving group vs. attack at unsbustituted carbon
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Hartree-Fock (SCF)
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In computational physics and chemistry, the Hartree–Fock (HF) method is an approximate method for the determination of the ground-state wave function and ground-state energy of a quantum many-body system
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Koopmans’ theorem
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states that in closed-shell Hartree-Fock theory, the first ionization energy of a molecular system is equal to the negative of the orbital energy of the highest occupied molecular orbital (HOMO).
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C1
answer

E No symmetry, chiral CFClBrH, lysergic acid

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Cs
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E σh Planar, no other symmetry thionyl chloride, hypochlorous acid

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Ci
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E i Inversion center anti-1,2-dichloro-1,2-dibromoethane

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C∞v
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E 2C∞ σv
linear hydrogen chloride, dicarbon monoxide
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D∞h
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E 2C∞ ∞σi i 2S∞ ∞C2 linear with inversion center dihydrogen, azide anion, carbon dioxide

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C2
answer

E C2 “open book geometry,” chiral hydrogen peroxide

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C3
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E C3 propeller, chiral triphenylphosphine

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C2h
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E C2 i σh Planar with inversion center trans-1,2-dichloroethylene

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C4v
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E 2C4 C2 2σv 2σd square pyramidal xenon oxytetrafluoride

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D3
answer

E C3(z) 3C2 triple helix, chiral Tris(ethylenediamine)cobalt(III) cation

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D2h
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E C2(z) C2(y) C2(x) i σ(xy) σ(xz) σ(yz) planar with inversion center ethylene, dinitrogen tetroxide, diborane
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D3h
answer

E 2C3 3C2 σh 2S3 3σv trigonal planar or trigonal bipyramidal boron trifluoride, phosphorus pentachloride

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D4h
answer

E 2C4 C2 2C2′ 2C2 i 2S4 σh 2σv 2σd square planar xenon tetrafluoride

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D5h
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E 2C5 2C52 5C2 σh 2S5 2S53 5σv pentagonal ruthenocene, eclipsed ferrocene, C70 fullerene

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D6h
answer

E 2C6 2C3 C2 3C2′ 3C2 i 3S3 2S63 σh 3σd 3σv hexagonal benzene, bis(benzene)chromium

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D2d
answer

E 2S4 C2 2Ch 2C2′ 2σd 90° twist allene, tetrasulfur tetranitride

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D2d
answer

E 2S4 C2 2Ch 2C2′ 2σd 90° twist allene, tetrasulfur tetranitride

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D3d
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E 2C3 3C2 i 2S6 3σd 60° twist ethane (staggered rotamer), cyclohexane (chair conformer)

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D4d
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E 2S8 2C4 2S83 C2 4C2′ 4σd 45° twist dimanganese decacarbonyl (staggered rotamer)

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D5d
answer

E 2C5 2C52 5C2 i 3S103 2S10 5σd 36° twist ferrocene (staggered rotamer)

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Td
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E 8C3 3C2 6S4 6σd tetrahedral methane, phosphorus pentoxide, adamantane

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Oh
answer

E 8C3 6C2 6C4 3C2 i 6S4 8S6 3σh 6σd octahedral or cubic cubane, sulfur hexafluoride

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Haloform Reaction
answer

The haloform reaction is a chemical reaction where a haloform (CHX3, where X is a halogen) is produced by the exhaustive halogenation of a methyl ketone (a molecule containing the R-CO-CH3 group) in the presence of a base.[1] R may be H, alkyl or aryl. The reaction can be used to produce CHCl3, CHBr3 or CHI3.
[image]
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amination
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addition/formation of an amine group

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alkylation
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addition of a new carbon fragment via carbon-carbon bond formation

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acylation
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a carbonyl with an R group is added to a molecule

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term symbol
answer

has the form
[image]
where
S is the total spin quantum number. 2S+1 is the spin multiplicity: the maximum number of different possible states of J for a given (L,S) combination.
L is the total orbital quantum number in spectroscopic notation. The symbols for L = 0,1,2,3,4,5 are S,P,D,F,G,H respectively.
J is the total angular momentum quantum number.
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facial stereochemistry
answer

when three ligands share the same face of an octahedron

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positron emission
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Positron emission is a type of beta decay, sometimes referred to as “beta plus” (β+). In beta plus decay, a proton is converted, via the weak force, to a neutron, a positron (also known as the “beta plus particle”, the antimatter counterpart of an electron), and a neutrino.
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red
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625–740 nm

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blue
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440–490 nm
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specific rotation
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determined by observed optical rotation (alpha) divided by the path length (dm) and concentration in (g/mL)

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dieckmann condensation
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intramolecular claisen condensation (makes a beta keto ester from two esters under basic conditions)

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claisen condensation
answer

a carbon-carbon bond forming reaction that occurs between two esters or one ester and another carbonyl compound in the presence of a strong base, resulting in a β-keto

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claisen rearrangement
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powerful carbon-carbon bond-forming chemical reaction discovered by Rainer Ludwig Claisen. The heating of an allyl vinyl ether will initiate a [3,3]-sigmatropic rearrangement to give a γ,δ-unsaturated carbonyl.

[image]

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Halite Structure
answer

“rock-salt”
NaCl, AgCl, AgBr, KBR, LiCl, RbI, Tio, MgO, CaO

-cubic array of anions with cations occupying all of the octahedral holes.

While the halite structure is almost always drawn to illustrate its cubic nature, recall from the previous discussion that the face-centered cubic array can be alternately viewed as a series of ABC-stacked hexagonal layers.

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zincblende
answer

“sphalerite” structure

ZnS, CdS, HgS, CuCl

Cubic array of Zn2+ with S2- in half of the tetrahedral holes

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fluorite
answer

CaF2, BaCl2, PbO2, HgF2 etc.

Cubic array of Ca2+ ions with F- in all the Tetrahedral holes

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anti-fluorite
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switch anion and cation to have a curbic array of anions with cations occupying the tetrahedral holes

K2O, K2S, Li2O, Na2O etc.

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wurzite
answer

ZnS, ZnO, MnS, beO

hexagonal array of Zn2+ with S2- occupying half of the tetrahedral holes

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nickel-arsenide
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NiAs, NiS, CoS, FeS

Hexagonal array of As3- ions with Ni3+ occupying all the octahedral holes

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rutile
answer

TiO2, MnO2, MgF2, SnO2, NiF2

Hexagonal Array of O2- with Ti4+ occupying half of the octahedral holes

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Born-Lande Equation
answer

a means of calculating the lattice energy of a crystalline ionic compound. In 1918[1] Max Born and Alfred Lande proposed that the lattice energy could be derived from the electrostatic potential of the ionic lattice and a repulsive potential energy term.[2]

[image] (Joules/mol)

where

[image] = Avogadros number
[image] = Madelung constant, relating to the geometry of the crystal.
[image] = charge of cation in electron units
[image] = charge of anion in electron units
[image] = electron charge in coulombs, 1.6022 ? 10−19 C

[image] = permittivity of free space

[image] = 1.112 ? 10−10 C?/(J m)
[image] = distance to closest ion in meters
[image] = Born exponent, a number between 5 and 12, determined experimentally by measuring the compressibility of the solid, or derived theoretically.

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Born-Mayer Equation
answer

Takes into account the repulsive components of the ionic solid that the Born Lande may not

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Strong Acids
answer

HCl-hydrochloric acid

HBr-Hydrobromic Acid

HI-Hydroiodic Acid

HNO3-Nitric Acid

H2SO4-Sulfuric Acid

HClO4-Perchloric Acid

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Relate pKa and pKb of a conjugate pair
answer

The sum is equal to 14 at 25 degrees celsius

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Henderson Hasselbalch Equation
answer

[image]

and

[image]

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Schottky Defect
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A vacancy, a point defect in which an atom or ion is missing from its usual site. Doesn’t change overall stoichiometry and is determined by density measurements

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Frenkel Defect
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A point defect in which an atom has been displaced to an intersittial site in the lattice. More common in open structures where the coordination numbers are low

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van der waals equation
answer

image
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First Law of Thermodynamics
answer

The Total Energy of a System and its surroundings is always constant

U=Q-W

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Enthalpy (H)
answer

H = U + PV

for constant pressure (atmospheric conditions)

ΔH = ΔU + PΔV

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Definition of Heat Capacity at constant pressure and constant volume
answer

Cv = (dU/dT)

Cp=(dH/dT)

Cp-Cv = R

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Second Law of Thermodynamics
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The Entropy of the universe tends to increase

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Third Law of Thermodynamics
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The entropy of all perfect crystalline substances is the same at absolute zero

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Gay-Lussac’s Law
answer

the volume of a given mass of gas is directly proportional to its temperature, if the pressure remains constant

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Boyle-Mariotte’s Law
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the volume of a given mass of gas varies inversely with the pressure (constant temperature)

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Gibbs (G) and Helmholtz(A) Energies
answer

Текст ответа
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Текст вопроса
answer

G = H-TS (usually constant pressure)

A = U – TS (usually constant volume

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Gibb’s Phase Rule
answer

F=C-P+2

F = degrees of freedom

C=components

P=phases

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Raoult’s Law
answer

the vapor pressure of an ideal solution is dependent on the vapor pressure of each chemical component and the mole fraction of the component present in the solution.

Once the components in the solution have reached equilibrium, the total vapor pressure p of the solution is:

[image]

and the individual vapor pressure for each component is

[image]

where

p*i is the vapor pressure of the pure component
xi is the mole fraction of the component in solution

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Poiseuille’s Equation
answer

[image]

or

[image]

where:

ΔP is the pressure drop
L is the length of pipe
μ is the dynamic viscosity
Q is the volumetric flow rate
r is the radius
d is the diameter

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First Order Reactions
answer

d[A]/dt = -k [A]

[A] = [A]0 exp(-k t)

ln([A]) = ln([A]0) – k t

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Second Order Reaction Rate
answer

d[A]/dt = -k [A]2 or dx/dt = -k [A][B]

1/[A] – 1/[A]0 = k t  or
(1/(a-b)) [ln((a-x)/(b-x))-ln(a/b)] = k t  

1/[A] = 1/[A]0 + k t

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Zeeman Effect
answer

Splitting of energy levels between which the transition occurs in the presence of a magnetic field

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Stark Effect
answer

 the shifting and splitting of spectral lines of atoms and molecules due to the presence of an external static electric field

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Solubility: Group I elements
answer

Salts containing Group I elements are soluble (Li+, Na+, K+, Cs+, Rb+). Exceptions to this rule are rare. Salts containing the ammonium ion (NH4+) are also soluble.

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Solubility :nitrate ion (NO3-)
answer

Salts containing nitrate ion (NO3-) are generally soluble.

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Solubility: Cl -, Br -, I –
answer

Salts containing Cl -, Br -, I – are generally soluble. Important exceptions to this rule are halide salts of Ag+, Pb2+, and (Hg2)2+. Thus, AgCl, PbBr2, and Hg2Cl2 are all insoluble

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Solubility: Ag
answer

Most silver salts are insoluble. AgNO3 and Ag(C2H3O2) are common soluble salts of silver; virtually anything else is insoluble

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Solubility: Sulfate ions (SO42-)
answer

Most sulfate salts are soluble. Important exceptions to this rule include BaSO4, PbSO4, Ag2SO4 and SrSO4

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Solubility: Hydroxide Ions
answer

hydroxide salts are only slightly soluble. Hydroxide salts of Group I elements are soluble. Hydroxide salts of Group II elements (Ca, Sr, and Ba) are slightly soluble. Hydroxide salts of transition metals and Al3+ are insoluble. Thus, Fe(OH)3, Al(OH)3, Co(OH)2 are not soluble

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Solubility: Sulfides
answer

Most sulfides of transition metals are highly insoluble. Thus, CdS, FeS, ZnS, Ag2S are all insoluble. Arsenic, antimony, bismuth, and lead sulfides are also insoluble

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Solubility: Carbonates (CO32-)
answer

Carbonates are frequently insoluble. Group II carbonates (Ca, Sr, and Ba) are insoluble. Some other insoluble carbonates include FeCO3 and PbCO3.

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Solubility: Chromates (CrO42-)
answer

Chromates are frequently insoluble. Examples: PbCrO4, BaCrO4 

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Solubility: Phosphates
answer

Phosphates are frequently insoluble. Examples: Ca3(PO4)2, Ag3PO4

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Crystallizing conditions
answer

1) minimize Q (solute concentration) by adding slowly

2) maximize S (precipitate solubility) by doing at higher temperature

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Henry’s Law
answer

At a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.

FOR DILUTE SOLUTIONS!!

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Potentiometry vs. Voltammetry
answer

Potentiometry-measure EMF compared to standard zero current. either uses electrodes (like pH meters) to directly measure ion activity, or uses electrodes to find end points of titrations

Voltammetry-electrolysis is carreid out so the analyte is completely oxidized/reduced to a product of known composition. requires application of current through the whole process

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Beer-Lambert Law
answer

[image]

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napthalene
answer

[image]

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anthracene
answer

[image]

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phenanthrene
answer

[image]

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pyrene
answer

[image]

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Maxwell Equations Enthalpy (H)
answer

[image]

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Baeyer Strain
answer

Baeyer strain theory or strain theory explains specific behaviour of chemical compounds in terms of bond angle strain.
It was proposed by Adolf von Baeyer in 1885 to account for the unusual chemical reactivity in ring opening reactions of cyclopropanes and cyclobutanes where this angle strain is relieved.
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Pitzer Strain
answer

Any strain resulting from torsion is also called Pitzer Strain or eclipsing strain

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Mohr Method
answer

The Mohr method uses chromate ions as an indicator in the titration of chloride ions with a
silver nitrate standard solution. After all the chloride has been precipitated as white silver
chloride, the first excess of titrant results in the formation of a silver chromate precipitate,
which signals the end point
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Kjeldahl Method
answer

The Kjeldahl method in analytical chemistry is a method for the quantitative determination of nitrogen in chemical substances developed by Johan Kjeldahl in 1883.

The Kjeldahl method’s universality, precision and reproducibility have made it the internationally-recognized method for estimating the protein content in foods and it is the standard method against which all other methods are judged. It does not, however, give a measure of true protein content, as it measures non-protein nitrogen in addition to the nitrogen in proteins.

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Stephen aldehyde synthesis
answer

[image]

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Mohr Method
answer

Standardizes a silver nitrate solution using potassium chloride as a primary standard

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Liebig Method
answer

titration of Cyanide with silver ion

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Mcbride Method
answer

Standardizing of Potassium Permanganate Solution

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anomers
answer

s a special type of epimer. It is a stereoisomer (diastereomer, more exactly) of a cyclic saccharide that differs only in its configuration at the hemiacetal (or hemiketal) carbon, also called the anomeric carbon

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Malonic Acid
answer

[image]
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Osmotic Pressure
answer

Π = iMRT
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Balmer Series
answer

n’ = 2
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paschen series
answer

n’ = 3

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lyman series
answer

n’ = 1

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NMR shift: Acids
answer

11.5

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NMR Shift: Aldehyde
answer

9.5

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NMR Shift: Alkene
answer

5.5

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NMR Shift: Aromatic
answer

7-8

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NMR Shift: Amide
answer

5.5-8.5

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NMR Shift: Ester RCO2-CH
answer

3.5-4.5

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NMR Shift: Alcohol
answer

0.5-5.5

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NMR Shift: Alkyne
answer

1.5-2.5

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IR Wavenumbers: Alcohol
answer

3300 – 3600 Strong and Broad

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IR Wavenumbers: Carboxylic Acid
answer

2500 – 3000 Very Broad

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IR Wavenumbers:N-H
answer

3200-3500 (sometimes doublet of NH2)

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IR Wavenumbers: Terminal Alkyne (H)
answer

3300

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IR Wavenumbers:Alkene (H)
answer

3000-3100

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IR Wavenumbers: C-H sp3 carbon
answer

2800-3000

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IR Wavenumbers:C triple bond N
answer

2250-2300

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IR Wavenumbers:Alkyne (CC)
answer

2100
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IR Wavenumbers:C=O
answer

1680-1820

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IR Wavenumbers:C=C
answer

1600

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IR Wavenumbers:C-O
answer

1050-1150

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HF Solvent Acids
answer

No protic acids in HF solvent

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Nitriles -> COOH
answer

Can occur in acid and base, but not oxidizing conditions

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Cope Rearrangement
answer

The Cope rearrangement is an extensively studied organic reaction involving the [3,3]-sigmatropic rearrangement of 1,5-dienes. It was developed byArthur C. Cope. For example 3-methyl-1,5-hexadiene heated to 300°C yields 1,5-heptadiene.

[image]

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McLafferty Rearrangement
answer

The McLafferty rearrangement is a reaction observed in mass spectrometry. It is sometimes found that a molecule containing a keto-group undergoes β-cleavage, with the gain of the γ-hydrogen atom. This rearrangement may take place by a radical or ionic mechanism

[image]

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Hoffman Rearrangement (degradation)
answer

The Hofmann rearrangement is the organic reaction of a primary amide to a primary amine with one fewer carbon atom

[image]

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Hofmann Elimination
answer

Hofmann elimination (also known as exhaustive methylation) is a process where an amine is reacted to create a tertiary amine and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat [image]
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Tollen’s Reagent
answer

Test for aldehydes

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Rankine Scale
answer

Temperature 

T(Rankine) = T(F) + 460

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Van Deemter Equation
answer

The Van Deemter equation in chromatography relates the variance per unit length of a separation column to the linear mobile phase velocity by considering physical, kinetic, and thermodynamic properties of a separation.[1] These properties include pathways within the column, diffusion (axial and longitudinal), and mass transfer kinetics between stationary and mobile phases.

[image]

Where

A = Eddy-diffusion
B = Longitudinal diffusion
C = mass transfer kinetics of the analyte between mobile and stationary phase
u = Linear Velocity.

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Linkage isomerism
answer

he existence of co-ordination compounds that have the same composition differing with the connectivity of the metal to a ligand.
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Selection Rules
answer

Electronic: can’t do s-s p-p d-d etc. 

Rotational-must differ by +-1

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Pure Rotational Absorption Spectrum
answer

Need a net dipole moment

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enamine
answer

an unsaturated compound derived by the reaction of an aldehyde or ketone with a secondary amine followed by loss of H2O

[image]

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imine
answer

is a functional group or chemical compound containing a carbon–nitrogen double bond [1]. Due to their diverse reactivity, imines are common substrates in a wide variety of transformations. An imine can be synthesised by the nucleophilic addition of an amine to a ketone or aldehyde giving a hemiaminal -C(OH)(NHR)- followed by an elimination of water to yield the imine

[image]

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Raman Spectroscopy
answer

Rotational and Vibrational

For the spontaneous Raman effect, the molecule will be excited from the ground state to a virtual energy state, and relax into a vibrational excited state. Two series of lines exist around this central vibrational transition. They correspond to the complimentary rotational transition. Anti-Stokes lines correspond to rotational relaxation whereas Stokes lines correspond to rotational excitation.

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upfield
answer

higher number, more deshielded
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