Chem Lab 3: Synthesis of K2[Cu(C2O4)2(H2O)2] – Flashcards
Unlock all answers in this set
Unlock answersquestion
synthesize
answer
to make
question
potassiumdiaquadioxalatocuprate(II)
answer
K2[Cu(C2O4)2(H2O)2]
question
metal complexes
answer
a type of molecule that consists of a central metal atom covalently bonded to ions or molecules, called ligands; also called "coordination compounds" or "coordination complexes"; common in biological systems
question
coordinate covalent bond
answer
the bond between a metal and a ligand; the ligand donates both electrons to the bond
question
heme group
answer
iron-containing component of hemoglobin, which transports oxygen in the blood
question
What is the central atom of the diaquadioxalatocuprate(II) ion?
answer
copper
question
The copper atom is bonded to what?
answer
2 waters (H2O) and 2 oxalate groups (C2O4 2-) - the water and oxalate groups are the ligands
question
What donates the electrons to the covalent bond?
answer
an oxygen on each group
question
monodentate ligands
answer
ligands that bond to the metal through only one atom; like water
question
bidentate ligands
answer
ligands that bond to metal through 2 atoms; oxalate
question
How many ligands in the diaquadioxalatocuprate(II) ion?
answer
4 - (two H2O + two C2O4 2-)
question
How many bonding regions in the diaquadioxalatocuprate(II) ion?
answer
6 - since the oxalate binds in two places
question
octahedral geometry
answer
the diaquadioxalatocuprate(II) ion, because there are four ligands and six bonding regions
question
stoichiometry of the reaction
answer
a balanced chemical equation indicates the relative amounts of reactants required and the relative amounts of products that will be produced
question
an excess of one reactant is added to be sure that the other reactant, the ____ ___, is completely consumed
answer
limiting reactant
question
limiting reactant
answer
controls (limits) the extent of the reaction because when it has been consumed, the reaction can no longer occur; determines how much product can be produced
question
chemical reaction for the synthesis of potassium diaquadioxalatocuprate(II)
answer
CuSO4 5H2O(aq) + 2K2C2O4H2O (aq) --> K2[Cu(C2O4)2(H2O)2](s) + K2SO4(aq) + 5H2O(l)
question
What is heated before mixing?
answer
solutions of copper (II) sulfate pentahydrate and potassium oxalate monohydrate
question
Why is it heated before mixing?
answer
the solubility of a substance increases with heat; this ensures that the salts are entirely dissolved and able to dissociate
question
Why to we allow the solution to slowly cool after mixing?
answer
this allows the product to very slowly precipitate, because the solubility of the solids decreases as you cool the substance, and form a crystalline structure that reduces impurities
question
Why do we place the product in an ice bath?
answer
to cool it further and to maximize the yield (amount of product we get)
question
theoretical yield
answer
the maximum amount of product that can be produced
question
How can the limiting reactant be determined?
answer
by calculating the theoretical yield of the reaction given the amount of each reactant used; the reactant that gives the lowest theoretical yield is the limiting reactant
question
How do you calculate the theoretical yield?
answer
calculate the number of moles of your product that would be produced if all the reagent in question were converted to the product --> use the molar mass of the reactant to convert grams of reactant to moles of reactant, and then use the stoichiometry of the balanced chemical reaction to convert moles of reactant to moles of product, and finally use the molar mass of the product to determine the mass of the product that would be theoretically produced
question
percent yield
answer
(experimental yield / theoretical yield) x 100%
question
experimental yield
answer
the amount of product actually produced, which you find by massing your product; should always be less than the theoretical yield
question
Why should the experimental yield be less than the theoretical yield?
answer
(1) issues with the the experimental design that can make it difficult to transfer all your crystals (2) production of side products (3) small amounts of of material typically remain in the solution and do not precipitate out
question
side products
answer
in this case, and copper-containing products other than the product